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# If xθy=(x+1)/(y−1) for all y≠1, and aθb=1, then a=

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Retired Moderator
Joined: 29 Apr 2015
Posts: 815
Location: Switzerland
Concentration: Economics, Finance
Schools: LBS MIF '19
WE: Asset Management (Investment Banking)
If xθy=(x+1)/(y−1) for all y≠1, and aθb=1, then a=  [#permalink]

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13 Jun 2015, 08:54
00:00

Difficulty:

5% (low)

Question Stats:

81% (00:56) correct 19% (01:13) wrong based on 129 sessions

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If xθy=(x+1)/(y−1) for all y≠1, and aθb=1, then a=

A. b−2
B. b−1
C. b
D. b+1
E. b+2
Math Expert
Joined: 02 Sep 2009
Posts: 60778
Re: If xθy=(x+1)/(y−1) for all y≠1, and aθb=1, then a=  [#permalink]

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13 Jun 2015, 08:58
reto wrote:
If xθy=(x+1)/(y−1) for all y≠1, and aθb=1, then a=

A. b−2
B. b−1
C. b
D. b+1
E. b+2

$$aθb = \frac{(a + 1)}{(b-1)} = 1$$;

$$a + 1 = b - 1$$;

$$a = b - 2$$.

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Re: If xθy=(x+1)/(y−1) for all y≠1, and aθb=1, then a=   [#permalink] 13 Jun 2015, 08:58
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