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# If x > y > z, is xz positive? (1) xy < 0 (2) yz

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VP
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If x > y > z, is xz positive? (1) xy < 0 (2) yz [#permalink]

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21 Apr 2005, 16:01
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If x > y > z, is xz positive?

(1) xy < 0
(2) yz > 0
VP
Joined: 18 Nov 2004
Posts: 1436
Followers: 2

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21 Apr 2005, 16:05
"D".....ans is NO in both cases.

state 1...y < 0 and x > 0.....so xz <0

state 2....y > 0 and z < 0...so xz < 0
Intern
Joined: 15 Feb 2005
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21 Apr 2005, 17:26
I get answer as A.

From 1) y < 0 and x > 0 therefore xz <0. Satisfied

From 2) yz > 0. This means both (y>0 & z>0) or (y<0 & z<0)

If (y>0 & z>0), then x>0 and xz>0

But if (y<0 & z<0), then x could be +ve or -ve. Therefore xz could be +ve or -ve. Hence not satisfied.
VP
Joined: 30 Sep 2004
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21 Apr 2005, 23:48
A)...

1) x is +ve and y is -ve for the statement to be true. while x must be +ve z must be -ve for y to be greater that z => xz is NOT positive => suff

2) yz can be both -ve or +ve. x can be +ve or -ve => insuff
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Current Student
Joined: 28 Dec 2004
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22 Apr 2005, 06:38
A for me!
how do you guys get D?

1) xy<0

which means y<0 and x>0 (problem stem says X>Y>Z)!

therefore XZ<0 ....suff!

2) YZ>0

well Y and Z can both be positive...or Y and Z are both negative!
we dont know anything about X? insuff....

A it is...
VP
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25 Apr 2005, 20:02
A too , a little late...

in statement 2, z can be +ive or -ive
whereas in statement 1 we know that x is +ive and z -ive, so xz<0
VP
Joined: 25 Nov 2004
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27 Apr 2005, 17:59
Antmavel wrote:
A too , a little late...

hmmm ........little or 3 days?
27 Apr 2005, 17:59
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# If x > y > z, is xz positive? (1) xy < 0 (2) yz

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