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If x, y, and z are all positive integers, how many trailing zeros are

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Bunuel
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If x, y, and z are all positive integers, how many trailing zeros are [#permalink] New post   29 Apr 2016, 16:05
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If x, y, and z are all positive integers, how many trailing zeros are contained in the product of (5^x)(2^y)(3^z)?

(1) x = 12
(2) x < y
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C
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prashant212
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Re: If x, y, and z are all positive integers, how many trailing zeros are [#permalink] New post   29 Apr 2016, 21:40
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The number of trailing zeros in a number will always depend on the number of 5's and 2's available as factors.

This question is basically asking us to find the number of pairs of 5 and 2.
First condition is certainly not enough.
Second condition is just a relation.Hence not enough.

Combining both conditions will tell us the exact number of pairs of 5 and 2. Thus C is the answer.
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Re: If x, y, and z are all positive integers, how many trailing zeros are [#permalink] New post   30 Apr 2016, 05:23
Bunuel wrote:
If x, y, and z are all positive integers, how many trailing zeros are contained in the product of (5^x)(2^y)(3^z)?

(1) x = 12
(2) x < y



C it is...(5,2) creates a zero....minimal pairing concept...
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Re: If x, y, and z are all positive integers, how many trailing zeros are [#permalink] New post   30 Apr 2016, 13:15
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[quote="Bunuel"]If x, y, and z are all positive integers, how many trailing zeros are contained in the product of (5^x)(2^y)(3^z)?

(1) x = 12
(2) x < y


I think the answer to this question should be C as each statement alone is not giving any solution but by combining both we know that x is 12 and y is more than 12. thus the product has 12 zeros in it.
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Re: If x, y, and z are all positive integers, how many trailing zeros are [#permalink] New post   10 Aug 2022, 07:40
Why first condition isnt enough ? there will always be more 5 in the product so knowing the number of 5 isnt enough ? i dont understand
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Re: If x, y, and z are all positive integers, how many trailing zeros are [#permalink]
10 Aug 2022, 07:40
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Bunuel
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