It is currently 23 Jun 2017, 02:25

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In a certain senior class, 72 percent of the male students

Author Message
Manager
Joined: 30 Jan 2006
Posts: 145
In a certain senior class, 72 percent of the male students [#permalink]

### Show Tags

15 Apr 2006, 14:35
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In a certain senior class, 72 percent of the male students and 80 percent of the female students have applied to college. What fraction of the students in the senior class are male?

1) There are 840 students in the senior class.

2) 75 percent of the students in the senior class have applied to college.

Manager
Joined: 09 Feb 2006
Posts: 129
Location: New York, NY

### Show Tags

15 Apr 2006, 15:09

Statement 1 -- this is insufficient, because we do not know anything about the percentage breakouts of males or females, or of those who applied to college.

Statement 2: Sufficient. Let m = number of males, and f = number of femals. m+f = T (total student body). We can set up an equation for the perccentage of people who applied to college. (.72m + .8f)/T = .75

.75m + .75f = .72m + .8f
.03m = .05f

The ratio of males to females in this group is given by m/f = 5/3

Now we can find out the fraction of males represented in the total student body, because we know m + f = T. f = 3/5m, so m + 3/5m = T.

8/5m = t

m = 5/8 t

Therefore, males represent 5/8 of the student body.
Senior Manager
Joined: 11 Nov 2005
Posts: 328
Location: London

### Show Tags

15 Apr 2006, 17:32
Agree B.

good explanation jcgoodchild.

jcgoodchild wrote:

Statement 1 -- this is insufficient, because we do not know anything about the percentage breakouts of males or females, or of those who applied to college.

Statement 2: Sufficient. Let m = number of males, and f = number of femals. m+f = T (total student body). We can set up an equation for the perccentage of people who applied to college. (.72m + .8f)/T = .75

.75m + .75f = .72m + .8f
.03m = .05f

The ratio of males to females in this group is given by m/f = 5/3

Now we can find out the fraction of males represented in the total student body, because we know m + f = T. f = 3/5m, so m + 3/5m = T.

8/5m = t

m = 5/8 t

Therefore, males represent 5/8 of the student body.
Manager
Joined: 30 Jan 2006
Posts: 145

### Show Tags

16 Apr 2006, 16:09
jcgoodchild wrote:

Statement 1 -- this is insufficient, because we do not know anything about the percentage breakouts of males or females, or of those who applied to college.

Statement 2: Sufficient. Let m = number of males, and f = number of femals. m+f = T (total student body). We can set up an equation for the perccentage of people who applied to college. (.72m + .8f)/T = .75

.75m + .75f = .72m + .8f
.03m = .05f

The ratio of males to females in this group is given by m/f = 5/3

Now we can find out the fraction of males represented in the total student body, because we know m + f = T. f = 3/5m, so m + 3/5m = T.

8/5m = t

m = 5/8 t

Therefore, males represent 5/8 of the student body.

Makes complete sense now! Thanks

OA is B.
16 Apr 2006, 16:09
Display posts from previous: Sort by