Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack
GMAT Club

 It is currently 22 Mar 2017, 17:24

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# If x#-y is (x-y)/(x+y)>1? (1) x>0 (2) y<0

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Director
Joined: 16 Aug 2005
Posts: 945
Location: France
Followers: 1

Kudos [?]: 23 [0], given: 0

If x#-y is (x-y)/(x+y)>1? (1) x>0 (2) y<0 [#permalink]

### Show Tags

23 Jun 2006, 08:17
2
This post was
BOOKMARKED
00:00

Difficulty:

85% (hard)

Question Stats:

43% (02:31) correct 57% (01:25) wrong based on 111 sessions

### HideShow timer Statistics

If x#-y is (x-y)/(x+y)>1?

(1) x>0
(2) y<0

OPEN DISCUSSION OF THIS QUESTION IS HERE: if-x-y-is-x-y-x-y-1-1-x-0-2-y-96090.html
[Reveal] Spoiler: OA

_________________

I believe its yogurt!

Last edited by Bunuel on 26 Apr 2012, 21:24, edited 2 times in total.
Edited the question and added the OA. Topic is locked.
VP
Joined: 15 Jun 2006
Posts: 1124
Schools: Chicago Booth
Followers: 5

Kudos [?]: 43 [0], given: 0

Re: GMATprep DS [#permalink]

### Show Tags

23 Jun 2006, 08:33
gmatmba wrote:
If x not equal to -y
is (x-y)/(x+y) >1?

(1) x > 0
(2) y < 0

E)

for solving this we need to establish if |x|>|y|
neither of the conditions provides an answer
consider:
a)x=2;y=-3
2+3/2-3=-5<1
b)x=3;y=-2
3+2/3-2=5>1
Senior Manager
Joined: 05 Jan 2006
Posts: 382
Followers: 1

Kudos [?]: 89 [0], given: 0

### Show Tags

23 Jun 2006, 08:46
E

X+Y # 0

is x-y/x+y>1

Let's analyze different scenerio,
1) x+, y+
2) x-, y-
3) x+, y-
4) x-, y+

for (1) and (2) |x-y|<|x+y| => |x-y|/|x+y| < 1 it can be positive or negative depending on x>y or x<y

Look at example:
for (1)
(1, 2) =x-y/x+y = -1/3
(2, 1) =x-y/x+y = 1/3

for (2)
(-1, -2) =x-y/x+y = -1/3
(-2, -1) =x-y/x+y = 1/3

For (3) and (4) |x-y|>|x+y| => |x-y|/|x+y| > 1

if x+ and y-
(1,-2) =x-y/x+y = -3
(2,-1) =x-y/x+y = +3

if x- and y+
(-1,2) =x-y/x+y = -3
(-2,1) =x-y/x+y = 3

A) says x>0 does not tell us anything about Y insufficient
B) says y<0 does not tell us anything about X insufficient

togather x+ and y- scnerio 3, it can be positve or negative so insufficient!

Hence E
VP
Joined: 02 Jun 2006
Posts: 1266
Followers: 2

Kudos [?]: 83 [1] , given: 0

### Show Tags

23 Jun 2006, 09:25
1
KUDOS
This Q had me thoroughly confused.. but I finally got it.

Q : (x-y)/(x+y) > 1 i.e (x-y) > (x+y)

S1: x > 0
Let x = 4, y = -7 then 11 >-3 True.
Let x = 4, y = -1 then 3 > 5 False

Different answers ... not sufficient.

S2: y < 0
Using the same values as above, different answers. ... Not sufficient.

S1 & S2:
Same set of values as above provide different answers
Therefore Not sufficient.

