Author 
Message 
TAGS:

Hide Tags

Manager
Joined: 16 May 2011
Posts: 204
Concentration: Finance, Real Estate
GMAT Date: 12272011
WE: Law (Law)

In a circular clock, the long hand is the radius of the circ [#permalink]
Show Tags
06 Jul 2011, 12:46
5
This post was BOOKMARKED
Question Stats:
47% (02:17) correct
53% (01:16) wrong based on 84 sessions
HideShow timer Statistics
In a circular clock, the long hand is the radius of the circle. At what time is the smaller angle between the hands of the clock NOT divisible by 15? I 7:20 II 9:00 III 4:30 (A) Only I (B) Only III (C) I + II (D) II+III (E) I+II+III
Official Answer and Stats are available only to registered users. Register/ Login.



Manager
Joined: 29 Jun 2011
Posts: 76

Re: Clock hands [#permalink]
Show Tags
06 Jul 2011, 13:13
1
This post received KUDOS
Moderators : help needed here as you can see from the diagram every division 121, 12, 23 etc etc makes a sector angle of 30 deg. this can be mathematically achieved by = total central angle in the circle/total number of sector divisions = 360/12 =30 (because clock divisions make 12 sectors in the clock) now see : I says 7:20 so here one hand points at 7 and the other at 20 (ie 4). Now count number of divisions from 7 to 4. div = 3 convert div to angle. each div = 30 deg so div(from 7 to 4) = 3*30 = 90 which is divisible by 15 II says : 9:00 ie angle made between 9 and 00(or 12) which is 3 divisions = 3*30 =90 divisible by 15 III says : 430 ie 2 divisions ie 60deg = divisible by 15 so IMO the options provided are debatable. please check and confirm. whats the OE and OA?
Attachments
File comment: clock angles.
15deg3.jpg [ 39.48 KiB  Viewed 11600 times ]
_________________
It matters not how strait the gate, How charged with punishments the scroll, I am the master of my fate : I am the captain of my soul. ~ William Ernest Henley



Manager
Joined: 07 Jun 2011
Posts: 73

Re: Clock hands [#permalink]
Show Tags
06 Jul 2011, 17:23
2
This post received KUDOS
in one minute hand take a 360 Degree circle and the hour hand take a 30 degree circle
For the hour hand 30 degree movement is accomplished in 1 hour,(60 Min) so in one minute 30/60 = .5 degree (hour hand travels that much in one minute) The minute hand accomplish 6 degree rotation in one minute
No to the problem at 7.20
Position of hour hand from 12(0 degree) is = 30*7 + 20*.5 = 210 + 10 = 220
Position of minute hand is 20*6 = 120 degrees from 12(0 degree)
the difference in angles is 100 degrees Not divisible by 15...
Employing the same priciple on the rest I get answer A



Math Forum Moderator
Joined: 20 Dec 2010
Posts: 2010

Re: Clock hands [#permalink]
Show Tags
06 Jul 2011, 18:04
fivedaysleft wrote: Moderators : help needed here
as you can see from the diagram every division 121, 12, 23 etc etc makes a sector angle of 30 deg. this can be mathematically achieved by = total central angle in the circle/total number of sector divisions = 360/12 =30 (because clock divisions make 12 sectors in the clock)
now see : I says 7:20 so here one hand points at 7 and the other at 20 (ie 4). Now count number of divisions from 7 to 4. div = 3 convert div to angle. each div = 30 deg so div(from 7 to 4) = 3*30 = 90 which is divisible by 15
II says : 9:00 ie angle made between 9 and 00(or 12) which is 3 divisions = 3*30 =90 divisible by 15
III says : 430 ie 2 divisions ie 60deg = divisible by 15
so IMO the options provided are debatable. please check and confirm.
whats the OE and OA? manishgeorge already answered. 7:20 means smaller hand also moved (30*4/360)*30= 10 deg; So angle between hands= 30*3+10=100
_________________
~fluke
GMAT Club Premium Membership  big benefits and savings



