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# In a battle 70% of the combatants lost an eye, 80% an ear,

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Manager
Joined: 01 Nov 2007
Posts: 103

Kudos [?]: 78 [1], given: 0

In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink]

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19 Mar 2008, 23:59
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In a battle 70% of the combatants lost an eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. The minimum value of x is?

Kudos [?]: 78 [1], given: 0

Manager
Joined: 02 Mar 2008
Posts: 205

Kudos [?]: 53 [0], given: 1

Concentration: Finance, Strategy

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20 Mar 2008, 00:53
85%
leg is subset of 4 limbs ( i suppose ^^). So those lost 4 limbs sure lost leg

Kudos [?]: 53 [0], given: 1

CEO
Joined: 17 Nov 2007
Posts: 3583

Kudos [?]: 4663 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

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20 Mar 2008, 01:15
az780 wrote:
In a battle 70% of the combatants lost an eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. The minimum value of x is?

terrible
it is a strange question...
So, 70% an eye, 80% an ear, 75% an arm, 85% a leg.

1. an eye and and an ear: p=[50%,70%]
2. (an eye and and an ear) and an arm: p=[25%,70%]
3. ((an eye and and an ear) and an arm) and a leg: p=[10%,70%]

Therefore, min: 10%, max: 70%
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Kudos [?]: 4663 [0], given: 360

SVP
Joined: 04 May 2006
Posts: 1878

Kudos [?]: 1443 [0], given: 1

Schools: CBS, Kellogg

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20 Mar 2008, 02:15
walker wrote:
az780 wrote:
In a battle 70% of the combatants lost an eye, 80% an ear, 75% an arm, 85% a leg, x% lost all four limbs. The minimum value of x is?

terrible
it is a strange question...
So, 70% an eye, 80% an ear, 75% an arm, 85% a leg.

1. an eye and and an ear: p=[50%,70%]
2. (an eye and and an ear) and an arm: p=[25%,70%]
3. ((an eye and and an ear) and an arm) and a leg: p=[10%,70%]

Therefore, min: 10%, max: 70%

This is really funny problem. I can not stand when I read it.
Anyway, Walker! I try to but can not follow your logic! Sets always make me confused! Please give me some detail. Your approach strange also
_________________

Kudos [?]: 1443 [0], given: 1

CEO
Joined: 17 Nov 2007
Posts: 3583

Kudos [?]: 4663 [0], given: 360

Concentration: Entrepreneurship, Other
Schools: Chicago (Booth) - Class of 2011
GMAT 1: 750 Q50 V40

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20 Mar 2008, 02:39
sondenso wrote:
This is really funny problem. I can not stand when I read it.
Anyway, Walker! I try to but can not follow your logic! Sets always make me confused! Please give me some detail. Your approach strange also

1. Let we have two attributes: A and B.
2. Let a% of people have A and b% of people have B.
3. we will try to find max and min ab% (the percentage of people that have two attributes)

I'll try to draw:

the maximum configuration:
|aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100%
|bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb--------------| 100%
max=min(a,b)

the minimum configuration:
|aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100%
|---------------bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb| 100%
min=b-(100-a)=a+b-100. if min<0 then min have to be 0

for example, a=75%, b=87%

max=min(75%,87%)=75%
min=87%-(100%-75%)=62%
_________________

HOT! GMAT TOOLKIT 2 (iOS) / GMAT TOOLKIT (Android) - The OFFICIAL GMAT CLUB PREP APP, a must-have app especially if you aim at 700+ | PrepGame

Kudos [?]: 4663 [0], given: 360

SVP
Joined: 04 May 2006
Posts: 1878

Kudos [?]: 1443 [0], given: 1

Schools: CBS, Kellogg

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20 Mar 2008, 19:34
walker wrote:
sondenso wrote:
This is really funny problem. I can not stand when I read it.
Anyway, Walker! I try to but can not follow your logic! Sets always make me confused! Please give me some detail. Your approach strange also

1. Let we have two attributes: A and B.
2. Let a% of people have A and b% of people have B.
3. we will try to find max and min ab% (the percentage of people that have two attributes)

I'll try to draw:

the maximum configuration:
|aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100%
|bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb--------------| 100%
max=min(a,b)

the minimum configuration:
|aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa------------------| 100%
|---------------bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb| 100%
min=b-(100-a)=a+b-100. if min<0 then min have to be 0

for example, a=75%, b=87%

max=min(75%,87%)=75%
min=87%-(100%-75%)=62%

Thank you Walker, you are great!
_________________

Kudos [?]: 1443 [0], given: 1

Non-Human User
Joined: 09 Sep 2013
Posts: 15638

Kudos [?]: 283 [0], given: 0

Re: In a battle 70% of the combatants lost an eye, 80% an ear, [#permalink]

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06 Jul 2017, 07:39
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Kudos [?]: 283 [0], given: 0

Re: In a battle 70% of the combatants lost an eye, 80% an ear,   [#permalink] 06 Jul 2017, 07:39
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