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# If x, y, z are chosen from the three numbers –3, 1/2, and 2, what is

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Math Expert
Joined: 02 Sep 2009
Posts: 44298
If x, y, z are chosen from the three numbers –3, 1/2, and 2, what is [#permalink]

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05 Nov 2017, 01:28
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Difficulty:

5% (low)

Question Stats:

85% (00:56) correct 15% (01:22) wrong based on 59 sessions

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If x, y, z are chosen from the three numbers –3, 1/2, and 2, what is the largest possible value of the expression x*z^2/y?

(A) –3/8
(B) 16
(C) 24
(D) 36
(E) 54
[Reveal] Spoiler: OA

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Math Expert
Joined: 02 Aug 2009
Posts: 5720
Re: If x, y, z are chosen from the three numbers –3, 1/2, and 2, what is [#permalink]

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05 Nov 2017, 01:42
Bunuel wrote:
If x, y, z are chosen from the three numbers –3, 1/2, and 2, what is the largest possible value of the expression x*z^2/y?

(A) –3/8
(B) 16
(C) 24
(D) 36
(E) 54

remember the following rules..
1) A NEGATIVE integer should be put to EVEN power to get a positive value out of it if there is only one negative value..
2) put any fraction<1 in the DENOMINATOR to get the max value out of it

so in $$x*\frac{z^2}{y}$$ , put z as -3 , y as 1/2 and x as the remaining value 2..
$$x*\frac{z^2}{y}..........2*(-3)^2/(1/2)=2*9*2=36$$
D
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Absolute modulus :http://gmatclub.com/forum/absolute-modulus-a-better-understanding-210849.html#p1622372
Combination of similar and dissimilar things : http://gmatclub.com/forum/topic215915.html

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Re: If x, y, z are chosen from the three numbers –3, 1/2, and 2, what is   [#permalink] 05 Nov 2017, 01:42
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