Intern
Joined: 14 Mar 2010
Posts: 16

Re: Clock hands [#permalink]
Show Tags
28 Jul 2011, 08:15
2
This post received KUDOS
Formula for angle between Hour ( H) and minute ( m ) hand is
(60H11m)/2
using this : 7.20 >60*7 11*20 /2 = 100 not divisible by 15 9:00 > 180 divisible by 15 4:30 > 105 divisible by 15
SO answer is A
br, Binu



Intern
Joined: 27 Feb 2011
Posts: 48

Re: Clock hands [#permalink]
Show Tags
28 Jul 2011, 13:22
7:20 1. Hours hand = 7* 30 + 1/3 (30) = 210 + 10 = 220 2. Mins hand = 4* 30 = 120
diff = 100 deg. NOT divisible by 15..
9:00 and 4:30 are pretty easy



Intern
Joined: 05 Oct 2010
Posts: 13

Re: Clock hands [#permalink]
Show Tags
28 Jul 2011, 14:19
dimri10 wrote: In a circular clock, the long hand is the radius of the circle. At what time is the smaller angle between the hands of the clock NOT divisible by 15? I 7:20 II 9:00 III 4:30 (A) Only I (B) Only III (C) I + II (D) II+III (E) I+II+III I just do not get it! The clock/circle has 360". Nowto figure out the SMALL angle between hands of the clock I asigned a 30" value between the numbers on its face (360/12=30) Now, at 7.20 one hand is on 7 and the other is on 4, thus, the small angle is 90" while the outside angle is 270". As follows, at 9.00 one hand is at nine while the other is on 12  We have an angle formed by 3 intervals of 30". Small angle is 90". In the last scenario, 4.30, One hand is at 4 and the other at 6 so the angle is 60. Everything divisible by 15... Where do I go wrong



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7438
Location: Pune, India

Re: Clock hands [#permalink]
Show Tags
28 Jul 2011, 21:20
5
This post received KUDOS
Expert's post
1
This post was BOOKMARKED
katealpha wrote: dimri10 wrote: In a circular clock, the long hand is the radius of the circle. At what time is the smaller angle between the hands of the clock NOT divisible by 15? I 7:20 II 9:00 III 4:30 (A) Only I (B) Only III (C) I + II (D) II+III (E) I+II+III I just do not get it! The clock/circle has 360". Nowto figure out the SMALL angle between hands of the clock I asigned a 30" value between the numbers on its face (360/12=30) Now, at 7.20 one hand is on 7 and the other is on 4, thus, the small angle is 90" while the outside angle is 270". As follows, at 9.00 one hand is at nine while the other is on 12  We have an angle formed by 3 intervals of 30". Small angle is 90". In the last scenario, 4.30, One hand is at 4 and the other at 6 so the angle is 60. Everything divisible by 15... Where do I go wrong At 7:20, is the hour hand at 7 or a third between 7 and 8? At 4:30, is the hour hand at 4 or mid way between 4 and 5? You have to account for the little bit of distance covered by the hour hand too. Employ Relative Speed here. Minute hand covers 360 degrees in an hour. Hour hand covers 360/12 = 30 degrees in an hour. Speed of minute hand relative to hour hand is 360  30 = 330 degrees per hour. At 7 o clock, the minute hand is 210 degrees behind the hour hand. In 20 minutes (at 7:20), it makes up 330/3 = 110 degrees. Now it will be 100 degrees behind the hour hand. The smaller angle between them is 100 degrees. At 4 o clock, the minute hand is 120 degrees behind the hour hand. In half an hour, it covers 330/2 = 165 degrees to get 45 degrees ahead of the hour hand. The smaller angle between them is 45 degrees. At 9 o clock, the angle between the two hands is 90 degrees. (Such clock questions are applications of Relative Speed. Do you remember 'A cop is running after a crook at a speed of ... Initial distance between them is ... When will he catch up?' kind of questions? The principle employed is exactly the same here.)
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews



Manager
Status: On...
Joined: 16 Jan 2011
Posts: 188

Re: Clock hands [#permalink]
Show Tags
30 Jul 2011, 19:31
@Karishma +1 Kudos Loved the approach. Yes it is a relative speed problem and I like your way to approach the problem. Do post any variant of the question popping up because I am too lazy to create a variant.
_________________
Labor cost for typing this post >= Labor cost for pushing the Kudos Button http://gmatclub.com/forum/kudoswhataretheyandwhywehavethem94812.html



