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• ### $450 Tuition Credit & Official CAT Packs FREE December 15, 2018 December 15, 2018 10:00 PM PST 11:00 PM PST Get the complete Official GMAT Exam Pack collection worth$100 with the 3 Month Pack ($299) • ### FREE Quant Workshop by e-GMAT! December 16, 2018 December 16, 2018 07:00 AM PST 09:00 AM PST Get personalized insights on how to achieve your Target Quant Score. # If x, y, z are integers, is xyz a multiple of 6?  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics Author Message TAGS: ### Hide Tags Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 6639 GMAT 1: 760 Q51 V42 GPA: 3.82 If x, y, z are integers, is xyz a multiple of 6? [#permalink] ### Show Tags 21 Sep 2018, 00:23 00:00 Difficulty: 65% (hard) Question Stats: 49% (01:18) correct 51% (01:32) wrong based on 49 sessions ### HideShow timer Statistics [Math Revolution GMAT math practice question] If $$x, y, z$$ are integers, is $$xyz$$ a multiple of $$6$$? 1) $$x+y+z$$ is a multiple of $$6$$ 2) $$x, y$$, and $$z$$ are consecutive integers _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$99 for 3 month Online Course"
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Re: If x, y, z are integers, is xyz a multiple of 6?  [#permalink]

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21 Sep 2018, 00:39
1
MathRevolution wrote:
[Math Revolution GMAT math practice question]

If $$x, y, z$$ are integers, is $$xyz$$ a multiple of $$6$$?

1) $$x+y+z$$ is a multiple of $$6$$
2) $$x, y$$, and $$z$$ are consecutive integers

Question: is xyz multiple of 6 ?

Statement 1: x + y + z is multiple of 6. Not always.

Suppose,

x = 1
y=2
z=3

1 + 2+ 3 = 6. and 3*2*1 = 6.

case 2:

x = 10
y=1
z = 1

x + y+ z = 10 + 1 + 1 = 12 and 10*1*1= 10, which is not a multiple of 6.

Thus statement 1 is NOT sufficient.

Statement 2: x , y , z are consecutive integers.

the product of 3 consecutive integers is a multiple of 6. all time. Sufficient.

1*2*3 6

2*3*4 = 24

3*4*5 = 60

So , this statement is SUFFICIENT .

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Re: If x, y, z are integers, is xyz a multiple of 6?  [#permalink]

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21 Sep 2018, 22:36
2
I thought consecutive integers include negatives too. In that case -1, 0 and 1 are also a set of three consecutive integers.
And -1*0*1 is not a multiple of 6.
Product of any three "positive consecutive integers" are. In absence of the term "positive", B should not be the OA.

OA should be C.
Please correct if my understanding is wrong.
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Re: If x, y, z are integers, is xyz a multiple of 6?  [#permalink]

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22 Sep 2018, 02:14
1
[quote="urvashis09"]I thought consecutive integers include negatives too. In that case -1, 0 and 1 are also a set of three consecutive integers.
And -1*0*1 is not a multiple of 6.
Product of any three "positive consecutive integers" are. In absence of the term "positive", B should not be the OA.

OA should be C.

0 is a multiple of every other integer. I your example -1*0*1 is 0.
And 0 is a multiple of 6.
So OA is B.
Hope its clear.
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Re: If x, y, z are integers, is xyz a multiple of 6?  [#permalink]

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22 Sep 2018, 02:38
MathRevolution wrote:
[Math Revolution GMAT math practice question]

If $$x, y, z$$ are integers, is $$xyz$$ a multiple of $$6$$?

1) $$x+y+z$$ is a multiple of $$6$$
2) $$x, y$$, and $$z$$ are consecutive integers

Statement I:

Consider, x,y,z,= 1,1,-8. Not a multiple of 6.

Statement II:

As its a consecutive number, it will be divisible by 6.
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Re: If x, y, z are integers, is xyz a multiple of 6?  [#permalink]

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22 Sep 2018, 04:50
rahul16singh28 wrote:
MathRevolution wrote:
[Math Revolution GMAT math practice question]

If $$x, y, z$$ are integers, is $$xyz$$ a multiple of $$6$$?

1) $$x+y+z$$ is a multiple of $$6$$
2) $$x, y$$, and $$z$$ are consecutive integers

Statement I:

Consider, x,y,z,= 1,1,-8. Not a multiple of 6.

Statement II:

As its a consecutive number, it will be divisible by 6.

Oh, correct! I missed that part. Thank you for pointing the flaw.
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Re: If x, y, z are integers, is xyz a multiple of 6?  [#permalink]

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24 Sep 2018, 04:21
=>

Forget conventional ways of solving math questions. For DS problems, the VA (Variable Approach) method is the quickest and easiest way to find the answer without actually solving the problem. Remember that equal numbers of variables and independent equations ensure a solution.

Since we have 3 variables (x, y and z) and 0 equations, E is most likely to be the answer. So, we should consider conditions 1) & 2) together first. After comparing the number of variables and the number of equations, we can save time by considering conditions 1) & 2) together first.

Conditions 1) & 2)
Since x and y are two consecutive integers, one of them, x or y is an even integer, and xy is a multiple of 2.
Since x, y and z are three consecutive integers, one of them, x, y or z is a multiple of 3, and xyz is a multiple of 3.
Therefore, xyz is a multiple of 6.
Both conditions (together) are sufficient.

Since this question is an integer question (one of the key question areas), CMT (Common Mistake Type) 4(A) of the VA (Variable Approach) method tells us that we should also check answers A and B.

Condition 1)
If x = 1, y = 2 and z = 3, then xyz = 6 is not a multiple of 6.
If x = 2, y = 2 and z = 2, then xyz = 8 is a multiple of 8.
Since we do not have a unique answer, condition 1) is not sufficient.

Condition 2)
Using the same argument as the one given for both conditions together, condition 2) is sufficient.

In cases where 3 or more additional equations are required, such as for original conditions with “3 variables”, or “4 variables and 1 equation”, or “5 variables and 2 equations”, conditions 1) and 2) usually supply only one additional equation. Therefore, there is an 80% chance that E is the answer, a 15% chance that C is the answer, and a 5% chance that the answer is A, B or D. Since E (i.e. conditions 1) & 2) are NOT sufficient, when taken together) is most likely to be the answer, it is generally most efficient to begin by checking the sufficiency of conditions 1) and 2), when taken together. Obviously, there may be occasions on which the answer is A, B, C or D.

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Re: If x, y, z are integers, is xyz a multiple of 6? &nbs [#permalink] 24 Sep 2018, 04:21
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