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If z is an integer, is z even?

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If z is an integer, is z even?  [#permalink]

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Updated on: 15 Feb 2014, 03:19
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53% (01:02) correct 47% (00:59) wrong based on 195 sessions

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If z is an integer, is z even?

(1) z/2 is not an odd integer.

(2) z + 5 is an odd integer.

Originally posted by bschool83 on 24 Jul 2011, 15:49.
Last edited by Bunuel on 15 Feb 2014, 03:19, edited 3 times in total.
Renamed the topic and edited the question.
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Re: DS - 700 level - even integer  [#permalink]

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24 Jul 2011, 20:09
bschool83 wrote:
If z is an integer, is z even?

(1) is not an odd integer.

(2) z + 5 is an odd integer.

I assume statement 1 says that "$$z$$ is not an odd integer."

Statement 1) If $$z$$ is NOT an odd integer, but $$z$$ is an integer, $$z$$ must be an even integer. All integers are either odd or even, including $$0$$. Sufficient.

Statement 2) $$z + odd = odd$$, so $$z$$ must be even. If $$z$$ were odd, then $$z + odd$$ would equal an even number. $$O + O = E$$ and $$E + O = O$$. Sufficient.

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Re: DS - 700 level - even integer  [#permalink]

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24 Jul 2011, 20:16
Ans D. Since from stmt 1, if Z is an integer and not odd then the possible values are 0 or any even integer . Suff

From Stmt 2: Even Int + 5 = odd Integer. Hence Suff
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Re: DS - 700 level - even integer  [#permalink]

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26 Jul 2011, 02:02
bschool83. If you dont mind, please make sure to mark level of the question in a right way.
This is not a 700 level question.

Thank you.
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Re: DS - 700 level - even integer  [#permalink]

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26 Jul 2011, 05:06
Is this really a 700 level question ?
If it's not odd then it's even, hence statement 1 sufficient
Statement 2 is also sufficient because as we try combinations only an even number with an odd number yields an odd number and there is no restriction on positive or negative even. Thanks

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Re: DS - 700 level - even integer  [#permalink]

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26 Jul 2011, 08:20
Both are suffcient .D is answer
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Re: DS - 700 level - even integer  [#permalink]

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26 Jul 2011, 13:22
fluke wrote:
bschool83 wrote:
If z is an integer, is z even?

(1) is not an odd integer.

(2) z + 5 is an odd integer.

(1) z/2 is not an odd integer
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Re: DS - 700 level - even integer  [#permalink]

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26 Jul 2011, 18:16
1
Agree with Fluke..

Z/2 is not an odd integer..we cannot assume that it is an integer in the first place!

Ans B...

If thats the catch, then it should be a 700 level question..
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Re: DS - 700 level - even integer  [#permalink]

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26 Jul 2011, 23:45
official ans plz ?

from what i solved ... assuming z/2 is an integer ... answer should be "d"
but ... if z/2 belongs to real numbers (including decimals) then it should be "b" as suggested by fluke
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Re: If z is an integer, is z even? (1) z/2 is not an odd  [#permalink]

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15 Feb 2014, 01:01
2
bschool83 wrote:
If z is an integer, is z even?

(1) z/2 is not an odd integer.

(2) z + 5 is an odd integer.

1) z/2 =1.5 then Z= 3,Z is odd, ans is No, if Z/2 =2 then z= 4, z is even , ans is yes
insufficient.

2)z + 5 is an odd integer --> then z must be even
sufficient

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Re: If z is an integer, is z even?  [#permalink]

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21 Jun 2016, 00:12
I think answer is E. because in second case for z=0 , z+5 is odd is also valid.
But for z=0 , z is not an even integer.
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Re: If z is an integer, is z even?  [#permalink]

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21 Jun 2016, 00:23
This question is really good question.
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Re: If z is an integer, is z even?  [#permalink]

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21 Jun 2016, 06:52
1
B

if z=27
1)z/2=13.5 so it neither odd(nor even nor an INTEGER)not suff
2)suff(given z is an integer
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Re: If z is an integer, is z even?  [#permalink]

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01 Jan 2017, 12:03
Here is my solution to this one ->

We need the even odd nature of integer z

Statement 1->
z=5
z=4

Taking these two test cases we can say that this is an insufficient statement

Statement 2->
z-odd=odd => z=> odd+odd=even
Hence sufficient

Hence B

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Re: If z is an integer, is z even?  [#permalink]

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12 Apr 2019, 13:24
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Re: If z is an integer, is z even?   [#permalink] 12 Apr 2019, 13:24
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