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If x is not equal to -y is (x-y)/(x+y) >1 1 x>0 2

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If x is not equal to -y is (x-y)/(x+y) >1 1 x>0 2 [#permalink]

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03 Aug 2008, 17:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If x is not equal to -y
is (x-y)/(x+y) >1

1 x>0
2 y<0
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Joined: 23 May 2006
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03 Aug 2008, 18:13
arjtryarjtry wrote:
If x is not equal to -y
is (x-y)/(x+y) >1

1 x>0
2 y<0

S1. X is positive; however you do not know what y is so you can get something > 1 or less than 1;
say x = 1 and y = 0 then = 1/1 = 1 No
say x = 5 and y = -3 then = 4 Yes

S2. Y is negative;
say x = 3 and y = -5 then = 3 + 5/-2 = -4 NO
say x = 5 and y = -3 then = 8/3 = 4 Yes
Hence Maybe case B is out

Combine:

Even then depending on the magnitude of Y and X you could get a yes or no scenario

IMO E
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03 Aug 2008, 18:24
when both are combined, what is the no scenario?
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03 Aug 2008, 18:57
arjtryarjtry wrote:
If x is not equal to -y
is (x-y)/(x+y) >1

1 x>0
2 y<0

-ve values can change any inequality
hence the behaviour needs to be studied in detail

given : x not eq -y
consider (1) x>0 when y <0 and y>0 (x-y)/(x+y) value changes
say , x=4,y=-1 (x-y)/(x+y) >1
x=2,y=-3 (x-y)/(x+y) <1 INSUFFI

(2) y<0
x=4,y=-1 (x-y)/(x+y) >1
x=2,y=-3 (x-y)/(x+y) <1 INSUFFI

consider (1) and (2) :
x=4,y=-1 (x-y)/(x+y) >1
x=2,y=-3 (x-y)/(x+y) <1 INSUFFI

IMO E
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Its Now Or Never

Re: x/y   [#permalink] 03 Aug 2008, 18:57
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