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In a certain factory, the production line which produces the bags has

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In a certain factory, the production line which produces the bags has  [#permalink]

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New post 05 Jan 2017, 05:51
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In a certain factory, the production line which produces the bags has the probability that a bag selected at random is defective is 0.02. If 6 bags are selected at random, what is the probability that at least one bag is defective?

A. \(0.02^6\)

B. \((0.02)(0.98)^6\)

C. \(1-(0.02)^6\)

D. \(0.98^6\)

E. \(1-(0.98)^6\)

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Re: In a certain factory, the production line which produces the bags has  [#permalink]

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New post 05 Jan 2017, 09:01
the probability of not getting A DEFECTIVE BAG is .98 so probability of getting defective bag equal to 1-(.98)^6 so answer is E
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Re: In a certain factory, the production line which produces the bags has  [#permalink]

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New post 05 Jan 2017, 09:28
MathRevolution wrote:
In a certain factory, the production line which produces the bags has the probability that a bag selected at random is defective is 0.02. If 6 bags are selected at random, what is the probability that at least one bag is defective?

A. \(0.02^6\)

B. \((0.02)(0.98)^6\)

C. \(1-(0.02)^6\)

D. \(0.98^6\)

E. \(1-(0.98)^6\)


p(d) = 0.02
p(g) = 0.98

Probability of getting 1 defective = 1 - Probability of selecting all good bags.

Probability of getting 1 defective = \(1 - P(g)^6\)

Probability of getting 1 defective = \(1 - (0.98)^6\)

Hence, the answer will be (E) \(1-(0.98)^6\)
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Re: In a certain factory, the production line which produces the bags has  [#permalink]

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New post 06 Jan 2017, 11:07
MathRevolution wrote:
In a certain factory, the production line which produces the bags has the probability that a bag selected at random is defective is 0.02. If 6 bags are selected at random, what is the probability that at least one bag is defective?

A. \(0.02^6\)

B. \((0.02)(0.98)^6\)

C. \(1-(0.02)^6\)

D. \(0.98^6\)

E. \(1-(0.98)^6\)


We are given that the probability that a selected bag is defective is 0.02, so we can determine that the probability of a non-defective bag is 1 - 0.02 = 0.98. We need to determine the probability that when 6 bags are selected at least one bag is defective.

We know the following:

1 = P(at least one defective bag is selected) + P(no defective bags are selected)

Thus,

P(at least one defective bag is selected) = 1 - P(no defective bags are selected)

Therefore, we need to determine P(no defective bags are among the 6 selected bags).

P(no defective bags are among the 6 selected bags) = 0.98^6

Thus, P(at least one defective bag is among the 6 selected bags) = 1 - 0.98^6

Answer: E
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Re: In a certain factory, the production line which produces the bags has  [#permalink]

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New post 08 Jan 2017, 18:11
==> probability that at least one bag is defective=1-probability that all bags are not defective=\(1-(1-0.02)^6\).

Hence, the answer is E.
Answer: E
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Re: In a certain factory, the production line which produces the bags has  [#permalink]

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New post 13 Jan 2017, 20:56
Probability of at least one bag is defective = 1 - P(0 defects)
P(a bag is defective) = 0.02
P(a bag is not defective) = 1-0.02 = 0.98

P(at least one bag is defective from a random selection of 6 bags) =1- 0C6*((0.02)^0)*((0.98)^6)
= 1-(0.98)^6
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Re: In a certain factory, the production line which produces the bags has  [#permalink]

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Re: In a certain factory, the production line which produces the bags has   [#permalink] 28 Jan 2018, 12:44
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