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# If X is the set of prime single-digit numbers and Y is a set containin

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Math Expert
Joined: 02 Sep 2009
Posts: 60627
If X is the set of prime single-digit numbers and Y is a set containin  [#permalink]

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28 Oct 2016, 01:00
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Difficulty:

15% (low)

Question Stats:

80% (01:16) correct 20% (01:44) wrong based on 45 sessions

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If X is the set of prime single-digit numbers and Y is a set containing each of the numbers in set X raised to the power of 2, how much greater is the median of set Y than the median of set X?

A. 2
B. 4
C. 9
D. 13
E. 17

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Re: If X is the set of prime single-digit numbers and Y is a set containin  [#permalink]

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28 Oct 2016, 01:08
Bunuel wrote:
If X is the set of prime single-digit numbers and Y is a set containing each of the numbers in set X raised to the power of 2, how much greater is the median of set Y than the median of set X?

A. 2
B. 4
C. 9
D. 13
E. 17

IMO D
set X={2,3,5,7} set of prime single digit numbers
set Y={4,9.25.49} each of the numbers in set X raised to the power of 2
Median set X= (3+5)/2= 4
Median set Y= (9+25)/2= 17
Required set Y - set X= 13
Hence D
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Re: If X is the set of prime single-digit numbers and Y is a set containin  [#permalink]

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27 Nov 2019, 12:13
Bunuel wrote:
If X is the set of prime single-digit numbers and Y is a set containing each of the numbers in set X raised to the power of 2, how much greater is the median of set Y than the median of set X?

A. 2
B. 4
C. 9
D. 13
E. 17

We see that X = {2, 3, 5, 7} and Y = {4, 9, 25 49}. Therefore, the median of set X is (3 + 5)/2 = 4, and that of set Y is (9 + 25)/2 = 17. So the median of set Y is 17 - 4 = 13 greater than the median of set X.

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Re: If X is the set of prime single-digit numbers and Y is a set containin   [#permalink] 27 Nov 2019, 12:13
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