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# If xyz>0, is x(y)^(2z)^3>0 1) y>0 2) x>0

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VP
Joined: 29 Dec 2005
Posts: 1337

Kudos [?]: 69 [0], given: 0

If xyz>0, is x(y)^(2z)^3>0 1) y>0 2) x>0 [#permalink]

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27 Apr 2006, 20:21
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If xyz>0, is x(y)^(2z)^3>0

1) y>0
2) x>0

Kudos [?]: 69 [0], given: 0

Manager
Joined: 21 Mar 2006
Posts: 89

Kudos [?]: 2 [0], given: 0

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27 Apr 2006, 20:31
I would say B, not totally certain though.

wouldn't x(y)^(2z)^3>0 = x(y)^6z>0. Therefore y will always be positive. It is X that we are uncertain about. Since B tells us that X is positive it answers yes to the equation.

Kudos [?]: 2 [0], given: 0

27 Apr 2006, 20:31
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# If xyz>0, is x(y)^(2z)^3>0 1) y>0 2) x>0

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