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# If xy=z and (x+33)(y-29)=z, then what x and y?

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Intern
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If xy=z and (x+33)(y-29)=z, then what x and y? [#permalink]

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29 Mar 2013, 23:46
The solution of the above escapes me, as I know the answer, but I would like to know howg to solve it.

Regards Jan
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Re: If xy=z and (x+33)(y-29)=z, then what x and y? [#permalink]

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30 Mar 2013, 02:24
The 'z' is of no conseque, but there should be two solutions, one being x and y are two real numbers.
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Re: If xy=z and (x+33)(y-29)=z, then what x and y? [#permalink]

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30 Mar 2013, 05:21
Sorry for my ambiguity. Z is just the same product of these equations. I have been told, that there to solutions, one of which are two real numbers e.g 5 and 8.
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Re: If xy=z and (x+33)(y-29)=z, then what x and y? [#permalink]

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01 Apr 2013, 12:52
this is like bull in a china shop.. running everywhere? not gmat like!
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Re: If xy=z and (x+33)(y-29)=z, then what x and y? [#permalink]

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02 Apr 2013, 06:18
jjwho wrote:
The solution of the above escapes me, as I know the answer, but I would like to know howg to solve it.

Regards Jan

$$xy = (x + 33)(y - 29)$$ = > $$33y - 29x = 29.33$$. It is a line and will have infinite solutions.
Re: If xy=z and (x+33)(y-29)=z, then what x and y?   [#permalink] 02 Apr 2013, 06:18
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