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If x > y^2 > z^4, which of the following statements could be
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05 Sep 2010, 13:17
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If \(x > y^2 > z^4\), which of the following statements could be true? I. \(x>y>z\) II. \(z>y>x\) III. \(x>z>y\) A. I only B. I and II only C. 1 and III only D. II and III only E. I, II and III
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Re: If x > y^2 > z^4, which of the following statements could be
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05 Sep 2010, 14:06
Orange08 wrote: If x > y^2 > z^4, which of the following statements could be true?
I. x>y>z II. z>y>x III. x>z>y
A. I only B. I and II only C. I and III only D. II and III only E. I, II and II As this is a COULD be true question then even one set of numbers proving that statement holds true is enough to say that this statement should be part of correct answer choice. Given: \(x > y^2 > z^4\). 1. \(x>y>z\) > the easiest one: if \(x=100\), \(y=2\) and \(z=1\) > this set satisfies \(x > y^2 > z^4\) as well as given statement \(x>y>z\). So 1 COULD be true. 2. \(z>y>x\) > we have reverse order than in stem (\(x > y^2 > z^4\)), so let's try fractions: if \(x=\frac{1}{5}\), \(y=\frac{1}{4}\) and \(z=\frac{1}{3}\) then again the stem and this statement hold true. So 2 also COULD be true. 3. \(x>z>y\) > let's make \(x\) some big number, let's say 1,000. Next, let's try the fractions for \(z\) and \(y\) for the same reason as above (reverse order of \(y\) and \(z\)): \(y=\frac{1}{3}\) and \(z=\frac{1}{2}\). The stem and this statement hold true for this set of numbers. So 3 also COULD be true. Answer: E.
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Re: If x > y^2 > z^4, which of the following statements could be
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28 Jun 2011, 13:17
Baten80 wrote: If x > y^2 >z^4, which of the following statements could be true?
I. x > y > z
x=10000 y=10; y^2=100 z=1; z^4=1 x>y^2>z^4
II. z > y > x z=0.5; z^4=0.0625 y=0.4; y^2=0.16 x=0.3 x>y^2>z^4
III. x > z > y x=0.5 z=0.2; z^4=0.0016 y=0.1; y^2=0.01 x>y^2>z^4
a. I only b. I and II only c. I and III only d. II and III only e. I, II and III We just need to remember that 1. the number decreases in value with increment in the power of the number if 0< number< 1; if x=0.1; x>x^2>x^3>x^(100) because x is between 0 and 1. 2. the number increases in value with increment in the power of the number if number>1 if x=2; x<x^2<x^(100) because x is more than 1. Ans: "E"
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Re: If x > y^2 > z^4, which of the following statements could be
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Updated on: 17 Sep 2018, 00:51
This is a really tough problem. Here is my video explanation: https://gmatquantum.com/gmatprepalgebr ... tatements/Dabral
Originally posted by dabral on 28 Jun 2011, 12:19.
Last edited by dabral on 17 Sep 2018, 00:51, edited 1 time in total.



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Re: If x > y^2 > z^4, which of the following statements could be
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23 Jan 2012, 01:52
arps wrote: 1) x > y2 > z4
which of the following is true:
I x>y>z II z>y>x III x>z>y
A) I Only B) I and II Only C) I and III Only D) II and III Only E) I, II and III I think the actual question is: Which of the following could be true? Plugging in numbers work best for such questions. The only thing to keep in mind is that you should plug in the right numbers. How do you know the right numbers? When I see \(x > y^2 > z^4\), I think that \(y^2\) and \(z^4\) are non negative. Since \(y^2 > z^4\), \(y^2\) cannot be 0. Only z can be 0. x has to be positive. Also, I have to take into account two ranges: 0 to 1 and 1 to infinity. The powers behave differently in these two ranges. I will consider negative numbers only if I have to since with powers, they get confusing to deal with. The question says: "Which of the following could be true?" We have to find examples where each relation holds. I. x > y > z This is the most intuitive of course. z = 0, y = 1 and x = 2 \(2 > 1^2 > 0^4\) II. z > y > x Let me consider the 0 to 1 range here. Say z = 1/2, y = 1/3 and x = 1/4 \(1/4 > 1/9 > 1/16\) III. x > z > y Let's stick to 0 to 1 range. z > y as in case II above but x has to be greater than both of them. Say z = 1/2, y = 1/3 and x = 1 \(1>1/9 > 1/16\) So all three statements could be true.
