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# In a certain school, 40 more than 1/3 of all the students

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Manager
Joined: 16 May 2004
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Location: Thailand
In a certain school, 40 more than 1/3 of all the students [#permalink]

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15 Jul 2004, 09:34
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In a certain school, 40 more than 1/3 of all the students are taking a science course and 1/4 of those taking a science course are taking physics. If 1/8 of all the students in the school are taking physics, how many students are in the school?

A) 48
B) 120
C) 240
D) 480
E) 960

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CIO
Joined: 09 Mar 2003
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15 Jul 2004, 10:08
C. plug in the answers, or just do the algebra. Plugging in is fine for this one.

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Senior Manager
Joined: 19 May 2004
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15 Jul 2004, 10:56
C) 240.

S = 40 + x*(1/3)
P=(1/4)*S = (1/8)X

Solve and get X=240.

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Intern
Joined: 07 Jun 2004
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15 Jul 2004, 11:11

Assume X=all students
Assume Y=Science Students

40+1/3x=y

Now take Physics students

1/8x=1/4y ---> Y=1/2x

Put the two equestions together

40+1/3x=1/2x

80+2/3x=x

80=1/3x

240=x
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Manager
Joined: 16 May 2004
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Location: Thailand

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17 Jul 2004, 10:08
" 1/4 of those taking a science course are taking physics "

Does it mean that there are some students studying both science and physics? 1/4 { 40 + X*(1/3) } is the number of student who study both science and physics ? Anyone think like me?
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Manager
Joined: 08 Jun 2004
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17 Jul 2004, 11:13
HI...

let the total no: of students in the class be X...

science course = X/3 +40 = X +120/3

physics course = X+120/3 *1/4

= X/8 of the total

12x- 8X =8*120

x = 240...

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17 Jul 2004, 11:13
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# In a certain school, 40 more than 1/3 of all the students

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