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Difficulty: 605-655 Levelx   Arithmeticx                              
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Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
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hloonker wrote:
Guys what is y = 159 and z=149. in this case if you take the stand alone 10's digits of both y and z you get 9, but when you actually in fact end up adding the numbers the 9 and the 9 from y and z lead to a carry over of one and then the 1 adds to both 4 and 5

Statement (1) does not allow for the case that you're describing, hloonker. The tens digit of (159+149) is 0, whereas the sum of the tens digits of x and y is 9. 0 is not equal to 9, therefore your case violates statement (1).
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Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
y: 153
z: 150
x: 303

Sum of tens digits of y and z: 5+5 =0, equal to x's tens digit (0); sum of hundreds digits of y and z: 1+1=2, not equal to x's hundreds digit (3)

y: 153
z: 111
x: 264

Sum of tens digits of y and z: 5+1 =6, equal to x's tens digit (6); sum of hundreds digits of y and z: 1+1= 2, equal to x's hundreds digit (2)

So even if the sum of tens digits of y and z equals to the tens digit of x, the hundreds digit of x may or may not be the sum of the hundreds digits of y and z. I'm stuck on this question but I must be missing something obvious. Can someone please explain?
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Re: If x, y, and z are three-digit positive integers and if x = [#permalink]
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