Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: If x < y < z and y-x > 5, where x is an even integer and y [#permalink]

Show Tags

28 Mar 2012, 01:24

1

This post received KUDOS

y-x is >5. y is odd and x is even then y-x will be odd. Lowest possible value of y-x is 7. For lowest possible value of z-x, y and z should be close, it means y and z are consecutive odd integers or z = y + 2. Hence z-x = y + 2 - x = 7 + 2 = 9.

If x < y < z and y-x > 5, where x is an even integer and y and z are odd integers, what is the least possible value of z - x?

A. 6 B. 7 C. 8 D. 9 E. 10

We want to minimize \(z-x\), so we need to maximize \(x\).

Say \(z=11=odd\), then max value of \(y\) will be 9 (as \(y\) is also odd). Now, since \(y-5>x\) --> \(9-5>x\) --> \(4>x\), then max value of \(x\) is 2 (as \(x\) is even).

Hence, the least possible value of \(z-x\) is 11-2=9.

Re: If x < y < z and y-x > 5, where x is an even integer and y [#permalink]

Show Tags

19 Dec 2012, 00:27

I did it like this and i am getting 7 as the answer. Kindly tell me where i went wrong.

Given x<y<z y-x>5

From the first equation i subtracted x so 0<y-x<z-x From the second equation multiply by (-1) so -y+x<-5 adding the above 2 i got 0<z-x-5 ie z-x>5 We now that z-x is odd so the next odd number is 7.

I did it like this and i am getting 7 as the answer. Kindly tell me where i went wrong.

Given x<y<z y-x>5

From the first equation i subtracted x so 0<y-x<z-x From the second equation multiply by (-1) so -y+x<-5 adding the above 2 i got 0<z-x-5 ie z-x>5 We now that z-x is odd so the next odd number is 7.

You got z-x>5 but we also have y-x>5, so the least value of y-x is 7 and since z>y then the least value of z-x is 9.
_________________

Re: If x < y < z and y-x > 5, where x is an even integer and y [#permalink]

Show Tags

20 Dec 2012, 11:30

We have: 1) x<y<z 2) y-x>5 3) x=2k (x is an even number) 4) y=2n+1 (y is an odd number) 5) z=2p+1 (z is an odd number) 6) z-x=? least value

z-x=2p+1-2k=2p-2k+1=2(p-k)+1 - that means that z-x must be an ODD number. We can eliminate answer choices A, C and E we are asked to find the least value, so we have to pick the least numbers since y is odd and x is even, y-x must be odd. since y-x>5, the least value for y-x must be 7, the least value for x must be 2, and, thus, the least possible value for y must be 9 (y-2=7, y=9) 2<9<z, since z is odd, the least possible value for z is 11 z-x=11-2=9

If x < y < z and y - x > 5, where x is an even integer and y and [#permalink]

Show Tags

23 Apr 2013, 06:33

Acer86 wrote:

If x < y < z and y - x > 5, where x is an even integer and y and z are odd integers, what is the least possible value of z – x ? (A) 6 (B) 7 (C) 8 (D) 9 (E) 10

The answer i am getting is 7..thought original answer is something else...can someone help me out

Question asks least possible value, thus we can substitute by least possible numbers to get to answer

A, C and E are out since they are even

Left with B and E

y-x>5 which means least value of y-x=7 (since y is odd and x is even, result will be odd) Work back: y= 5 (least value) x= -2 (least value). thus y-x = 5 - (-2) = 7 (least possible odd integer greater than 5)

Since z> y, thus least possible value of z = 7 Therefore, z-x = 7 - (-2) = 9

Correct choice D
_________________

"When the going gets tough, the tough gets going!"

Re: If x < y < z and y-x > 5, where x is an even integer and y [#permalink]

Show Tags

28 Mar 2014, 00:46

ACE are out as they are even. z = odd and x is even therefore Z-X is odd. out of B or D we need to see that we have to get the minimum value of z-x so we have to minimize z and maximize x. Hence z-x is 9

Re: If x < y < z and y-x > 5, where x is an even integer and y [#permalink]

Show Tags

24 Nov 2015, 09:35

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Its been long time coming. I have always been passionate about poetry. It’s my way of expressing my feelings and emotions. And i feel a person can convey...

Written by Scottish historian Niall Ferguson , the book is subtitled “A Financial History of the World”. There is also a long documentary of the same name that the...

Post-MBA I became very intrigued by how senior leaders navigated their career progression. It was also at this time that I realized I learned nothing about this during my...