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Re: If Y < X and XM < YM, what must be true? [#permalink]
Bunuel wrote:
If Y < X and XM < YM, what must be true?

A. M < X.
B. M < Y.
C. X < 0.
D. M < 0.
E. Y < 0.

Case 1
M>0
then X<Y
Case 2
M<0
X>Y
ATQ Y<X
we have case 2
so M<0
Ans D
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Re: If Y < X and XM < YM, what must be true? [#permalink]
Expert Reply
Bunuel wrote:
If Y < X and XM < YM, what must be true?

A. M < X.
B. M < Y.
C. X < 0.
D. M < 0.
E. Y < 0.


We see that when X and Y are multiplied by M, the inequality is switched. That means M must be less than zero.

For example, if X = 2, and Y = -3, and M = -1, we have:

-2 > -3

(2)(-1) < (-3)(-1)

2 < 3

Answer: D
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Re: If Y < X and XM < YM, what must be true? [#permalink]
Expert Reply
Given: Y < X

Multiply 'M' on both sides: MY < MX, but it is given that MY > MX. This is possible when we multiply (-M) as it will flip the inequality.

Hence, M < 0

Answer D
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Re: If Y < X and XM < YM, what must be true? [#permalink]
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