If xy=1, what is the value of / ? A)2 B)4 C)8 D)16 E)32 Is : Quant Question Archive [LOCKED]
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# If xy=1, what is the value of / ? A)2 B)4 C)8 D)16 E)32 Is

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If xy=1, what is the value of / ? A)2 B)4 C)8 D)16 E)32 Is [#permalink]

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29 May 2008, 10:56
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

If xy=1, what is the value of [2(x+y)^2]/[2(x-y)^2]?

A)2
B)4
C)8
D)16
E)32

Is integer x positive ?

1) x > x^3
2) x < x^2

If p,q,r are even numbers such that 2<p<q<r
what is the value of q ?
1) r<10
2)p<6
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Joined: 30 Apr 2008
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Schools: Hard Knocks
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29 May 2008, 11:31
Do you mean it to be this...

$$\frac{2(x+y)^2}{2(x-y)^2}$$

If so, that would become

$$\frac{2(x^2 + 2xy + y^2)}{2(x^2 - 2xy + y^2)}$$

$$\frac{2x^2 + 4xy + 2y^2}{2x^2 - 4xy + 2y^2}$$

If xy=1, then...

$$\frac{2x^2 + 4 + 2y^2}{2x^2 - 4 + 2y^2}$$

From this, if I did it right, none of the answer choices fit.

Extremepbs wrote:
If xy=1, what is the value of [2(x+y)^2]/[2(x-y)^2]?

A)2
B)4
C)8
D)16
E)32

Is integer x positive ?

1) x > x^3
2) x < x^2

If p,q,r are even numbers such that 2<p<q<r
what is the value of q ?
1) r<10
2)p<6

_________________

------------------------------------
J Allen Morris
**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$. GMAT Club Premium Membership - big benefits and savings SVP Joined: 08 Nov 2006 Posts: 1559 Location: Ann Arbor Schools: Ross '10 Followers: 14 Kudos [?]: 191 [0], given: 1 Re: GMAT Trap Ques - Please HELP! [#permalink] ### Show Tags 29 May 2008, 13:01 I think the question is $${{2}^{{(x+y)}^{2}}}/{2}^{{(x-y)}^{2}}$$ If you expand the exponents and reduce the expression, it will become $${2}^{4xy}$$ if xy=1, then the expression then becomes $${2}^{4}$$. The answer is 16. SVP Joined: 30 Apr 2008 Posts: 1887 Location: Oklahoma City Schools: Hard Knocks Followers: 40 Kudos [?]: 580 [0], given: 32 Re: GMAT Trap Ques - Please HELP! [#permalink] ### Show Tags 29 May 2008, 13:06 That makes sense because when you have the same base (i.e., $$\frac{2^4}{2^3} = 2^1 = 2$$), you subtract the denominator's exponent from the numerator's exponent. ncprasad wrote: I think the question is $${{2}^{{(x+y)}^{2}}}/{2}^{{(x-y)}^{2}}$$ If you expand the exponents and reduce the expression, it will become $${2}^{4xy}$$ if xy=1, then the expression then becomes $${2}^{4}$$. The answer is 16. _________________ ------------------------------------ J Allen Morris **I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

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29 May 2008, 15:39
I think the question is

$${{2}^{{(x+y)}^{2}}}/{2}^{{(x-y)}^{2}}$$

If you expand the exponents and reduce the expression, it will become $${2}^{4xy}$$

if xy=1, then the expression then becomes $${2}^{4}$$. The answer is 16.

i too get 2^4... assuming thats what the question asks..
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