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Re: If x > y^2 > z^4, which of the following statements could be
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28 Feb 2012, 02:31
Hi Bunuel/Karishma, Thanks for the earlier response.. I think, I am very weak in Inequalities.. Could you please post how to go about this question in algebraic way.. ...also if you could let me know how do you make sure about the "Range of the values", that will also work.. Thanks H



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Re: If x > y^2 > z^4, which of the following statements could be
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28 Feb 2012, 02:46
imhimanshu wrote: Hi Bunuel/Karishma, Thanks for the earlier response.. I think, I am very weak in Inequalities.. Could you please post how to go about this question in algebraic way.. ...also if you could let me know how do you make sure about the "Range of the values", that will also work.. Thanks H Plugin method is really the best way to handle such kind of questions. No need to look for some kind of textbook or algebraic ways. Notice that there are are certain GMAT questions which are pretty much only solvable with plugin or trial and error methods (well at leas in 23 minutes). Many difficult inequality problems will often require some sort of plugins, as part of your technique or else you'll spend too much time solving them with algebra. Which means that you MUST make plugin methods part of your arsenal if you want to get a decent score. Inequality questions to practice. DS: search.php?search_id=tag&tag_id=184PS: search.php?search_id=tag&tag_id=189Hope it helps. P.S. I'm not sure understood the following part of your post: "how do you make sure about the "Range of the values", that will also work.. "
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Re: If x > y^2 > z^4, which of the following statements could be
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28 Feb 2012, 04:01
Thanks Bunuel for your response.. This is what I mean when I said range  Red Part in Karishma's response" VeritasPrepKarishma wrote: arps wrote: 1) x > y2 > z4
which of the following is true:
I x>y>z II z>y>x III x>z>y
A) I Only B) I and II Only C) I and III Only D) II and III Only E) I, II and III I think the actual question is: Which of the following could be true? Plugging in numbers work best for such questions. The only thing to keep in mind is that you should plug in the right numbers. How do you know the right numbers? When I see \(x > y^2 > z^4\), I think that \(y^2\) and \(z^4\) are non negative. Since \(y^2 > z^4\), \(y^2\) cannot be 0. Only z can be 0. x has to be positive. Also, I have to take into account two ranges: 0 to 1 and 1 to infinity. The powers behave differently in these two ranges. I will consider negative numbers only if I have to since with powers, they get confusing to deal with. The question says: "Which of the following could be true?" We have to find examples where each relation holds. I. x > y > z This is the most intuitive of course. z = 0, y = 1 and x = 2 \(2 > 1^2 > 0^4\) II. z > y > x Let me consider the 0 to 1 range here. Say z = 1/2, y = 1/3 and x = 1/4 \(1/4 > 1/9 > 1/16\) III. x > z > y Let's stick to 0 to 1 range. z > y as in case II above but x has to be greater than both of them. Say z = 1/2, y = 1/3 and x = 1 \(1>1/9 > 1/16\) So all three statements could be true. "



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Re: If x > y^2 > z^4, which of the following statements could be
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28 Feb 2012, 05:59
imhimanshu wrote: Thanks Bunuel for your response.. This is what I mean when I said range  Red Part in Karishma's response" VeritasPrepKarishma wrote: First notice that since x>z^4 (x is greater than some nonnegative value) then x>0. Now, as Karishma correctly noted, numbers in powers behave differently in the range {0. 1} and {1. +infinity}. For example: If 0<a<1 then a, a^2 and a^4 will be ordered as follows: 0(a^4)(a^2)(a)1If a>1 then a, a^2 and a^4 will be ordered as follows: 1(a)(a^2)(a^4)So, we should take the above difference in ordering into account when picking numbers for x, y, and z, since we need to find the values which satisfy 3 different statements. Hope it's clear.
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Re: If x > y^2 > z^4, which of the following statements could be
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08 Sep 2013, 07:15
Restrictions are not provided on the variables so I planned to check different values I and used x=y=z=1/2. As if I take 1/2 for each variables, its given condition would be satisfied and it will become 1/2>1/4>1/8.
So according to me none of the conditions are satisfied. Am I doing anything wrong here?



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Re: If x > y^2 > z^4, which of the following statements could be
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08 Sep 2013, 07:40
chetan86 wrote: Restrictions are not provided on the variables so I planned to check different values I and used x=y=z=1/2. As if I take 1/2 for each variables, its given condition would be satisfied and it will become 1/2>1/4>1/8.
So according to me none of the conditions are satisfied. Am I doing anything wrong here? Notice that the question asks "which of the following statements could be true" NOT "which of the following statements must be true"
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Re: If x > y^2 > z^4, which of the following statements could be
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07 Nov 2013, 02:10
Bunuel wrote: Orange08 wrote: If x > y^2 > z^4, which of the following statements could be true?