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7438
Location: Pune, India

Re: Clock hands [#permalink]
Show Tags
01 Aug 2011, 02:30
krishp84 wrote: @Karishma +1 Kudos
Loved the approach. Yes it is a relative speed problem and I like your way to approach the problem. Do post any variant of the question popping up because I am too lazy to create a variant. Another type of clock questions that I have come across: Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is x degrees. He returns between 6 and 7 pm same day and notices that the angle is again x degrees. For how much time was Mr A away from home? (The value of x is given. Try putting different values (180 degrees, 170 degrees, 45 degrees etc) and you can make PS/DS questions)
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews



Manager
Status: On...
Joined: 16 Jan 2011
Posts: 188

Re: Clock hands [#permalink]
Show Tags
01 Aug 2011, 17:19
VeritasPrepKarishma wrote: Another type of clock questions that I have come across: Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is x degrees. He returns between 6 and 7 pm same day and notices that the angle is again x degrees. For how much time was Mr A away from home? (The value of x is given. Try putting different values (180 degrees, 170 degrees, 45 degrees etc) and you can make PS/DS questions) Is the answer 3 hours 18 mns ? okay  My thought process.... Distance between Hour hand and Minute hand between 3 and 4 PM is x degree  So Time will be 3:y, where y is the distance of the minute hand from 12 position Distance between Hour hand and Minute hand between 6 and 7 PM is x degree  So Time will be 6:z, where z is the distance of the minute hand from 12 position y = ()+x z = ()+x+30*3 So the difference between 6:z and 3:y is (63) hours + 30*3/5 minute (Minute hand covers 30 degree in 5 minutes) = 3 hours 18minutes.... PS  I did not substitute, But I will definitely substitute the answer choices to confirm. Do let me know your thoughts.....
_________________
Labor cost for typing this post >= Labor cost for pushing the Kudos Button http://gmatclub.com/forum/kudoswhataretheyandwhywehavethem94812.html



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7438
Location: Pune, India

Re: Clock hands [#permalink]
Show Tags
01 Aug 2011, 22:24
krishp84 wrote: VeritasPrepKarishma wrote: Another type of clock questions that I have come across: Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is x degrees. He returns between 6 and 7 pm same day and notices that the angle is again x degrees. For how much time was Mr A away from home? (The value of x is given. Try putting different values (180 degrees, 170 degrees, 45 degrees etc) and you can make PS/DS questions) Is the answer 3 hours 18 mns ? okay  My thought process.... Distance between Hour hand and Minute hand between 3 and 4 PM is x degree  So Time will be 3:y, where y is the distance of the minute hand from 12 position Distance between Hour hand and Minute hand between 6 and 7 PM is x degree  So Time will be 6:z, where z is the distance of the minute hand from 12 position y = ()+x z = ()+x+30*3 So the difference between 6:z and 3:y is (63) hours + 30*3/5 minute (Minute hand covers 30 degree in 5 minutes) = 3 hours 18minutes.... PS  I did not substitute, But I will definitely substitute the answer choices to confirm. Do let me know your thoughts..... y and z are the distances from 12 in minutes in your solution, not in degrees. I am not sure how you made these equations. The question I gave is a generic example. The actual question would have a value for x. e.g. Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is 45 degrees. He returns between 6 and 7 pm same day and notices that the angle is again 45 degrees. For how much time was Mr A away from home? Even this would be a DS question with 2 statements giving further information because multiple answers are possible. The diagram below will explain why. Attachment:
Ques3.jpg [ 14.19 KiB  Viewed 10964 times ]
So the statements could be something like "He was out for more than 3 hr 10 minutes" etc...
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews



Manager
Joined: 25 Aug 2008
Posts: 223
Location: India
WE 1: 3.75 IT
WE 2: 1.0 IT

Re: Clock hands [#permalink]
Show Tags
02 Aug 2011, 03:58
Karishma, Shouldn't this question be like what will the maximum / minimum time was Mr A away from home, considering that we are going to have 2 possibilities. Also, how can we solve this types of ques.
_________________
Cheers, Varun
If you like my post, give me KUDOS!!



