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# If xy < 5, is x < 1 ? (1) | y | > 5 (2) x / y > 0

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If xy < 5, is x < 1 ? (1) | y | > 5 (2) x / y > 0 [#permalink]

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07 Feb 2012, 16:36
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If xy < 5, is x < 1 ?

(1) |y| > 5
(2) x/y > 0
[Reveal] Spoiler: OA

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Re: is x < 1 ? [#permalink]

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07 Feb 2012, 16:49
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If xy < 5, is x < 1 ?

(1) |y| > 5 --> if y=10 and x=0 then the answer is YES but if y=-10 and x=2 then the answer is NO. Not sufficient.

(2) x/y > 0 --> x and y have the same sign. Still insufficient: if y=-2 and x=-1 then the answer is YES but if y=2 and x=2 then the answer is NO.

(1)+(2) From (2) x and y have the same sign. Now, if from (1) y>5 then 0<x<1 (in order xy<5 to hold true) and if from (1) y<-5 then -1<x<0 (again in order xy<5 to hold true). So in both cases x<1. Sufficient.

Answer: C.
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Re: If xy < 5, is x < 1 ? (1) | y | > 5 (2) x / y > 0 [#permalink]

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29 Mar 2017, 05:43
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Re: If xy < 5, is x < 1 ? (1) | y | > 5 (2) x / y > 0   [#permalink] 29 Mar 2017, 05:43
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# If xy < 5, is x < 1 ? (1) | y | > 5 (2) x / y > 0

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