I. x>y>z II. z>y>x III. x>z>y
A. I only B. I and II only C. I and III only D. II and III only E. I, II and II As this is a COULD be true question then even one set of numbers proving that statement holds true is enough to say that this statement should be part of correct answer choice. Given: \(x > y^2 > z^4\). 1. \(x>y>z\) > the easiest one: if \(x=100\), \(y=2\) and \(z=1\) > this set satisfies \(x > y^2 > z^4\) as well as given statement \(x>y>z\). So 1 COULD be true. 2. \(z>y>x\) > we have reverse order than in stem (\(x > y^2 > z^4\)), so let's try fractions: if \(x=\frac{1}{5}\), \(y=\frac{1}{4}\) and \(z=\frac{1}{3}\) then again the stem and this statement hold true. So 2 also COULD be true. 3. \(x>z>y\) > let's make \(x\) some big number, let's say 1,000. Next, let's try the fractions for \(z\) and \(y\) for the same reason as above (reverse order of \(y\) and \(z\)): \(y=\frac{1}{3}\) and \(z=\frac{1}{2}\). The stem and this statement hold true for this set of numbers. So 3 also COULD be true. Answer: E. Isn't it stated in the exam that assume all numbers are integers? We can't try fractions unless they say they are not integers.



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Re: If x > y^2 > z^4, which of the following statements could be
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07 Nov 2013, 02:19
SaramiR wrote: Bunuel wrote: Orange08 wrote: If x > y^2 > z^4, which of the following statements could be true?
I. x>y>z II. z>y>x III. x>z>y
A. I only B. I and II only C. I and III only D. II and III only E. I, II and II As this is a COULD be true question then even one set of numbers proving that statement holds true is enough to say that this statement should be part of correct answer choice. Given: \(x > y^2 > z^4\). 1. \(x>y>z\) > the easiest one: if \(x=100\), \(y=2\) and \(z=1\) > this set satisfies \(x > y^2 > z^4\) as well as given statement \(x>y>z\). So 1 COULD be true. 2. \(z>y>x\) > we have reverse order than in stem (\(x > y^2 > z^4\)), so let's try fractions: if \(x=\frac{1}{5}\), \(y=\frac{1}{4}\) and \(z=\frac{1}{3}\) then again the stem and this statement hold true. So 2 also COULD be true. 3. \(x>z>y\) > let's make \(x\) some big number, let's say 1,000. Next, let's try the fractions for \(z\) and \(y\) for the same reason as above (reverse order of \(y\) and \(z\)): \(y=\frac{1}{3}\) and \(z=\frac{1}{2}\). The stem and this statement hold true for this set of numbers. So 3 also COULD be true. Answer: E. Isn't it stated in the exam that assume all numbers are integers? We can't try fractions unless they say they are not integers. No that's not true at all. All numbers on the test represent real numbers: Integers, Fractions and Irrational Numbers. You cannot assume a variable is integer if you are not explicitly told so.
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Re: If x > y^2 > z^4, which of the following statements could be
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07 Aug 2015, 15:45
Algebraic solution:
In the question we are given: x>y2>z4, hence from concepts of inequalities we break it into 2 parts: x>y2 and y2>z4. 1. x>y2 means x(1/2)<y<x(1/2) 2. y2>z4 means y<z2<y, but a square cannot be negative so 0<z2<y, this implies y(1/2)<z<y(1/2).
Now we plot all these points on number line with the intersection of there ranges. But before that we need to understand that we will only be taking x,y,z as positive since if we take y as negative for example(easiest one) the value z(2) becomes negative, whereas a square can never be negative.
hence we plot all of them on the positive xaxis. From above 1 & 2 point we get a general range as such 0<z<y(1/2)<y<x(1/2)<x. Now, we need to see that we haven't in reality considered various values of x,y,z but have come up with a general idea of how they look on the number line. Now we define the ranges, since we know about a^x graph varies for values 0<a<1 and a>1, we also take such cases for all three of them. 1. 0<x<1 and x>1 2. 0<y<1 and y>1 3. 0<z<1 and z>1
Hence looking at the combinations we find we have 8 possibilities (2*2*2). taking the 2 general ones: 1. x>1 y>1 z>1. In the general formula we simply put x,y,z and get x>y>z. (Would have figured initially). 2. 0<x<1, 0<y<1 and 0<z<1. In this possibility put x as 1/x, y as 1/y and z as 1/z in general formula we get z>y>x. 3. x>1 0<y<1 and 0<z<1. In this put y as 1/y and z as 1/z. Keep x as x in general formula, we see x>1/y>1/z. since only 1/y>1/z are in reciprocal hence z>y by inequalities. thus x>z>y.
Therefore we can get 8 possibilities and the fact is all of them are correct.



