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If z is an integer, is z even?

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If z is an integer, is z even? [#permalink]

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New post Updated on: 15 Feb 2014, 03:19
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If z is an integer, is z even?

(1) z/2 is not an odd integer.

(2) z + 5 is an odd integer.
[Reveal] Spoiler: OA

Originally posted by bschool83 on 24 Jul 2011, 15:49.
Last edited by Bunuel on 15 Feb 2014, 03:19, edited 3 times in total.
Renamed the topic and edited the question.
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Re: DS - 700 level - even integer [#permalink]

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New post 24 Jul 2011, 20:09
bschool83 wrote:
If z is an integer, is z even?

(1) is not an odd integer.

(2) z + 5 is an odd integer.

I assume statement 1 says that "\(z\) is not an odd integer."

Statement 1) If \(z\) is NOT an odd integer, but \(z\) is an integer, \(z\) must be an even integer. All integers are either odd or even, including \(0\). Sufficient.

Statement 2) \(z + odd = odd\), so \(z\) must be even. If \(z\) were odd, then \(z + odd\) would equal an even number. \(O + O = E\) and \(E + O = O\). Sufficient.

[Reveal] Spoiler:
D
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Re: DS - 700 level - even integer [#permalink]

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New post 24 Jul 2011, 20:16
Ans D. Since from stmt 1, if Z is an integer and not odd then the possible values are 0 or any even integer . Suff

From Stmt 2: Even Int + 5 = odd Integer. Hence Suff
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Re: DS - 700 level - even integer [#permalink]

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New post 26 Jul 2011, 02:02
bschool83. If you dont mind, please make sure to mark level of the question in a right way.
This is not a 700 level question.

Thank you.
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Re: DS - 700 level - even integer [#permalink]

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New post 26 Jul 2011, 05:06
Is this really a 700 level question ?
The answer is clearly D
If it's not odd then it's even, hence statement 1 sufficient
Statement 2 is also sufficient because as we try combinations only an even number with an odd number yields an odd number and there is no restriction on positive or negative even. Thanks

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Re: DS - 700 level - even integer [#permalink]

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New post 26 Jul 2011, 08:20
Both are suffcient .D is answer
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Re: DS - 700 level - even integer [#permalink]

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New post 26 Jul 2011, 13:22
fluke wrote:
bschool83 wrote:
If z is an integer, is z even?

(1) is not an odd integer.

(2) z + 5 is an odd integer.


Please complete statement 1.


(1) z/2 is not an odd integer
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Re: DS - 700 level - even integer [#permalink]

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New post 26 Jul 2011, 18:16
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Agree with Fluke..

Z/2 is not an odd integer..we cannot assume that it is an integer in the first place!

Ans B...

If thats the catch, then it should be a 700 level question..
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Re: DS - 700 level - even integer [#permalink]

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New post 26 Jul 2011, 23:45
official ans plz ?

from what i solved ... assuming z/2 is an integer ... answer should be "d"
but ... if z/2 belongs to real numbers (including decimals) then it should be "b" as suggested by fluke
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Re: If z is an integer, is z even? (1) z/2 is not an odd [#permalink]

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bschool83 wrote:
If z is an integer, is z even?

(1) z/2 is not an odd integer.

(2) z + 5 is an odd integer.


1) z/2 =1.5 then Z= 3,Z is odd, ans is No, if Z/2 =2 then z= 4, z is even , ans is yes
insufficient.

2)z + 5 is an odd integer --> then z must be even
sufficient

Answer B
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Re: If z is an integer, is z even? [#permalink]

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New post 21 Jun 2016, 00:12
I think answer is E. because in second case for z=0 , z+5 is odd is also valid.
But for z=0 , z is not an even integer.
Please correct me
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Re: If z is an integer, is z even? [#permalink]

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New post 21 Jun 2016, 00:23
This question is really good question.
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Re: If z is an integer, is z even? [#permalink]

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New post 21 Jun 2016, 06:52
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B

if z=27
1)z/2=13.5 so it neither odd(nor even nor an INTEGER)not suff
2)suff(given z is an integer
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Re: If z is an integer, is z even? [#permalink]

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New post 01 Jan 2017, 12:03
Here is my solution to this one ->

We need the even odd nature of integer z

Statement 1->
z=5
z=4

Taking these two test cases we can say that this is an insufficient statement

Statement 2->
z-odd=odd => z=> odd+odd=even
Hence sufficient

Hence B

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Re: If z is an integer, is z even? [#permalink]

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New post 19 Mar 2018, 22:06
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Re: If z is an integer, is z even?   [#permalink] 19 Mar 2018, 22:06
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