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# If x is negative, is x < -3 ?

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If x is negative, is x < -3 ? [#permalink]

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02 Jan 2011, 08:47
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If x is negative, is x < –3 ?

(1) x^2 > 9
(2) x^3 < –9
[Reveal] Spoiler: OA

Last edited by Engr2012 on 12 Sep 2015, 09:44, edited 2 times in total.
Renamed the topic and edited the question.

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Re: If x is negative, is x < -3 ? [#permalink]

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02 Jan 2011, 08:57
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If x is negative, is x < –3 ?

(1) x^2 > 9 --> $$x<-3$$ or $$x>3$$ as given that $$x<0$$ then we have that $$x<-3$$. Sufficient.

(2) x^3 < –9 --> if $$x=-3$$ ($$x^3=-27<-9$$) then the answer will be NO (as $$x$$ equals to -3 and is not less than -3) but if $$x=-4$$ ($$x^3=-64<-9$$) then the answer will be YES. Not sufficient.

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Re: If x is negative, is x < -3 ? [#permalink]

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24 Feb 2011, 05:11
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1.
$$x^2>9$$
$$|x|>3$$
$$x>3 \hspace{3} or \hspace{3} x<-3$$
We know that x is -ve.
Thus;
$$x<-3$$
Sufficient.

2.
$$x^3<-9$$
$$x^3$$ can be -27 making x=-3 or $$x^3$$ can be -64 making x=-4[/m]
We can't conclude that x is definitely smaller than -3.
Not Sufficient.

Ans:"A"
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Re: If x is negative, is x < -3 ? [#permalink]

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09 Mar 2013, 11:41
I'm not seeing something in testing out statement 2.

Would someone be able to illustrate on a number line when testing out x=-3 and x=-4 only -64 <-3 and not -27?

And if you have a similar problem, please post.
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Re: If x is negative, is x < -3 ? [#permalink]

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10 Mar 2013, 06:07
DelSingh wrote:
I'm not seeing something in testing out statement 2.

Would someone be able to illustrate on a number line when testing out x=-3 and x=-4 only -64 <-3 and not -27?

And if you have a similar problem, please post.

Not sure I understand what you mean there. Can you please elaborate? Thank you.

Anyway both -64 and -27 are less than -3, since both are negative and further from 0 than -3 is.
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Re: If x is negative, is x < -3 ? [#permalink]

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10 Mar 2013, 16:02
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they are asking is x<-3, not if x^3<-3. -27 and -64 are the values of x^3. so x=-3 and x=-4. negative 3 isn't less than negative 3, so answer is no. negative 4 is less than negative 3, so answer is yes. insufficient.

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Re: If x is negative, is x < -3 ? [#permalink]

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10 Mar 2013, 22:49
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DelSingh wrote:
Bunuel wrote:
DelSingh wrote:
I'm not seeing something in testing out statement 2.

Would someone be able to illustrate on a number line when testing out x=-3 and x=-4 only -64 <-3 and not -27?

And if you have a similar problem, please post.

Not sure I understand what you mean there. Can you please elaborate? Thank you.

Anyway both -64 and -27 are less than -3, since both are negative and further from 0 than -3 is.

Hopefully this will show what I am doing wrong in statement two:

I had sufficient for statement 2 but that was wrong

x = -3 and x = -4 satisfy the second statement: (-3)^3 < -9 and (-4)^3 < -9.

Now, if x = -4 we have an YES answer because -4 < -3;
But if x = -3 we have a NO answer because -3 = -3 (x equals to -3 and is not less than -3).

Hope it's clear.
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Re: If x is negative, is x < -3 ? [#permalink]

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20 Jun 2013, 14:37
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Statement 2 : X^3<-9
=> We know (-2)^3 = -8 and (-3)^3= -27
=> it isnt given in the q that x has to be an integer
=> x can be any decimal slightly less than -2.0 ie. -2.5^3 (-15) and thus give an answer NO
& x can be any number <-3 (=>x^3 <-27)and give an answer YES.
Thus, insufficient

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Re: If x is negative, is x < -3 ? [#permalink]

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Re: If x is negative, is x < -3 ? [#permalink]

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29 Aug 2015, 01:55
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If x is negative, is x < -3 ? [#permalink]

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02 Dec 2015, 23:31
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St1) Quite obviously SUFF
St2) x^3<-9. First of all x has to be negative as cube root of a negative number will be negative. Now lets take cube root of both sides:
x<- (~2.1) ...[we know than cube root of -8 is -2, so cube root of of -9 will be just slightly smaller than -2]
So our ballpark estimate is that x lies to the left of -2.1 we don't know if it will lie to the left of -3. INSUF

Alternatively-

Stem: If x is negative, is x < -3 ?
In other words,
i) is x^2>9? (Inequality sign will flip)
ii) is x^3<-27? (Ineqality sign doesnt change)
ii) is x^4> 81? (Inequality sign will flip)
etc
etc
.
.
.
st1) Straight away yes from i)...SUF
St2) only tells us x^3 is less than -9 so x^3 could be less than -27 or not. INSUF

Ans: A
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Re: If x is negative, is x < -3 ? [#permalink]

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10 Jan 2017, 08:27
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Re: If x is negative, is x < -3 ? [#permalink]

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20 Jan 2017, 05:25
(1) says that x^2 > 9

I thought that this would mean that x > 3 or x < -3 and hence, (1) is insufficient.