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Re: If x > y^2 > z^4, which of the following statements could be
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22 Aug 2015, 23:59
Hi vinnisatija,
Yes, if you see a "could be" question, then just one example that satisfies the given condition is sufficient. In case of "must be" questions, the required condition must hold true under all circumstances along with whatever additional constraint is given in the problem.
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Re: If x > y^2 > z^4, which of the following statements could be
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10 Mar 2017, 10:41
Quote: If x > y^2 > z^4, which of the following statements could be true?
I. x>y>z II. z>y>x III. x>z>y
A. I only B. I and II only C. I and III only D. II and III only E. I, II and II We are given that x > y^2 > z^4 and need to determine which statements must be true. Let’s test each Roman Numeral. I. x > y > z Notice that the order of arrangement of x, y, and z in the inequality x > y > z is the same as the order of arrangement of x, y^2, and z^4 in the inequality x > y^2 > z^4, so we want to test positive integers in this case. x = 10 y = 3 z = 1 Notice that 10 > 3 > 1 for x > y > z AND 10 > 9 > 1 for x > y^2 > z^4. We see that I could be true. II. z > y > x Notice that the order of arrangement of x, y, and z in the inequality z > y > x differs from the order of arrangement of x, y^2, and z^4 in the inequality x > y^2 > z^4, so we want to test positive proper fractions in this case. This is because we need to decrease the value of y and z to make them work within the given inequality. x = 1/5 y = 1/3 z = 1/2 Notice that 1/2 > 1/3 > 1/5 for z > y > x AND 1/5 > 1/9 > 1/16 for x > y^2 > z^4. We see that II could be true. III. x > z > y Notice that the order of arrangement of y and z in the inequality x > z > y differs from the order of arrangement of y^2 and z^4 in the inequality x > y^2 > z^4, so we once again want to test positive proper fractions. This is because we need to decrease the value of z to make it work within the given inequality (that is, we want to swap the order of z4 and y2 even if z > y). x = 1/2 y = 1/4 z = 1/3 Notice that 1/2 > 1/3 > 1/4 for x > z > y AND 1/2 > 1/16 > 1/81 for x > y^2 > z^4. We see that III could be true. Answer: E
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Re: If x > y^2 > z^4, which of the following statements could be
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11 May 2017, 05:35
If x > y^2 > z^4, which of the following statements could be true? I. x>y>z II. z>y>x III. x>z>y A. I only B. I and II only C. I and III only D. II and III only E. I, II and II Solution: To answer questions like this, use ZONEF. Z = zero O = one N = negative integers E = Extreme Integers (Read as Positive Integers > 1) F = Fractions (think both positive and negative) For x > y^2 > z^4, the following numbers work: x = 10, y = 3, z = 1. So , I is true. Eliminate (D). The easiest way to prove II true is to multiply the above numbers by 1, but as you are dealing with even exponents, negative numbers will not work. That leaves us with F(Fractions). Let z = 0.9, y = 0.7 and x = 0.1 These numbers keep both x > y^2 > z^4 and z > y > x true. Eliminate (A) and (C). Now, proving the third is easy. Just take x = any big positive number, say 10 Now, you have x = 10, y = 0.7 and z = 0.9 These values keep both x > y^2 > z^4 and x > z > y true. So, all three are true. The answer is (E).
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Re: If x > y^2 > z^4, which of the following statements could be
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25 Jun 2017, 12:13
Orange08 wrote: If x > y^2 > z^4, which of the following statements could be true?
I. x>y>z II. z>y>x III. x>z>y
A. I only B. I and II only C. 1 and III only D. II and III only E. I, II and II Question is about "COULD BE" true ..so we just need one set of numbers which ensures that the above conditions are true.. Take x = 100, y = 5 and z = 2 So statement 1 and the statement in the question stem are true.. Take x = 0.4, y = 0.5 and z = 0.6 So statement 2 and the statement in the question stem are true Take x = 100, y = 0.5 and z = 0.6 So statement 3 and the statement in the question stem are true So option E
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Re: If x > y^2 > z^4, which of the following statements could be
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17 Jan 2018, 16:37
Orange08 wrote: If \(x > y^2 > z^4\), which of the following statements could be true?
I. \(x>y>z\)
II. \(z>y>x\)
III. \(x>z>y\)
A. I only B. I and II only C. 1 and III only D. II and III only E. I, II and II If we CAN find a set of values that satisfies a statement AND yields values such that x > y² > z⁴, then we'll keep that statement. Statement I. x > y > z If x = 2, y = 1, and z = 0, then x > y² > z⁴ KEEP statement I Statement II. z > y > x If x = 1/4, y = 1/3, and z = 1/2, then x > y² > z⁴ KEEP statement II Statement III. x > z > y If x = 2, y = 1, and z = 0, then x > y² > z⁴ KEEP statement III Answer: E Cheers, Brent
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