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If x + y + z = 2, and x + 2y + 3z = 6 and y ≠ 0, then what is the valu

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Math Expert
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V
Joined: 02 Sep 2009
Posts: 49915
If x + y + z = 2, and x + 2y + 3z = 6 and y ≠ 0, then what is the valu  [#permalink]

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New post 04 Oct 2018, 00:33
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

79% (01:24) correct 21% (02:21) wrong based on 28 sessions

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Director
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G
Joined: 31 Oct 2013
Posts: 647
Concentration: Accounting, Finance
GPA: 3.68
WE: Analyst (Accounting)
Re: If x + y + z = 2, and x + 2y + 3z = 6 and y ≠ 0, then what is the valu  [#permalink]

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New post 04 Oct 2018, 00:42
Bunuel wrote:
If x + y + z = 2, and x + 2y + 3z = 6 and y ≠ 0, then what is the value of x/y?


(A) −1/2
(B) −1/3
(C) −1/6
(D) 1/3
(E) 1/2



x + y+ z = 2

3x + 3y + 3z = 6

3x + 3y + 3z = x + 2y + 3z

3x - x = 2y - 3y

2x = -y

x/y = -1 /2.


The best answer is A.
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Re: If x + y + z = 2, and x + 2y + 3z = 6 and y ≠ 0, then what is the valu  [#permalink]

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New post 04 Oct 2018, 01:39
Bunuel wrote:
If x + y + z = 2, and x + 2y + 3z = 6 and y ≠ 0, then what is the value of x/y?


(A) −1/2
(B) −1/3
(C) −1/6
(D) 1/3
(E) 1/2



Another way would be to substitute in the other equation.

Z = 2 - x - y

x + 2y + 3z = 6
x + 2y + 3(2 - x - y) = 6
x + 2y + 6 - 3x - 3y = 6

-2x - y = 0
-2x = y
-2 (x/y) = 1
(x/y) = - 1/2

Answer choice A

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Re: If x + y + z = 2, and x + 2y + 3z = 6 and y ≠ 0, then what is the valu &nbs [#permalink] 04 Oct 2018, 01:39
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If x + y + z = 2, and x + 2y + 3z = 6 and y ≠ 0, then what is the valu

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