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# If y = ( x^2 - y^2)/(x-y) where x not equal to y, then what

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Director
Joined: 11 Jun 2007
Posts: 639

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If y = ( x^2 - y^2)/(x-y) where x not equal to y, then what [#permalink]

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21 Nov 2007, 12:32
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If y = ( x^2 - y^2)/(x-y) where x not equal to y, then what is the value of y ?

(1) x + y = 3
(2) x - y = 2

Kudos [?]: 409 [0], given: 0

Director
Joined: 11 Jun 2007
Posts: 639

Kudos [?]: 409 [0], given: 0

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21 Nov 2007, 13:07
young_gun wrote:
A, y=3?

I chose A but OA is different.

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CEO
Joined: 17 Nov 2007
Posts: 3585

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Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

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21 Nov 2007, 14:00
D

y = ( x^2 - y^2)/(x-y)=(x+y)(x-y)/(x-y)=x+y ==> x=0; for any y.

1. x + y = 3 ==> y=3 suff
2. x - y = 2 ==> y=-2 suff

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Current Student
Joined: 28 Dec 2004
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Location: New York City
Schools: Wharton'11 HBS'12

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21 Nov 2007, 14:08
I believe the OA is wrong then..

(x-y)(x+y)/(x-y)=y

y=x+y

x+y=3

y=3

sufficient

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Director
Joined: 11 Jun 2007
Posts: 639

Kudos [?]: 409 [0], given: 0

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21 Nov 2007, 16:55
Can someone look at this problem? This is from GMATClub Challenges
http://gmatclub.com/tests/m/02/#q25

Also, is it possible for the variable y to have two different values for 2 cases?

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Director
Joined: 08 Jun 2007
Posts: 575

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21 Nov 2007, 17:27
eyunni wrote:
Can someone look at this problem? This is from GMATClub Challenges
http://gmatclub.com/tests/m/02/#q25

Also, is it possible for the variable y to have two different values for 2 cases?

yes it is possible that you may end up with different values for 2 cases.

In this case it should be D.

1) y = x + y = 3

2) y = x + y => x - y + y = 0 => y = -2

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Manager
Joined: 03 Sep 2006
Posts: 233

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21 Nov 2007, 19:41
Late, but D.
Agree with walker (same approach)

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21 Nov 2007, 19:41
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