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# If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =

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Math Expert
Joined: 02 Sep 2009
Posts: 59722
If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =  [#permalink]

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08 May 2015, 06:33
00:00

Difficulty:

5% (low)

Question Stats:

91% (00:53) correct 9% (01:42) wrong based on 108 sessions

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If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =

(A) 4/3
(B) 1/3
(C) 1/12
(D) -1/12
(E) -4/3

Kudos for a correct solution.

_________________
Intern
Joined: 09 Jan 2015
Posts: 8
Re: If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =  [#permalink]

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08 May 2015, 10:52
(-1)^2 / 2 = 1/2
(1/2)^2 / 3 = 1/12
so C is my answer
Current Student
Joined: 24 Mar 2015
Posts: 35
Concentration: General Management, Marketing
GMAT 1: 660 Q44 V38
GPA: 3.21
WE: Science (Pharmaceuticals and Biotech)
Re: If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =  [#permalink]

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08 May 2015, 13:25
1
Bunuel wrote:
If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =

(A) 4/3
(B) 1/3
(C) 1/12
(D) -1/12
(E) -4/3

Kudos for a correct solution.

Working inside to out:
(-1)^2/2= 1/2
gives us: (1/2)#3
(1/2)^2/3 = (1/4)(1/3) = 1/12 answer choice C.
Manager
Joined: 09 Jan 2013
Posts: 68
Concentration: Entrepreneurship, Sustainability
GMAT 1: 650 Q45 V34
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GRE 1: Q790 V650
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WE: Other (Pharmaceuticals and Biotech)
Re: If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =  [#permalink]

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09 May 2015, 02:46
1
Since you always solve the part in brackets
$$-1#2 = (-1)^2/2= 1/2$$
Thus,
$$(1/2)#3 = (1/2)^2/3 = (1/4)(1/3) = 1/12$$

Director
Joined: 21 May 2013
Posts: 633
Re: If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =  [#permalink]

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09 May 2015, 09:33
1
Bunuel wrote:
If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =

(A) 4/3
(B) 1/3
(C) 1/12
(D) -1/12
(E) -4/3

Kudos for a correct solution.

(-1#2)=-1^2/2=1/2
And, (1/2)#3=1/4/3=1/4*1/3=1/12
Re: If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =   [#permalink] 09 May 2015, 09:33
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# If x#y is defined to equal x^2/y for all x and y, then (-1#2)#3 =

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