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# If x is equal to the sum of even integers from 40 to 60,

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If x is equal to the sum of even integers from 40 to 60, [#permalink]

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03 Aug 2007, 19:46
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x is equal to the sum of even integers from 40 to 60, inclusive, and y is the number of even integers from 40 to 60, inclusive, what is the value of x + y?

550
551
560
561
572
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03 Aug 2007, 21:58
abhi_ferrari wrote:
If x is equal to the sum of even integers from 40 to 60, inclusive, and y is the number of even integers from 40 to 60, inclusive, what is the value of x + y?

550
551
560
561
572

This should be D (561).

Sum of even integers from 40 - 60 = (11/2)*[2*40 + (11-1)*2] = 11*(40+10) = 50*11 = 550 = x

No. of even integers from 40-60 = 11 = y

So, x+y = 550+11 = 561
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03 Aug 2007, 22:00
abhi_ferrari wrote:
If x is equal to the sum of even integers from 40 to 60, inclusive, and y is the number of even integers from 40 to 60, inclusive, what is the value of x + y?

550
551
560
561
572

D

40, 2, 4, 6, 8, 50, 2, 4, 6, 8, 60 = 11 = y

a) sum of integers = avg(# of integers)
{40, 42, 44, 46, 48 }
the avg in any set of evenly space numbers is the middle #. that said,
the avg. in the above set is 44. there are 5 numbers in this set to. the sum of the set is 44(5) = 220.

b) repeat above for 50 - 58. this sums to 270 = (54*5)

c) 220 + 270 + 60 + 11 = 561
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04 Aug 2007, 00:35
x = sum of even integers from 40 to 60:

x = 11/2(2(40) + (10)(2)) = 550
y = 11

so x + y = 561
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04 Aug 2007, 07:25
Thanks, OA is D. I was making a very silly mistake
04 Aug 2007, 07:25
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