ShaunakSawant wrote:
can someone tell me how which values i can pick for option C to eliminate it
Bunuel KarishmaBHello
ShaunakSawant,
Let me begin by telling you that this approach of plugging in values is not scalable (would take a lot of time to check each choice) and something that I would not recommend. Had you adopted the methodical approach of solving the question, you would have known exactly what value would eliminate choice C.
That said, I will address your request right now. 😊
You wished for a value to help us eliminate option C:
x > 1. If we find a case where the original condition,
|x| < x\(^2\) is true but condition
x > 1 is not true, then we will be done - that is, we will be able to reject choice C as need not be true.
Now, since we want
x > 1 to not be true, our x must be anywhere in the range
x <= 1. And remember that it must satisfy the condition given in the question:
|x| < x\(^2\).
To find such numbers, let’s just take numbers from the range
x <= 1 and plug them into the given inequality:
|x| < x\(^2\)to see which ones work. (Again, the ones that do work will help us reject choice C.)
- x = 1
|x| = 1 and x\(^2\) = 1
|x| < x\(^2\) – NOT TRUE - x = 0
|x| = 0 and x\(^2\) = 0
|x| < x\(^2\) – NOT TRUE - x = -1
|x| = 1 and x\(^2\) = 1
|x| < x\(^2\) – NOT TRUE - x = -2
|x| = 2 and x\(^2\) = 4
|x| < x\(^2\) – TRUE
So, we have found a value in the range x <= 1 that satisfies the original condition! Hence, choice C can be rejected.
Note: I would again suggest that you build methodical approaches to solve questions. This will enable you to tackle the hardest of questions with ease.
You can check the solution given by
BrushMyQuant just above your query.
Hope this helps!
Best Regards,
Ashish Arora
Quant Expert,
e-GMAT _________________