Senior Manager
Joined: 08 Nov 2010
Posts: 408
WE 1: Business Development

Re: Clock hands [#permalink]
Show Tags
02 Aug 2011, 10:19
dimri10 wrote: In a circular clock, the long hand is the radius of the circle. At what time is the smaller angle between the hands of the clock NOT divisible by 15? I 7:20 II 9:00 III 4:30 (A) Only I (B) Only III (C) I + II (D) II+III (E) I+II+III The way I would solve this Q is this: look at the answers  we want to check answer II first of all bc its easy to check and if ill cancel it, it will leave me with 2 answers. We know easily that at 0900  the angel is 90 and therefore we can remove all the questions with answer II  meaning C,D,E  OUT. now  bc we have no answer as "none"  we need to check only one of the answers. I or III. For me, 0430 is easier bc its dealing with half and not thirds. we know that the big one is at 180, the small one is 4.5*30 = 135. 180135=45. Done. III is out. I dont need to check answer I bc i made sure all the others are wrong.
_________________
GMAT Club Premium Membership  big benefits and savings



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7438
Location: Pune, India

Re: Clock hands [#permalink]
Show Tags
02 Aug 2011, 21:44
varunmaheshwari wrote: Karishma, Shouldn't this question be like what will the maximum / minimum time was Mr A away from home, considering that we are going to have 2 possibilities. Also, how can we solve this types of ques. Yes, if you want to make it a PS question, you can definitely ask for the maximum or minimum time. There are going to be 4 possibilities (2C1 * 2C1). 2 possibilities for the time at which he leaves. 2 possibilities for the time at which he returns. How to solve it? Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is 45 degrees. He returns between 6 and 7 pm same day and notices that the angle is again 45 degrees. What is the minimum time for which Mr A was away from home? Let's focus on the minimum time that he was away. For that he should have left later and arrived earlier. So he should have left at around 3:25 and arrived at around 6:25 (Look at the diagram above to see the case we are talking about) At 3 o clock, the angle between the hour and minute hand is 90 degrees. The minute hand should cover the 90 degrees and then create an angle of 45 degrees between itself and the hour hand. Relative speed of minute hand is 330 degrees/hour. To cover 135 degrees relative to the hour hand, it will take 60/330 * 135 minutes = 270/11 minutes = 24(6/11) minutes He must have left at 24(6/11) minutes past 3. At 6 o clock, the angle between the hour and minute hand is 180 degrees. The minute hand should cover 135 degrees relative to the hour hand to create an angle of 45 degrees. Relative speed of minute hand is 330 degrees/hour. To cover 135 degrees relative to the hour hand, it will take 60/330 * 135 minutes = 270/11 minutes = 24(6/11) minutes. He must have arrived at 24(6/11) minutes past 6. This means he was out for exactly 3 hours. Now try the case of 'maximum time' and put it up.
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews



