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Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  If x & y are integers and y = x^2 + x^3, is y < 0? (1) x < 0 (2) y < 1

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Math Expert V
Joined: 02 Sep 2009
Posts: 58335
If x & y are integers and y = x^2 + x^3, is y < 0? (1) x < 0 (2) y < 1  [#permalink]

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Difficulty:   55% (hard)

Question Stats: 63% (02:00) correct 37% (01:24) wrong based on 58 sessions

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If x & y are integers and y = x^2 + x^3, is y < 0?

(1) x < 0
(2) y < 1

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examPAL Representative P
Joined: 07 Dec 2017
Posts: 1129
Re: If x & y are integers and y = x^2 + x^3, is y < 0? (1) x < 0 (2) y < 1  [#permalink]

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Bunuel wrote:
If x & y are integers and y = x^2 + x^3, is y < 0?

(1) x < 0
(2) y < 1

1) let's say x=-1: in this case, y = 1 -1 = 0 ===> the answer is no!
But now let's try another number: say x=-2: in this case, y =4-8=-4 ==> the answer is yes!
We've used the data to get two contradicting answers - insufficient! eliminate A & D

2) if y is an integer smaller than 1, it is either negative (meaning the answer is yes) or zero (meaning it is no). As we've just seen, it can be both given the above expression, and this data gives us no tools to decide which - insufficient! Eliminate B.

Combined: (1) tells us y can be either negative or zero. (2) tells us the same. neither adds any information to the other. insufficient! Eliminate C.

E is our answer.
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Joined: 31 Oct 2013
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Concentration: Accounting, Finance
GPA: 3.68
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Re: If x & y are integers and y = x^2 + x^3, is y < 0? (1) x < 0 (2) y < 1  [#permalink]

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Bunuel wrote:
If x & y are integers and y = x^2 + x^3, is y < 0?

(1) x < 0
(2) y < 1

Statement 1:

x<0.

let x be -1.

In this case y = 0.

Not Sufficient.

Statement 2;

y<1.

y could be 0 , -100.

Not sufficient.

Combining both statements :

If y is less than 1 and x<0 , y could be 0 , -100 - 5..........

Still NOT sufficient.

The best answer is E. Re: If x & y are integers and y = x^2 + x^3, is y < 0? (1) x < 0 (2) y < 1   [#permalink] 09 Oct 2018, 03:37
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If x & y are integers and y = x^2 + x^3, is y < 0? (1) x < 0 (2) y < 1

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