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If x, y and z are positive single-digit integers and x*y = z. What is

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Bunuel
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If x, y and z are positive single-digit integers and x*y = z. What is [#permalink] New post   19 Sep 2017, 01:32
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If x, y and z are positive single-digit integers and x*y = z. What is z?

(1) x and y even numbers
(2) x = y
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C
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Luckisnoexcuse
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Re: If x, y and z are positive single-digit integers and x*y = z. What is [#permalink] New post   19 Sep 2017, 01:48
Bunuel wrote:
If x, y and z are positive single-digit integers and x*y = z. What is z?

(1) x and y even numbers
(2) x = y


(1) x,y,z can be 2,4,8 or 2,2,4
not sufficient

(2) x,y,z can be 1,1,1 or 2,2,4 or 3,3,9
not sufficient

on combining

only 2,2,4 satisfies

C
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Re: If x, y and z are positive single-digit integers and x*y = z. What is [#permalink] New post   19 Sep 2017, 03:03
Bunuel wrote:
If x, y and z are positive single-digit integers and x*y = z. What is z?

(1) x and y even numbers
(2) x = y


Because z is positive single digit integer, so the value is between 1 and 9.
- Statement 1 : many pairs can result in 1-9 value. We have 2*4;4*2;2*2... NS.
- Statement 2 : many pairs also. We have 1*1; 2*2 and 3*3. NS
- Combine, we only get one possible pair = 2*2.

C.
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Re: If x, y and z are positive single-digit integers and x*y = z. What is [#permalink] New post   19 Sep 2017, 03:30
Bunuel wrote:
If x, y and z are positive single-digit integers and x*y = z. What is z?

(1) x and y even numbers
(2) x = y


Given x, y, z are positive single digit integers.
S1 - x,y can be any even numbers
if x=2, y=4, z=8
or if x=2, y=2, z=4.
two different answers hence not sufficient.

S2 - x=y
if x=y=2, z=4
or if x=1,y=1, z=1
two different answers hence not sufficient.

Combining both statements x=y and both are even,
only option is x=y=2, z=4 because any other even integer will lead to z as 2 digit integer
hence C

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Re: If x, y and z are positive single-digit integers and x*y = z. What is [#permalink] New post   18 May 2019, 22:33
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Re: If x, y and z are positive single-digit integers and x*y = z. What is [#permalink]
18 May 2019, 22:33
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