GMAT Question of the Day: Daily via email | Daily via Instagram New to GMAT Club? Watch this Video

 It is currently 30 May 2020, 09:46

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

In a certain candy store, 22% of the customers are caught sa

Author Message
TAGS:

Hide Tags

Intern
Joined: 26 Apr 2013
Posts: 45
Location: United States
Concentration: Marketing, Nonprofit
GPA: 3.5
WE: Marketing (Telecommunications)
In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

11 Oct 2013, 01:09
1
11
00:00

Difficulty:

65% (hard)

Question Stats:

62% (02:15) correct 38% (02:03) wrong based on 185 sessions

HideShow timer Statistics

In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 12% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy?

A) 22%
B) 23%
C) 24%
D) 25%
E) 34%
Math Expert
Joined: 02 Sep 2009
Posts: 64245
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

11 Oct 2013, 01:17
4
1
tk1tez7777 wrote:
In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 12% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy?

A) 22%
B) 23%
C) 24%
D) 25%
E) 34%

Since 12% of the customers who sample the candy are not caught, then 88% of the customers who sample the candy are caught:

{% of customers who sample candy}*0.88 = 0.22;
{% of customers who sample candy} = 0.25.

_________________
General Discussion
Intern
Joined: 05 Feb 2013
Posts: 13
In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

Updated on: 02 Apr 2016, 03:51
What is the best way to calculate this question?
I tried to aproximate and i ended up with a wrong answer.

Originally posted by eladavid on 13 Oct 2013, 02:43.
Last edited by eladavid on 02 Apr 2016, 03:51, edited 1 time in total.
Math Expert
Joined: 02 Sep 2009
Posts: 64245
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

13 Oct 2013, 03:07
1
What is the best way to calculate this question?
I tried to aproximate and i ended up with a wrong answer.
only afterwords i noticed that 22 is one quarter of 88.

It's quite easy:

{% of customers who sample candy}*0.88 = 0.22 --> {% of customers who sample candy} = 22/88 = 1/4.

Hope it helps.
_________________
Manager
Joined: 18 Oct 2013
Posts: 66
Location: India
Concentration: Technology, Finance
GMAT 1: 580 Q48 V21
GMAT 2: 530 Q49 V13
GMAT 3: 590 Q49 V21
WE: Information Technology (Computer Software)
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

09 Apr 2014, 19:06
I am little bit confused in this question.Would you please elaborate the explanation more clearly.

Lets say we have 100 customer in store. 12% sample the candy but didn't caught.
So, 88% customer caught sampling the candy. I didn't get after this.

Director
Joined: 23 Jan 2013
Posts: 507
Schools: Cambridge'16
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

09 Apr 2014, 23:54
tk1tez7777 wrote:
In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 12% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy?

A) 22%
B) 23%
C) 24%
D) 25%
E) 34%

One can solve by two equations:
x-y=22
y=0.12x

we get x-0.12x=22 => 0.88x=22 => x=25
Intern
Joined: 08 Apr 2014
Posts: 11
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

10 Apr 2014, 00:23
4
vikrantgulia wrote:
I am little bit confused in this question.Would you please elaborate the explanation more clearly.

Lets say we have 100 customer in store. 12% sample the candy but didn't caught.
So, 88% customer caught sampling the candy. I didn't get after this.

Hi Vikrant,

lets say there are 100 customers in store, out of with x sample the candy
12% of this x was not caught, 88% of this x was caught

this 88% of x = 22% of the total customers (it is given that 22% of the total customers were found sampling)

so x = 22/88 = 0.25

*press Kudos if you like the post
SVP
Status: The Best Or Nothing
Joined: 27 Dec 2012
Posts: 1708
Location: India
Concentration: General Management, Technology
WE: Information Technology (Computer Software)
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

14 Apr 2014, 01:08
4
vikrantgulia wrote:
I am little bit confused in this question.Would you please elaborate the explanation more clearly.

Lets say we have 100 customer in store. 12% sample the candy but didn't caught.
So, 88% customer caught sampling the candy. I didn't get after this.

Lets say Total = 100
Sample................................... .............................. Dont Sample
x......................................................................... 100-x

$$\frac{12x}{100} =$$Not Caught, means

$$\frac{88x}{100} =$$Caught Sampling

Given that 22% of the customers are caught sampling the candy, i.e

$$\frac{88x}{100} = \frac{22}{100} * 100$$

x = 25%

Attachments

eqn.jpg [ 32.54 KiB | Viewed 5704 times ]

Manager
Status: A mind once opened never loses..!
Joined: 05 Mar 2015
Posts: 186
Location: India
MISSION : 800
WE: Design (Manufacturing)
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

23 Jun 2015, 09:34
2
Let's say the no of customers who sample candy = S

Now { 0.12 S }+ {22} = S

>> S = 25
EMPOWERgmat Instructor
Status: GMAT Assassin/Co-Founder
Affiliations: EMPOWERgmat
Joined: 19 Dec 2014
Posts: 16746
Location: United States (CA)
GMAT 1: 800 Q51 V49
GRE 1: Q170 V170
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

23 Jun 2015, 19:09
Hi All,

The presentation in this question is relatively rare on Test Day - the logic most often appears in Overlapping Sets questions (but the wording is a bit more straight-forward). The idea here is essentially about "groups within groups"...

