GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

It is currently 18 Jan 2020, 11:21

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

Find Similar Topics 
Math Expert
User avatar
V
Joined: 02 Sep 2009
Posts: 60473
If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is  [#permalink]

Show Tags

New post 06 Dec 2019, 03:05
00:00
A
B
C
D
E

Difficulty:

  45% (medium)

Question Stats:

59% (01:27) correct 41% (01:48) wrong based on 54 sessions

HideShow timer Statistics

Director
Director
avatar
D
Joined: 30 Sep 2017
Posts: 571
GMAT 1: 720 Q49 V40
GPA: 3.8
Premium Member Reviews Badge
Re: If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is  [#permalink]

Show Tags

New post 06 Dec 2019, 03:36
1
xy ≠ 0

x.12^(1/2) + y.51^(1/2)
=3^(1/2) * [2x +y.17^(1/2)]
= z^(1/2) * [2x +y.17^(1/2)]

Z=3

Final answer is (C)

Posted from my mobile device
VP
VP
avatar
P
Joined: 24 Nov 2016
Posts: 1069
Location: United States
CAT Tests
Re: If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is  [#permalink]

Show Tags

New post 06 Dec 2019, 04:47
1
Quote:
If xy≠0 and x√12 + y√51 = √z(2x +y√17), what is the value of z?

A. √3
B. 2
C. 3
D. √5
E. 7


x√12 + y√51 = √z(2x +y√17)
x√(4*3) + y√(3*17) = √z(2x +y√17)
√3(2x+y√17)=√z(2x +y√17)
√3=√z, z=3

Ans (C)
Director
Director
avatar
P
Joined: 18 May 2019
Posts: 646
GMAT ToolKit User Premium Member CAT Tests
Re: If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is  [#permalink]

Show Tags

New post 06 Dec 2019, 08:41
1
We are given than xy≠0 and that x√12+y√51 = √z(2x+y√17). We are to find z.
Simplifying the RHS: x√12+y√51 = 2x√3+y√3*√17 = √3(2x+√17)
Now, equating LHS to RHS: √3(2x+√17)=√z(2x+y√17)
√3=√z
Hence z=3.

The answer is therefore C.
Senior Manager
Senior Manager
avatar
P
Joined: 25 Jul 2018
Posts: 465
Re: If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is  [#permalink]

Show Tags

New post 06 Dec 2019, 18:43
1
If x*y ≠0 and x√12 +y√51= √z*(2x+y√17), what is the value of z?

x√12 +y√51 =x√3√4+y√3√17 =2x√3+y√3√17 =√3(2x+y√17)

--> √3(2x+y√17) =√z*(2x+y√17)
x*y ≠0--> we can simplify that --> √z=√3 --> z=3

The answer is C.
GMAT Club Legend
GMAT Club Legend
User avatar
V
Joined: 18 Aug 2017
Posts: 5693
Location: India
Concentration: Sustainability, Marketing
GPA: 4
WE: Marketing (Energy and Utilities)
GMAT ToolKit User Premium Member
If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is  [#permalink]

Show Tags

New post Updated on: 09 Dec 2019, 00:39
we can solve LHS and RHS
x√12+y√51=√z(2x+y√17)
x√3*4+y√3*17 = √z(2x+y√17)
√3(2x+√17) = √z(2x+√17)
√z=√3
z=3
IMO C


If xy≠0xy≠0 and x12‾‾‾√+y51‾‾‾√=z√(2x+y17‾‾‾√)x12+y51=z(2x+y17), what is the value of z?

A. 3‾√3
B. 2
C. 3
D. 5‾√5
E. 7

Originally posted by Archit3110 on 07 Dec 2019, 02:48.
Last edited by Archit3110 on 09 Dec 2019, 00:39, edited 1 time in total.
Senior Manager
Senior Manager
avatar
P
Joined: 01 Mar 2019
Posts: 389
Location: India
Concentration: Strategy, Social Entrepreneurship
Schools: Ross '22, ISB '20, NUS '20
GPA: 4
Reviews Badge
Re: If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is  [#permalink]

Show Tags

New post 07 Dec 2019, 17:58
1
√3 can be taken common from above equation

x√12+y√51=x√4.√3+y√3.√17=√3(2x+y√17)


So z=3

OA:C

Posted from my mobile device
Intern
Intern
avatar
B
Joined: 21 Nov 2019
Posts: 1
Re: If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is  [#permalink]

Show Tags

New post 10 Dec 2019, 09:47
If x√12+y√51= 2x√7 + √7*y√17 = x√4z + y√(17z)
Then x√12+y√51=x√4z + y√(17z)
By deduction 4z = 12 or 17z= 51, therefore z=3.
GMAT Club Bot
Re: If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is   [#permalink] 10 Dec 2019, 09:47
Display posts from previous: Sort by

If xy ≠ 0 and x12^(1/2) + y51^(1/2) = z^(1/2)(2x +y 17^(1/2)), what is

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  





Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne