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# in a certain city 80% of the houses have cables and 60% have VCR. what

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Manager
Joined: 16 May 2011
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Concentration: Finance, Real Estate
GMAT Date: 12-27-2011
WE: Law (Law)
in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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13 Jun 2011, 04:47
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Difficulty:

45% (medium)

Question Stats:

67% (01:48) correct 33% (01:21) wrong based on 21 sessions

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in a certain city 80% of the houses have cables and 60% have VCR. what is the range of houses that have both cables and a VCR, if there are 150,000 houses:(IN THOUSENDS)

1. 30-60
2. 30-90
3. 60-90
4. 60-150
5. 90-150

I used a table solving for NO CABLES/NO VCR=0 and then VCR/NO CABLES=0 to recieve the anser which seems correct.

is som1 can suggest a quicker method?

kind regards
[Reveal] Spoiler: OA

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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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13 Jun 2011, 04:58
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The highest range can be the # of people who have both Cables and VCR, which means 60% of people have cables, and VCR too.

So 60% of people = 60/100 * 150000 = 90000

Then again, the least overlap can be like :

80% + 60% - 100% = 40%

40% of 150000 = 40/100 * 150000 = 60000

So the range = 60000 - 90000

Attachments

Sets.png [ 12.76 KiB | Viewed 1596 times ]

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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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13 Jun 2011, 05:20
dimri10 wrote:
in a certain city 80% of the houses have cables and 60% have VCR. what is the range of houses that have both cables and a VCR, if there are 150,000 houses:(IN THOUSENDS)

1. 30-60
2. 30-90
3. 60-90
4. 60-150
5. 90-150

I used a table solving for NO CABLES/NO VCR=0 and then VCR/NO CABLES=0 to recieve the anser which seems correct.

is som1 can suggest a quicker method?

kind regards

The range is 40% - 60% hence
60k - 90K
Attachments

Set.jpg [ 22.51 KiB | Viewed 1587 times ]

Kudos [?]: 238 [0], given: 13

Manager
Joined: 16 May 2011
Posts: 203

Kudos [?]: 98 [0], given: 37

Concentration: Finance, Real Estate
GMAT Date: 12-27-2011
WE: Law (Law)
Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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13 Jun 2011, 05:33
subhashghosh wrote:
The highest range can be the # of people who have both Cables and VCR, which means 60% of people have cables, and VCR too.

So 60% of people = 60/100 * 150000 = 90000

Then again, the least overlap can be like :

80% + 60% - 100% = 40%

40% of 150000 = 40/100 * 150000 = 60000

So the range = 60000 - 90000

but in the same subject:

is there a way to deal with sets without Venn diagrams?

Kudos [?]: 98 [0], given: 37

SVP
Joined: 16 Nov 2010
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Kudos [?]: 592 [1], given: 36

Location: United States (IN)
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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13 Jun 2011, 05:37
1
KUDOS
Well, to my mind, Venn diagrams make visualization easier. I think Venn diagrams are great, you can try the how to draw Venn diagrams by Whiplash, I think it's really good stuff.

Sometimes, double matrix is also good, especially for 2 sets, but it's really based on individual comfort level.
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Formula of Life -> Achievement/Potential = k * Happiness (where k is a constant)

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Kudos [?]: 592 [1], given: 36

Manager
Joined: 16 May 2011
Posts: 203

Kudos [?]: 98 [0], given: 37

Concentration: Finance, Real Estate
GMAT Date: 12-27-2011
WE: Law (Law)
Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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13 Jun 2011, 06:14
well i tried whiplash's way. it's too long in comparison to:

150=58+88+53-both-2*all.

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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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13 Jun 2011, 23:04
40 - 60% giving 60-90.
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what [#permalink]

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06 May 2016, 10:34
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Re: in a certain city 80% of the houses have cables and 60% have VCR. what   [#permalink] 06 May 2016, 10:34
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