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# If x/y =2/3, then (x-y)/x?

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If x/y =2/3, then (x-y)/x? [#permalink]

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21 Oct 2005, 01:42
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If x/y =2/3, then (x-y)/x?

A. -1/2
B. -1/3
C. 1/3
D. 1/2
E. 5/2
[Reveal] Spoiler: OA
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Re: PS -Toughnut from OG [#permalink]

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21 Oct 2005, 01:54
njss750 wrote:
x/y =2/3, then (x-y)/x?
-1/2, -1/3, 1/3, 1/2, 5/2

Since this was in the last few probs of OG, thot that x/y could also be interpreted as x=-2 and y=-3 and therefore x/y can be equal to 2/3. OG proved me wrong, but is this a theoretical possibility?

we have this law of fraction:
a/b=c/d= (a-c)/(b-d)

x/y=2/3 ---> x/2=y/3= (x-y)/(2-3)=(x-y)/(-1) ---> (x-y)/x= -1/2
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21 Oct 2005, 01:55
hik, i thought too complicatedly ....you're right, ywilfred!
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Re: PS -Toughnut from OG [#permalink]

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17 Sep 2013, 19:02
laxieqv wrote:
njss750 wrote:
x/y =2/3, then (x-y)/x?
-1/2, -1/3, 1/3, 1/2, 5/2

Since this was in the last few probs of OG, thot that x/y could also be interpreted as x=-2 and y=-3 and therefore x/y can be equal to 2/3. OG proved me wrong, but is this a theoretical possibility?

we have this law of fraction:
a/b=c/d= (a-c)/(b-d)

x/y=2/3 ---> x/2=y/3= (x-y)/(2-3)=(x-y)/(-1) ---> (x-y)/x= -1/2

will you please explain this rule i couldn't find it anywhere on the internet? also i am not familiar with it either

i have solved it like this:x/y=2/3
x-y/x=x/x-y/x
1-2/3=3-2/3
so the answer is 1/3............. am i right?? :s
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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17 Sep 2013, 19:17
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njss750 wrote:
If x/y =2/3, then (x-y)/x?

A. -1/2
B. -1/3
C. 1/3
D. 1/2
E. 5/2

x/y=2/3 --> y/x=3/2.

$$\frac{x-y}{x}=1-\frac{y}{x}=1-\frac{3}{2}=-\frac{1}{2}$$.

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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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17 Sep 2013, 19:24
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x/y=2/3, then y/x=3/2.
(x-y)/x = x/x-y/x = 1-3/2 = -1/2
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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18 Sep 2013, 10:52
i got it!!! thanks guys!!!!
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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19 Sep 2013, 03:49
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I solved it like this...

x/y = 2/3
so x = 2 and y = 3
substitute and get the answer -1/2
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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21 Nov 2013, 19:59
I'm still confused. Where does the 1 come from?
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Re: If x/y =2/3, then (x-y)/x? [#permalink]

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21 Nov 2013, 21:32
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sdlucas wrote:
I'm still confused. Where does the 1 come from?

You separate out the numerator.

$$\frac{(x-y)}{x} = \frac{x}{x} - \frac{y}{x} = 1 - \frac{y}{x} = 1 - \frac{3}{2} = -\frac{1}{2}$$
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Get started with Veritas Prep GMAT On Demand for $199 Veritas Prep Reviews Intern Joined: 25 Jan 2016 Posts: 19 Location: United States (OH) GPA: 3.7 Followers: 0 Kudos [?]: 6 [0], given: 3 Re: If x/y =2/3, then (x-y)/x? [#permalink] ### Show Tags 19 Apr 2016, 16:12 did i get lucky? or can this be a correct approach. I cross multiplied to get 3x=2y. I then divided by 3 to get 2/3y and just plugged that into where ever x was Veritas Prep GMAT Instructor Joined: 16 Oct 2010 Posts: 7241 Location: Pune, India Followers: 2200 Kudos [?]: 14302 [0], given: 222 Re: If x/y =2/3, then (x-y)/x? [#permalink] ### Show Tags 19 Apr 2016, 22:12 ross14 wrote: did i get lucky? or can this be a correct approach. I cross multiplied to get 3x=2y. I then divided by 3 to get 2/3y and just plugged that into where ever x was Yes, the approach is fine. You are eliminating one variable, bringing it all in terms of a single variable and then cancelling it off to get a value. _________________ Karishma Veritas Prep | GMAT Instructor My Blog Get started with Veritas Prep GMAT On Demand for$199

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Re: If x/y =2/3, then (x-y)/x?   [#permalink] 19 Apr 2016, 22:12
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