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In a certain club, every member likes red wine or white wine
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24 Jun 2012, 03:43
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In a certain club, every member likes red wine or white wine or both. If the number of club members that like red wine and do not like white wine is three times the number of club members that like white wine and do not like red wine, then what is the number of club members that like both red wine and white wine? (1) The total number of club members is 60. (2) The number of club members that do not like white wine is three times that number of club members that do like white wine.
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Re: In a certain club, every member likes red wine or white wine
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24 Jun 2012, 04:10
In a certain club, every member likes red wine or white wine or both. If the number of club members that like red wine and do not like white wine is three times the number of club members that like white wine and do not like red wine, then what is the number of club members that like both red wine and white wine?Since in the club every member likes red wine or white wine or both, then there are no members who like neither of the wines, so we have that: {Total}={Red}+{White}{Both}. Also given that {Red}{Both}=3*({White}{Both}) > {Red}=3*{White}2*{Both}. So, {Total}=(3*{White}2{Both})+{White}{Both} > {Total}=4*{White}3*{Both}The question is asks about {Both}=?(1) The total number of club members is 60 > 60=4*{White}3*{Both}. Two unknowns. Not sufficient. (2) The number of club members that do not like white wine is three times that number of club members that do like white wine > {Total}{White}=3*{White} > {Total}=4*{White}. So, 4*{White}=4*{White}3*{Both} > 3*{Both}=0 > {Both}=0. Sufficient. Answer: B. Hope it's clear.
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Re: In a certain club, every member likes red wine or white wine
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10 Aug 2012, 16:19
Bunuel wrote: In a certain club, every member likes red wine or white wine or both. If the number of club members that like red wine and do not like white wine is three times the number of club members that like white wine and do not like red wine, then what is the number of club members that like both red wine and white wine?
Since in the club every member likes red wine or white wine or both, then there are no members who like neither of the wines, so we have that: {Total}={Red}+{White}{Both}.
Also given that {Red}{Both}=3*({White}{Both}) > {Red}=3*{White}2*{Both}. So, {Total}=(3*{White}2{Both})+{White}{Both} > {Total}=4*{White}3*{Both}
The question is asks about {Both}=?
(1) The total number of club members is 60 > 60=4*{White}3*{Both}. Two unknowns. Not sufficient.
(2) The number of club members that do not like white wine is three times that number of club members that do like white wine > {Total}{White}=3*{White} > {Total}=4*{White}. So, 4*{White}=4*{White}3*{Both} > 3*{Both}=0 > {Both}=0. Sufficient.
Answer: B.
Hope it's clear. Doing the set matrix:  red not red tot white  ?  x not white  3x  0 tot 2)  red not red tot white  ?  x  y not white  3x  0  3y tot So, y=x. and this implies white/red = 0 Is this the right reasoning?



