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# If (Z-3)^2 = 12,then 2z(z-6)=

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If (Z-3)^2 = 12,then 2z(z-6)=  [#permalink]

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05 Feb 2020, 07:15
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79% (02:07) correct 21% (02:16) wrong based on 39 sessions

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If $$(Z-3)^2 = 12$$,then $$2z(z-6)=$$

A. 6

B. 9

C. 10

D. 15

E. 27

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Director
Joined: 14 Dec 2019
Posts: 506
Location: Poland
GMAT 1: 570 Q41 V27
WE: Engineering (Consumer Electronics)
Re: If (Z-3)^2 = 12,then 2z(z-6)=  [#permalink]

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05 Feb 2020, 07:22
1
If $$(Z−3)^2=12$$, then $$2z(z−6)=$$?

A. 6

B. 9

C. 10

D. 15

E. 27

$$(Z−3)^2=12$$ -> $$Z^2 -6Z + 9 = 12$$ -> $$Z^2 = 6Z + 3$$ -> $$2z^2 - 12Z = 12Z + 6 -12Z = 6$$

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Re: If (Z-3)^2 = 12,then 2z(z-6)=  [#permalink]

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09 Feb 2020, 04:20
If $$(Z-3)^2 = 12$$,then $$2z(z-6)=$$

A. 6

B. 9

C. 10

D. 15

E. 27

Foiling the given equation, we have:

Z^2 - 6Z + 9 = 12

Z^2 - 6Z - 3 = 0

Z^2 - 6Z = 3

Z(Z - 6) = 3

So 2 * Z(Z - 6) = 2 * 3 = 6.

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Re: If (Z-3)^2 = 12,then 2z(z-6)=   [#permalink] 09 Feb 2020, 04:20
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# If (Z-3)^2 = 12,then 2z(z-6)=

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