Manager
Status: On...
Joined: 16 Jan 2011
Posts: 188

Re: Clock hands [#permalink]
Show Tags
08 Aug 2011, 19:42
1
This post received KUDOS
VeritasPrepKarishma wrote: varunmaheshwari wrote: Karishma, Shouldn't this question be like what will the maximum / minimum time was Mr A away from home, considering that we are going to have 2 possibilities. Also, how can we solve this types of ques. Yes, if you want to make it a PS question, you can definitely ask for the maximum or minimum time. There are going to be 4 possibilities (2C1 * 2C1). 2 possibilities for the time at which he leaves. 2 possibilities for the time at which he returns. How to solve it? Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is 45 degrees. He returns between 6 and 7 pm same day and notices that the angle is again 45 degrees. What is the minimum time for which Mr A was away from home? Let's focus on the minimum time that he was away. For that he should have left later and arrived earlier. So he should have left at around 3:25 and arrived at around 6:25 (Look at the diagram above to see the case we are talking about) At 3 o clock, the angle between the hour and minute hand is 90 degrees. The minute hand should cover the 90 degrees and then create an angle of 45 degrees between itself and the hour hand. Relative speed of minute hand is 330 degrees/hour. To cover 135 degrees relative to the hour hand, it will take 60/330 * 135 minutes = 270/11 minutes = 24(6/11) minutes He must have left at 24(6/11) minutes past 3. At 6 o clock, the angle between the hour and minute hand is 180 degrees. The minute hand should cover 135 degrees relative to the hour hand to create an angle of 45 degrees. This is because 18045 = 135 degrees and not 90+45 degrees  Highlighted to see that evryone gets the reason. Anyway it will become clear in the Maximum exampleRelative speed of minute hand is 330 degrees/hour. To cover 135 degrees relative to the hour hand, it will take 60/330 * 135 minutes = 270/11 minutes = 24(6/11) minutes. He must have arrived at 24(6/11) minutes past 6. This means he was out for exactly 3 hours. Now try the case of 'maximum time' and put it up. Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is 45 degrees. He returns between 6 and 7 pm same day and notices that the angle is again 45 degrees. What is the maximum time for which Mr A was away from home? Now we need  Earliest time that Mr. A left b/w 3 and 4 PM Latest time when Mr. A returned b/w 6 and 7 PM
Relative speed of Minute hand w.r.t Hour hand = 330 degrees per hour
At 3 PM, the angle b/w hour and minute hand = 90 degree So earliest time when Mr. A leaves will be 9045 = 45 degrees to be covered by the minute hand relative to Hour hand = (60/330)45 minutes past 3
At 6 PM, the angle b/w hour and minute hand = 180 degree So latest time when Mr. A returns will be 180+45 = 225 degrees to be covered by the minute hand relative to Hour hand = (60/330)225 minutes past 6
So maximum time for which Mr A was away from home = (60/330)225 minutes past 6  (60/330)45 minutes past 3 = 3 hrs (60/330)180minutes = 3 hours (360/11) minutes = \(3 hours 34\frac{6}{11} minutes\)
_________________
Labor cost for typing this post >= Labor cost for pushing the Kudos Button http://gmatclub.com/forum/kudoswhataretheyandwhywehavethem94812.html



Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 7438
Location: Pune, India

Re: Clock hands [#permalink]
Show Tags
09 Aug 2011, 03:43
krishp84 wrote: Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is 45 degrees. He returns between 6 and 7 pm same day and notices that the angle is again 45 degrees. What is the maximum time for which Mr A was away from home?
Now we need  Earliest time that Mr. A left b/w 3 and 4 PM Latest time when Mr. A returned b/w 6 and 7 PM
Relative speed of Minute hand w.r.t Hour hand = 330 degrees per hour
At 3 PM, the angle b/w hour and minute hand = 90 degree So earliest time when Mr. A leaves will be 9045 = 45 degrees to be covered by the minute hand relative to Hour hand = (60/330)45 minutes past 3
At 6 PM, the angle b/w hour and minute hand = 180 degree So latest time when Mr. A returns will be 180+45 = 225 degrees to be covered by the minute hand relative to Hour hand = (60/330)225 minutes past 6
So maximum time for which Mr A was away from home = (60/330)225 minutes past 6  (60/330)45 minutes past 3 = 3 hrs (60/330)180minutes = 3 hours (360/11) minutes = \(3 hours 34\frac{6}{11} minutes\)
Yes, that's right. Though, in the last step, 360/11 minutes would be 32(8/11) minutes
_________________
Karishma Veritas Prep  GMAT Instructor My Blog
Get started with Veritas Prep GMAT On Demand for $199
Veritas Prep Reviews