However, I missed out that question itself says that x < 0. So, this rules out x > 3. Hence, (1) itself says that x < -3.

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Re: If x is negative, is x < -3 ? [#permalink]

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17 Jun 2017, 05:22
Hi guys...this is how i solved the question... plz correct me,wher i am wrong...
For statement 1:
x^2>9,
x^2-9>0 ,
(x+3)(x-3)>0 ,
{x>-3 & x>3} or {x<-3 & x<3}
Now considering only negative values i get x>-3 or x<-3..
Since answer is not consistent A is not sufficient...

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Re: If x is negative, is x < -3 ? [#permalink]

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17 Jun 2017, 05:32
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JJSHHShank wrote:
Hi guys...this is how i solved the question... plz correct me,wher i am wrong...
For statement 1:
x^2>9,
x^2-9>0 ,
(x+3)(x-3)>0 ,
{x>-3 & x>3} or {x<-3 & x<3}
Now considering only negative values i get x>-3 or x<-3..
Since answer is not consistent A is not sufficient...

This is not correct.

x^2 > 9

|x| > 3 (by taking the square root from both sides, notice that we can safely do that because both sides are non-negative);

x < -3 or x > 3.

You should brush up fundamentals on inequalities:

Solving Quadratic Inequalities - Graphic Approach
Inequality tips
Wavy Line Method Application - Complex Algebraic Inequalities

DS Inequalities Problems
PS Inequalities Problems

700+ Inequalities problems

http://gmatclub.com/forum/inequalities-trick-91482.html
http://gmatclub.com/forum/data-suff-ine ... 09078.html
http://gmatclub.com/forum/range-for-var ... 09468.html
http://gmatclub.com/forum/everything-is ... 08884.html
http://gmatclub.com/forum/graphic-appro ... 68037.html

Hope this helps.
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Re: If x is negative, is x < -3 ? [#permalink]

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17 Jun 2017, 05:33
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JJSHHShank wrote:
Hi guys...this is how i solved the question... plz correct me,wher i am wrong...
For statement 1:
x^2>9,
x^2-9>0 ,
(x+3)(x-3)>0 ,
{x>-3 & x>3} or {x<-3 & x<3}
Now considering only negative values i get x>-3 or x<-3..
Since answer is not consistent A is not sufficient...

Hey Mate,

If x^2 > 9
x > 3 or x < -3

With what you're saying is x > -3 then x = -2 for example and x^2 = 4 which is not in line with the equation, and this is also incorrect.

In terms of solving an inequality equation,

If x^2 > 9 then x > 3 or x < -3
If x^2 < 9 then -3<x<3

Try to input value of x in the range, and it'll always be true.

Hope this helps.
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Re: If x is negative, is x < -3 ? [#permalink]

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18 Jun 2017, 04:38
Thanks Bunuel and akshayk for the quick response...
The links given were bible for inequalities...Thanks a lot.
Understood that we cannot just solve taking a pen and a scratch pad... we need to think too-at every step, especially when dealing with inequalities...

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Re: If x is negative, is x < -3 ? [#permalink]

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11 Sep 2017, 19:10
Bunnel,

Can you please explain why we should consider statement 1 as sufficient? I eliminated it thinking there two different values and not 1 value.

What am I missing here!

Shinrai

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Re: If x is negative, is x < -3 ? [#permalink]

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11 Sep 2017, 20:50
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shinrai15 wrote:
Bunnel,

Can you please explain why we should consider statement 1 as sufficient? I eliminated it thinking there two different values and not 1 value.

What am I missing here!

Shinrai

If x is negative, is x < –3 ?

(1) x^2 > 9 --> $$x<-3$$ or $$x>3$$ as given that $$x<0$$ then we have that $$x<-3$$. Sufficient.

Please tell if anything is unclear above.
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If x is negative, is x < -3 ? [#permalink]

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24 Sep 2017, 07:51
There are no doubts about 1 as it is obviously sufficient . I want to discuss more about 2.
2. Is x<-3
if x=-3 then x^3=-27, -27<-9 which is very true . This is the very point where the option 2 fails. Is X<-3 ? No because 2 becomes true at x=-3 as-27<-9, so x cannot be <-3.If the question was is x<= -3 then it would have been sufficient.
Ans - A
Hope this helps
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If x is negative, is x < -3 ?   [#permalink] 24 Sep 2017, 07:51
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