Director
Joined: 16 Aug 2005
Posts: 945
Location: France
Followers: 1

Kudos [?]: 23 [0], given: 0

### Show Tags

23 Jun 2006, 13:20
chiragr wrote:
E

X+Y # 0

is x-y/x+y>1

Let's analyze different scenerio,
1) x+, y+
2) x-, y-
3) x+, y-
4) x-, y+

for (1) and (2) |x-y|<|x+y| => |x-y|/|x+y| < 1 it can be positive or negative depending on x>y or x<y

Look at example:
for (1)
(1, 2) =x-y/x+y = -1/3
(2, 1) =x-y/x+y = 1/3

for (2)
(-1, -2) =x-y/x+y = -1/3
(-2, -1) =x-y/x+y = 1/3

For (3) and (4) |x-y|>|x+y| => |x-y|/|x+y| > 1

if x+ and y-
(1,-2) =x-y/x+y = -3
(2,-1) =x-y/x+y = +3

if x- and y+
(-1,2) =x-y/x+y = -3
(-2,1) =x-y/x+y = 3

A) says x>0 does not tell us anything about Y insufficient
B) says y<0 does not tell us anything about X insufficient

togather x+ and y- scnerio 3, it can be positve or negative so insufficient!

Hence E

Thats great explanation...thanks Chirag and hass_mba
How long did it take you guys to do it?
I couldn't do this on the test due to time constraints and got it wrong...
_________________

I believe its yogurt!

Manager
Joined: 27 Oct 2011
Posts: 191
Location: United States
Concentration: Finance, Strategy
GMAT 1: Q V
GPA: 3.7
WE: Account Management (Consumer Products)
Followers: 5

Kudos [?]: 158 [0], given: 4

Re: If x not equal to -y is (x-y)/(x+y) >1? (1) x > 0 (2) [#permalink]

### Show Tags

26 Apr 2012, 20:26
if you reorganize the question it becomes x - y < x + y ==> 0 < 2y ==> 0 < y.... Why is this logic not possible?
_________________

DETERMINED TO BREAK 700!!!

Math Expert
Joined: 02 Sep 2009
Posts: 37547
Followers: 7390

Kudos [?]: 99182 [2] , given: 11008

Re: If x not equal to -y is (x-y)/(x+y) >1? (1) x > 0 (2) [#permalink]

### Show Tags

26 Apr 2012, 21:23
2
KUDOS
Expert's post
3
This post was
BOOKMARKED
calreg11 wrote:
if you reorganize the question it becomes x - y < x + y ==> 0 < 2y ==> 0 < y.... Why is this logic not possible?

Given: $$\frac{x-y}{x+y}>1$$. When you are then writing $$x-y>x+y$$, you are actually multiplying both sides of inequality by $$x+y$$: never multiply an inequality by variable (or expression with variable) unless you know the sign of variable (or expression with variable). Because if $$x+y>0$$ you should write $$x-y>x+y$$ BUT if $$x+y<0$$, you should write $$x-y<x+y$$ (flip the sign when multiplying by negative expression).

COMPLETE SOLUTION:

If $$x\neq{-y}$$ is $$\frac{x-y}{x+y}>1$$?

Is $$\frac{x-y}{x+y}>1$$? --> Is $$0>1-\frac{x-y}{x+y}$$? --> Is $$0>\frac{x+y-x+y}{x+y}$$? --> Is $$0>\frac{2y}{x+y}$$?

(1) $$x>0$$ --> Not sufficient.

(2) $$y<0$$ --> Not sufficient.

(1)+(2) $$x>0$$ and $$y<0$$ --> numerator (y) is negative, but we can not say whether the denominator {positive (x)+negative (y)} is positive or negative. Not sufficient.

In case of any question please post it here: if-x-y-is-x-y-x-y-1-1-x-0-2-y-96090.html
_________________
Re: If x not equal to -y is (x-y)/(x+y) >1? (1) x > 0 (2)   [#permalink] 26 Apr 2012, 21:23
Similar topics Replies Last post
Similar
Topics:
3 If x ≠ -y, is (x-y)/(x+y)> 1 ? (1) x > 0 (2) y < 0 4 11 Jan 2016, 12:49
Is X^2Y^3Z^2>0 ? (1) XY>0 (2) YZ<0 3 17 Aug 2015, 14:59
Is x-y+1 greater than x+y-1? 1) x>0 2) y<0 10 01 Jun 2011, 14:15
Is x-y+1 greater than x+y-1 ? (1) x > 0 (2) y < 0 2 18 Aug 2010, 00:30
23 If x#-y is (x-y)/(x+y)>1? (1) x>0 (2) y<0 33 19 Jun 2010, 03:45
Display posts from previous: Sort by

# If x#-y is (x-y)/(x+y)>1? (1) x>0 (2) y<0

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.