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If xy = 2, xz = 8, and yz = 5, then the value of xyz is

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Intern
Joined: 22 Mar 2013
Posts: 11
If xy = 2, xz = 8, and yz = 5, then the value of xyz is [#permalink]

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27 Jun 2013, 14:12
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If xy = 2, xz = 8, and yz = 5, then the value of xyz is closest to:

A. 5
B. 9
C. 15
D. 25
E. 75

My question is, why are there not two solutions to the problem?
I see that (x^2)(y^2)(z^2) = 80.

[Reveal] Spoiler: OA

Last edited by Bunuel on 27 Jun 2013, 14:22, edited 3 times in total.
Edited the question and moved to PS forum.
Math Expert
Joined: 02 Sep 2009
Posts: 39723
Re: If xy = 2 , xz = 8 , and yz = 5, then the value of xyz is [#permalink]

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27 Jun 2013, 14:26
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Expert's post
tmipanthers wrote:
If xy = 2, xz = 8, and yz = 5, then the value of xyz is closest to:

A. 5
B. 9
C. 15
D. 25
E. 75

My question is, why are there not two solutions to the problem?
I see that (x^2)(y^2)(z^2) = 80.

You are not making any error, xyz CAN be $$\sqrt{80}$$ as well as $$-\sqrt{80}$$.
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Re: If xy = 2 , xz = 8 , and yz = 5, then the value of xyz is   [#permalink] 27 Jun 2013, 14:26
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