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# If (x-y)^3 > (x-y)^2, then which of the following must be true?

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Current Student
Joined: 12 Aug 2015
Posts: 2633
Schools: Boston U '20 (M)
GRE 1: Q169 V154
If (x-y)^3 > (x-y)^2, then which of the following must be true?  [#permalink]

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Updated on: 21 Apr 2017, 12:40
1
4
00:00

Difficulty:

25% (medium)

Question Stats:

74% (01:50) correct 26% (02:02) wrong based on 222 sessions

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If $$(x-y)^3>(x-y)^2$$, then which of the following must be true?

A. $$x^3<y^2$$

B. $$x^5<y^4$$

C. $$x^3>y^2$$

D. $$x^5>y^4$$

E. $$x^3>y^3$$

Source-> NOVA.

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Originally posted by stonecold on 21 Apr 2017, 09:24.
Last edited by stonecold on 21 Apr 2017, 12:40, edited 2 times in total.
Renamed the topic and edited the question.
Senior Manager
Joined: 02 Mar 2017
Posts: 263
Location: India
Concentration: Finance, Marketing
Re: If (x-y)^3 > (x-y)^2, then which of the following must be true?  [#permalink]

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21 Apr 2017, 19:48
1
(x−y)^3>(x−y)^2

Clearly Implies (X-Y)^3 > 0

which Implies X>Y-----Option E states X^3 > Y^3 -------X>Y
Hence E Must be true
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Kudos-----> If my post was Helpful

Current Student
Joined: 12 Aug 2015
Posts: 2633
Schools: Boston U '20 (M)
GRE 1: Q169 V154
Re: If (x-y)^3 > (x-y)^2, then which of the following must be true?  [#permalink]

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27 Apr 2017, 21:03
Here is what i did on this one ==>

Questions such as these are best solved by using Test Cases.

First and Foremost ==> (x-y)^3>(x-y)^2
Hence (x-y)>1

So x>y+1

Option 1 =>
Taking x=10 y=1 => REJECTED.

Option 2 =>
Taking x=10 and y=1 => REJECTED.

Option 3 =>
Taking x=-10 and y=-100 => REJECTED.

Option 4 =>
Taking x=-10 and y=-100 => REJECTED.

Only option left is E.

SMASH THAT E.

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Joined: 09 Apr 2016
Posts: 1
Re: If (x-y)^3 > (x-y)^2, then which of the following must be true?  [#permalink]

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29 Apr 2017, 23:04
1
(x-y)^3 will be positive if
i) both x and y are +ve and x>y,
ii) both x and y are -ve and y<x
iii) x is +ve and y is -ve

Case i-Let's assume that both X&Y are positive numbers.
x=3 and y=1
(x-y)^3 > (x-y)^2
Checking validity of the given options
a) x^3 < y^2 Incorrect.
b) x^5 < y^4 Incorrect.
c) x^3 >y^2 Correct.
d) x^5 > y^4 Correct.
e) x^3 > y^3 Correct.

Case ii-Let's assume that both X&Y are negative numbers and y<x
x=-2 and y=-5
(x-y)^3 > (x-y)^2
Checking validity of the given options
a) x^3 < y^2 Correct.
b) x^5 < y^4 Correct.
c) x^3 >y^2 Incorrect.
d) x^5 > y^4 Incorrect.
e) x^3 > y^3 Correct.

Case iii-Let's assume that both X is +ve and y is -ve
x=3 and y=-1
(x-y)^3 > (x-y)^2
Checking validity of the given options
a) x^3 < y^2 Incorrect.
b) x^5 < y^4 Incorrect.
c) x^3 >y^2 Correct.
d) x^5 > y^4 Correct.
e) x^3 > y^3 Correct.

Only option E is correct in all 3 scenarios.
Intern
Joined: 14 Oct 2016
Posts: 30
Location: India
WE: Sales (Energy and Utilities)
Re: If (x-y)^3 > (x-y)^2, then which of the following must be true?  [#permalink]

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29 Aug 2017, 14:56
If (x−y)^3>(x−y)^2, then which of the following must be true?

Let (x−y) = a

so , a^3> a^2 implies a>0

that is x-y>0 , so that means x>y (but we cannot say for sure if x, y is >or< 0)
Also X can be integers and or fractions . Don't assume that its only integer.

Now if we see all options we have

A. x^3<y^2 ( Not always true )

B. x^5<y^4 ( Not always true )

C. x^3>y^2 ( Not always true)

D. x^5>y^4 ( Not always true)

E. x^3>y^3 Yes ( true even in case of fractions)
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Abhimanyu

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Joined: 11 Mar 2015
Posts: 35
Re: If (x-y)^3 > (x-y)^2, then which of the following must be true?  [#permalink]

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02 Dec 2017, 07:24
(X-Y)^3>(X-Y)^2
=>(X-Y)^2*(X-Y)>(X-Y)^2
=> X-Y>0
=> X>Y
Therefore, E is the correct option
Re: If (x-y)^3 > (x-y)^2, then which of the following must be true? &nbs [#permalink] 02 Dec 2017, 07:24
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