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Re: In a certain club, every member likes red wine or white wine
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11 Aug 2012, 00:54
superpus07 wrote: Bunuel wrote: In a certain club, every member likes red wine or white wine or both. If the number of club members that like red wine and do not like white wine is three times the number of club members that like white wine and do not like red wine, then what is the number of club members that like both red wine and white wine?
Since in the club every member likes red wine or white wine or both, then there are no members who like neither of the wines, so we have that: {Total}={Red}+{White}{Both}.
Also given that {Red}{Both}=3*({White}{Both}) > {Red}=3*{White}2*{Both}. So, {Total}=(3*{White}2{Both})+{White}{Both} > {Total}=4*{White}3*{Both}
The question is asks about {Both}=?
(1) The total number of club members is 60 > 60=4*{White}3*{Both}. Two unknowns. Not sufficient.
(2) The number of club members that do not like white wine is three times that number of club members that do like white wine > {Total}{White}=3*{White} > {Total}=4*{White}. So, 4*{White}=4*{White}3*{Both} > 3*{Both}=0 > {Both}=0. Sufficient.
Answer: B.
Hope it's clear. Doing the set matrix:  red not red tot white  ?  x not white  3x  0 tot 2)  red not red tot white  ?  x  y not white  3x  0  3y tot So, y=x. and this implies white/red = 0 Is this the right reasoning? Yes, your approach is correct.
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Re: In a certain club, every member likes red wine or white wine
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12 Aug 2012, 10:42
manulath wrote: (2) The number of club members that do not like white wine is three times that number of club members that do like white wine.
x Ah, i failed to carefully read (2) where it says at the end "..number of club members that do like white wine", which is the sum of those who like Both + those who like only like White wine (as opposed to those who only like white)
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Re: In a certain club, every member likes red wine or white wine
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16 Sep 2012, 06:59
Let a > no of ppl who like Red wine alone c >no of ppl who like white wine alone b > no of ppl who like both from the question a=3c and we have to find b 1) a+b+c = 60.. nothing can be inferred abt b 2) a=3(b+c) and from the question we know a=3c which implies b=0 hence 2 alone is sufficient
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Re: In a certain club, every member likes red wine or white wine
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07 May 2018, 19:29
Bunuel wrote: In a certain club, every member likes red wine or white wine or both. If the number of club members that like red wine and do not like white wine is three times the number of club members that like white wine and do not like red wine, then what is the number of club members that like both red wine and white wine?
Since in the club every member likes red wine or white wine or both, then there are no members who like neither of the wines, so we have that: {Total}={Red}+{White}{Both}.
Also given that {Red}{Both}=3*({White}{Both}) > {Red}=3*{White}2*{Both}. So, {Total}=(3*{White}2{Both})+{White}{Both} > {Total}=4*{White}3*{Both}
The question is asks about {Both}=?
(1) The total number of club members is 60 > 60=4*{White}3*{Both}. Two unknowns. Not sufficient.
(2) The number of club members that do not like white wine is three times that number of club members that do like white wine > {Total}{White}=3*{White} > {Total}=4*{White}. So, 4*{White}=4*{White}3*{Both} > 3*{Both}=0 > {Both}=0. Sufficient.
Answer: B.
Hope it's clear. Hi Bunuel, How can we infer to this {Red}{Both}=3*({White}{Both}). I dont understand this part. Can you elaborate more? Thank you



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Re: In a certain club, every member likes red wine or white wine
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07 May 2018, 22:01
Hungluu92vn wrote: Bunuel wrote: In a certain club, every member likes red wine or white wine or both. If the number of club members that like red wine and do not like white wine is three times the number of club members that like white wine and do not like red wine, then what is the number of club members that like both red wine and white wine?
Since in the club every member likes red wine or white wine or both, then there are no members who like neither of the wines, so we have that: {Total}={Red}+{White}{Both}.
Also given that {Red}{Both}=3*({White}{Both}) > {Red}=3*{White}2*{Both}. So, {Total}=(3*{White}2{Both})+{White}{Both} > {Total}=4*{White}3*{Both}
The question is asks about {Both}=?
(1) The total number of club members is 60 > 60=4*{White}3*{Both}. Two unknowns. Not sufficient.
(2) The number of club members that do not like white wine is three times that number of club members that do like white wine > {Total}{White}=3*{White} > {Total}=4*{White}. So, 4*{White}=4*{White}3*{Both} > 3*{Both}=0 > {Both}=0. Sufficient.
Answer: B.
Hope it's clear. Hi Bunuel, How can we infer to this {Red}{Both}=3*({White}{Both}). I dont understand this part. Can you elaborate more? Thank you The number of club members that like red wine and do not like white wine is three times the number of club members that like white wine and do not like red wine. The number of club members that like red wine and do not like white wine = {Red}  {Both} (this gives the number of club members that like only Red wine) The number of club members that like white wine and do not like red wine = {White}  {Both} (this gives the number of club members that like only White wine)
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Collection of Questions: PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.
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Re: In a certain club, every member likes red wine or white wine
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01 Jun 2018, 12:51
manulath wrote: In a certain club, every member likes red wine or white wine or both. If the number of club members that like red wine and do not like white wine is three times the number of club members that like white wine and do not like red wine, then what is the number of club members that like both red wine and white wine?
(1) The total number of club members is 60.
(2) The number of club members that do not like white wine is three times that number of club members that do like white wine. Hi Can anyone please help me with the double matrix to solve this question? Thanks



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Re: In a certain club, every member likes red wine or white wine
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20 Sep 2018, 19:58
I find the answer quite contradictory:
In the question, it says: "every member likes red wine or white wine or both"
implying there must be some number for "Like Red", "Like White" and "Like both"
Yet, we got an answer saying "Both" is 0.............
I just dont get the concept.




Re: In a certain club, every member likes red wine or white wine &nbs
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