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# In a certain class 1/3 of students are honors 1/4 of

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Manager
Joined: 19 Jun 2003
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In a certain class 1/3 of students are honors 1/4 of [#permalink]

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24 Aug 2004, 21:22
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In a certain class 1/3 of students are honors 1/4 of students play varisity sports. If 12 students are honors and play varisty sports , what is the least number of students in class?

20

22

36

48

144

Please explain your solution..

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GMAT Club Legend
Joined: 07 Jul 2004
Posts: 5034

Kudos [?]: 437 [0], given: 0

Location: Singapore

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24 Aug 2004, 22:34
Backsolve.
Using 36, 1/3(36)=12
1/4(36)=9
Impossible, since 12 are both.

Using 48, 1/3(48) = 16
1/4(48) = 12

Possible, since we have 12 playing sports now. We are asked for least possible number, so this has to be the one, since 144 will satisfy the condition given but have an excess of students who are only playing one role.

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Senior Manager
Joined: 22 Jun 2004
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Location: Bangalore, India
Re: PS: varisty sports [#permalink]

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25 Aug 2004, 04:13
The least number comes when both the categories have the highest overlap. Thus, the maximum overlap is all the students that play varsity sports are honors. => x/4 = 12. i.e., x = 48 which is the minimum.

afife76 wrote:
In a certain class 1/3 of students are honors 1/4 of students play varisity sports. If 12 students are honors and play varisty sports , what is the least number of students in class?

20

22

36

48

144

Please explain your solution..

_________________

Awaiting response,

Thnx & Rgds,
Chandra

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Intern
Joined: 10 Aug 2004
Posts: 40

Kudos [?]: 1 [0], given: 0

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25 Aug 2004, 08:34
My answer is 144

Total=Group1+group2-both+neither
144=48+36-12+60
144=144.

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Intern
Joined: 10 Aug 2004
Posts: 40

Kudos [?]: 1 [0], given: 0

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25 Aug 2004, 08:35
My answer is 144

Total=Group1+group2-both+neither
144=48+36-12+60
144=144.

Kudos [?]: 1 [0], given: 0

Intern
Joined: 10 Aug 2004
Posts: 40

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25 Aug 2004, 08:37
I got the math wrong, please ignore last post.

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Manager
Joined: 19 Jun 2003
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Re: PS: varisty sports [#permalink]

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25 Aug 2004, 12:14
mallelac wrote:
The least number comes when both the categories have the highest overlap. Thus, the maximum overlap is all the students that play varsity sports are honors. => x/4 = 12. i.e., x = 48 which is the minimum.

Mallelac, your approach is very cool!!

Thank you to both!!

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Re: PS: varisty sports   [#permalink] 25 Aug 2004, 12:14
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# In a certain class 1/3 of students are honors 1/4 of

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