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# if x is an integer, is x even? 1) x^2-y^2=0 2) x^2+y^2=18

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VP
Joined: 25 Nov 2004
Posts: 1481

Kudos [?]: 130 [0], given: 0

if x is an integer, is x even? 1) x^2-y^2=0 2) x^2+y^2=18 [#permalink]

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26 Feb 2005, 23:41
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if x is an integer, is x even?
1) x^2-y^2=0
2) x^2+y^2=18

Kudos [?]: 130 [0], given: 0

Director
Joined: 07 Jun 2004
Posts: 610

Kudos [?]: 948 [0], given: 22

Location: PA

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27 Feb 2005, 05:19
from 1 x = y or x <> Y

from 2 x can be 4 or 3 and y can be any ting as its not an integer

from 1 and 2 x has to be 3 or -3 so its C

Kudos [?]: 948 [0], given: 22

Current Student
Joined: 28 Dec 2004
Posts: 3345

Kudos [?]: 322 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12

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28 Feb 2005, 10:46
c it is...

statement 1

X^2-y^2=0, pick 0 (which is even) and 3 which is odd.

we dont know what Y is... so insuff

statement 2

X^2+y^2=18,

x can be 3 or 0 if y is 3 or some value like 4.4 <--we dont know if y is integer or not.

taking together we now know that x=y therfore 3 is the only possible soution.

C it is

Kudos [?]: 322 [0], given: 2

SVP
Joined: 03 Jan 2005
Posts: 2228

Kudos [?]: 385 [0], given: 0

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28 Feb 2005, 11:52
It the stem is changed to "X and Y are integers", will your answer change?

Kudos [?]: 385 [0], given: 0

Manager
Joined: 15 Feb 2005
Posts: 245

Kudos [?]: 8 [0], given: 0

Location: Rockville

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28 Feb 2005, 12:56
Why does it become B
how is that enough to ditermine if X is an even integer or not?

Kudos [?]: 8 [0], given: 0

VP
Joined: 18 Nov 2004
Posts: 1430

Kudos [?]: 49 [0], given: 0

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28 Feb 2005, 13:02
Rupstar wrote:
Why does it become B
how is that enough to ditermine if X is an even integer or not?

If both r ints...then state I satisfies when X = 1 and Y = 1 and X = 2 and Y = 2....insuff.....as Xcan be even or odd

In state 2.....if X = 0,1,2,4...Y can't be an integer and vice versa, also either of X or Y can't be >= 5.....so only for X = Y = #3 satisfies....so X is always odd...so ANS is NO.....suff

Kudos [?]: 49 [0], given: 0

28 Feb 2005, 13:02
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