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# If x, y, and z are positive integers, is x+y divisible by 7?

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
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GMAT 1: 760 Q51 V42
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If x, y, and z are positive integers, is x+y divisible by 7?  [#permalink]

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25 Feb 2018, 18:38
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Difficulty:

35% (medium)

Question Stats:

74% (01:20) correct 26% (01:29) wrong based on 49 sessions

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[GMAT math practice question]

If $$x, y$$, and $$z$$ are positive integers, is $$x+y$$ divisible by $$7$$?

1) $$x+z$$ is divisible by $$7$$
2) $$y+z$$ is divisible by $$7$$

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"Only $79 for 1 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Math Expert Joined: 02 Aug 2009 Posts: 8282 Re: If x, y, and z are positive integers, is x+y divisible by 7? [#permalink] ### Show Tags 25 Feb 2018, 19:03 MathRevolution wrote: [GMAT math practice question] If $$x, y$$, and $$z$$ are positive integers, is $$x+y$$ divisible by $$7$$? 1) $$x+z$$ is divisible by $$7$$ 2) $$y+z$$ is divisible by $$7$$ Statements alone are clearly insuff as we are not told about third variable.. 1) x+z is divisible by 7. Nothing about y, insufficient 2) y+z is div by 7 Nothing about x, insufficient Combined.. X+z and y+z are div by 7, so we can say for sure x+y+2z is div by 7.. So if z is div by 7, x+y is div by 7.. z=14, both x and y will have to be div by 7 to satisfy the statements and hence their sum is div by 7. But if z is not div by 7, x+y is not div by 7.. z=4, so x can be 3 as X+z is div by 7.. Similarly y can be 10, as y+z is div by 7.. But x+y =3+10=13 is not Insufficient E _________________ Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 8229 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: If x, y, and z are positive integers, is x+y divisible by 7? [#permalink] ### Show Tags 26 Feb 2018, 02:31 => Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution. Since we have 3 variables ($$x, y$$ and $$z$$) and $$0$$ equations, E is most likely to be the answer. So, we should consider conditions 1) & 2) together first. Conditions 1) & 2): If $$x = 7, y = 7,$$ and $$z = 7$$, the answer is ‘yes’, since $$x + y = 14$$ is divisible by $$7$$. If $$x = 1, y = 1$$, and $$z = 6$$, the answer is ‘no’, since $$x + y = 2$$ is not divisible by $$7$$. Thus, conditions 1) and 2) together are not sufficient. Therefore, E is the answer. Answer: E In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C or D. _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$79 for 1 month Online Course"
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Re: If x, y, and z are positive integers, is x+y divisible by 7?   [#permalink] 26 Feb 2018, 02:31
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