From the prompt we know that there are 3 different types of people....

Those who do NOT sample candy
Those who SAMPLE AND are CAUGHT
Those who SAMPLE but are NOT CAUGHT

The percents that we're given refer to the latter 2 groups....we can TEST VALUES to clarify the logic:

22% of customers are caught sampling candy - this refers to 22% of ALL CUSTOMERS....

IF Total customers = 100
22%(100) = 22 customers SAMPLE AND are CAUGHT.

Next, we're told that 12% of those WHO SAMPLE are NOT CAUGHT. This is NOT 12% of everyone; it's 12% of those who SAMPLE.

TOTAL WHO SAMPLE = X = (those CAUGHT) + (those NOT CAUGHT)

X = 22 + .12(X)

From here, we can combine like terms and solve for X....

.88X = 22
X = 22/.88 = 1/.04 = 25

Thus, 25 out of the original 100 SAMPLE candy. Since that is what the question is focused on, 25% is the answer.

GMAT assassins aren't born, they're made,
Rich
_________________
Contact Rich at: Rich.C@empowergmat.com

The Course Used By GMAT Club Moderators To Earn 750+

souvik101990 Score: 760 Q50 V42 ★★★★★
ENGRTOMBA2018 Score: 750 Q49 V44 ★★★★★
Board of Directors
Joined: 17 Jul 2014
Posts: 2432
Location: United States (IL)
Concentration: Finance, Economics
GMAT 1: 650 Q49 V30
GPA: 3.92
WE: General Management (Transportation)
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

09 Mar 2016, 19:50
i used the total number of clients = 100
now..22 sampling and fined
suppose X is the number of clients who sample
0.12x are not fined.
it means that 22 = 0.88x
now..
x=22*100/88 = 25

so 25 people are sampling.
since we have 100 customers, 25 of them would represent 25%
Current Student
Joined: 08 Jun 2015
Posts: 408
Location: India
GMAT 1: 640 Q48 V29
GMAT 2: 700 Q48 V38
GPA: 3.33
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

20 May 2016, 07:14
Tricky one .. good question ... 25% it is
_________________
" The few , the fearless "
Current Student
Joined: 18 Oct 2014
Posts: 772
Location: United States
GMAT 1: 660 Q49 V31
GPA: 3.98
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

20 May 2016, 07:19
Let 100 be the total number of persons.

22 sample candy and get caught.

Let total number of persons who sample candy be x

12% (.12x) are not caught while 22 (88%) are caught
.88x= 22
x=25%
_________________
I welcome critical analysis of my post!! That will help me reach 700+
Intern
Joined: 23 Apr 2016
Posts: 16
Location: United States
Concentration: Finance, Economics
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

07 Jul 2016, 18:45
Good question. I made the mistake of sorting information too mechanically by dividing the customers into Sample/Did not sample and Caught/ Not Caught categories. I completely missed the fact that there was no one who would did not sample but got caught.. Once I saw it, I realized that the "22% of the customers are caught sampling the candy and are charged a small fine" is in fact 22% of total customers.

Because "12% of the customers who sample the candy are not caught", 88% of customers who sample are caught. That 88% is 22% of total customers, so 100% of people who sample is 22%*100%/88%= 25% of total customers.
Director
Joined: 13 Mar 2017
Posts: 717
Location: India
Concentration: General Management, Entrepreneurship
GPA: 3.8
WE: Engineering (Energy and Utilities)
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

09 Aug 2017, 06:33
tk1tez7777 wrote:
In a certain candy store, 22% of the customers are caught sampling the candy and are charged a small fine, but 12% of the customers who sample the candy are not caught. What is the total percent of all customers who sample candy?

A) 22%
B) 23%
C) 24%
D) 25%
E) 34%

22% of the overall customers are caught sampling candy and are fined.
12% of the customers who sample candy are not caught.
So, 88% of the customers who sample candy are caught.

So, total percentage of all customers of sample candy = 22/.88 = 22*100/88 = 25 %

Non-Human User
Joined: 09 Sep 2013
Posts: 15022
Re: In a certain candy store, 22% of the customers are caught sa  [#permalink]

Show Tags

09 Mar 2019, 13:22
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: In a certain candy store, 22% of the customers are caught sa   [#permalink] 09 Mar 2019, 13:22