Manager
Status: On...
Joined: 16 Jan 2011
Posts: 188

Re: Clock hands [#permalink]
Show Tags
09 Aug 2011, 04:41
VeritasPrepKarishma wrote: krishp84 wrote: Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is 45 degrees. He returns between 6 and 7 pm same day and notices that the angle is again 45 degrees. What is the maximum time for which Mr A was away from home?
Now we need  Earliest time that Mr. A left b/w 3 and 4 PM Latest time when Mr. A returned b/w 6 and 7 PM
Relative speed of Minute hand w.r.t Hour hand = 330 degrees per hour
At 3 PM, the angle b/w hour and minute hand = 90 degree So earliest time when Mr. A leaves will be 9045 = 45 degrees to be covered by the minute hand relative to Hour hand = (60/330)45 minutes past 3
At 6 PM, the angle b/w hour and minute hand = 180 degree So latest time when Mr. A returns will be 180+45 = 225 degrees to be covered by the minute hand relative to Hour hand = (60/330)225 minutes past 6
So maximum time for which Mr A was away from home = (60/330)225 minutes past 6  (60/330)45 minutes past 3 = 3 hrs (60/330)180minutes = 3 hours (360/11) minutes [color=#FF0000]= \(3 hours 34\frac{6}{11} minutes\) [/color] Yes, that's right. Though, in the last step, 360/11 minutes would be 32(8/11) minutesYeah silly me Any one should have said it is 32.xxx minutes just by dividing mentally
_________________
Labor cost for typing this post >= Labor cost for pushing the Kudos Button http://gmatclub.com/forum/kudoswhataretheyandwhywehavethem94812.html



Manager
Status: On...
Joined: 16 Jan 2011
Posts: 188

Re: Clock hands [#permalink]
Show Tags
09 Aug 2011, 04:50
VeritasPrepKarishma wrote: varunmaheshwari wrote: Karishma, Shouldn't this question be like what will the maximum / minimum time was Mr A away from home, considering that we are going to have 2 possibilities. Also, how can we solve this types of ques. Yes, if you want to make it a PS question, you can definitely ask for the maximum or minimum time. There are going to be 4 possibilities (2C1 * 2C1). 2 possibilities for the time at which he leaves. 2 possibilities for the time at which he returns. How to solve it? Mr. A leaves his house between 3 and 4 pm and notices that the angle between the hour and minute hands is 45 degrees. He returns between 6 and 7 pm same day and notices that the angle is again 45 degrees. What is the minimum time for which Mr A was away from home? Let's focus on the minimum time that he was away. For that he should have left later and arrived earlier. So he should have left at around 3:25 and arrived at around 6:25 (Look at the diagram above to see the case we are talking about) At 3 o clock, the angle between the hour and minute hand is 90 degrees. The minute hand should cover the 90 degrees and then create an angle of 45 degrees between itself and the hour hand. Relative speed of minute hand is 330 degrees/hour. To cover 135 degrees relative to the hour hand, it will take 60/330 * 135 minutes = 270/11 minutes = 24(6/11) minutes He must have left at 24(6/11) minutes past 3. At 6 o clock, the angle between the hour and minute hand is 180 degrees. The minute hand should cover 135 degrees relative to the hour hand to create an angle of 45 degrees. Relative speed of minute hand is 330 degrees/hour. To cover 135 degrees relative to the hour hand, it will take 60/330 * 135 minutes = 270/11 minutes = 24(6/11) minutes. He must have arrived at 24(6/11) minutes past 6. This means he was out for exactly 3 hours. Now try the case of 'maximum time' and put it up. One more important thing to note here  At 3 o clock, the angle between the hour and minute hand is 90 degrees. The minute hand should cover the 90 degrees and then create an angle of 45 degrees between itself and the hour hand.
Relative speed of minute hand is 330 degrees/hour. To cover 135 degrees relative to the hour hand, it will take 60/330 * 135 minutes = 270/11 minutes = 24(6/11) minutes
When minute hand moves, Hour hand will also move, but the distance in degree b/w both the hands will remain same.
Let Hour hand move by h degrees when minute hands moves ... The minute hand would be 135+h degrees from 12'o clock position..... But here we ae speaking about relative speed and NOT ABSOLUTE SPEEDcolor=#0000BF], so relative to hour hand , the speed will remain constant (135 degrees)[/color] These are simple points but make the difference to understand the core concepts
_________________
Labor cost for typing this post >= Labor cost for pushing the Kudos Button http://gmatclub.com/forum/kudoswhataretheyandwhywehavethem94812.html



GMAT Club Legend
Joined: 09 Sep 2013
Posts: 15911

Re: Clock hands [#permalink]
Show Tags
21 Sep 2013, 18:29
Hello from the GMAT Club BumpBot! Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up  doing my job. I think you may find it valuable (esp those replies with Kudos). Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Books  GMAT Club Tests  Best Prices on GMAT Courses  GMAT Mobile App  Math Resources  Verbal Resources







Go to page
1 2
Next
[ 21 posts ]




