It is currently 19 Nov 2017, 06:00

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# In a consumer survey, 85% of those surveyed liked at least

Author Message
TAGS:

### Hide Tags

Manager
Joined: 11 Jul 2004
Posts: 119

Kudos [?]: 33 [0], given: 0

In a consumer survey, 85% of those surveyed liked at least [#permalink]

### Show Tags

22 Aug 2004, 14:04
2
This post was
BOOKMARKED
00:00

Difficulty:

65% (hard)

Question Stats:

53% (01:34) correct 47% (01:17) wrong based on 196 sessions

### HideShow timer Statistics

In a consumer survey, 85% of those surveyed liked at least one of three products: 1, 2, and 3. 50% of those asked liked product 1, 30% liked product 2, and 20% liked product 3. If 5% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?

A) 5

B) 10

C) 15

D) 20

E) 25

OPEN DISCUSSION OF THIS QUESTION IS HERE: in-a-consumer-survey-85-of-those-surveyed-liked-at-least-98018.html
[Reveal] Spoiler: OA

Last edited by Bunuel on 14 Sep 2013, 12:20, edited 1 time in total.
Edited the question and added the OA

Kudos [?]: 33 [0], given: 0

Manager
Joined: 16 May 2004
Posts: 64

Kudos [?]: 4 [0], given: 0

Location: columbus

### Show Tags

22 Aug 2004, 15:42
I'm thinking B

more than 1 product is : 50 + 30 + 20 - 85 =15
but this 15% counts the a(intersection)b(intersection)c twice so the ans is
15 -5 = 10 ans

Kudos [?]: 4 [0], given: 0

Current Student
Joined: 06 Sep 2013
Posts: 1972

Kudos [?]: 740 [0], given: 355

Concentration: Finance
Re: In a consumer survey, 85% of those surveyed liked at least [#permalink]

### Show Tags

14 Sep 2013, 12:05
I'll go with B too.

85 = 50 + 30 + 20 - x - 2(5) + 0

x = 5

Then Liked more than 1 includes those who liked exactly 2 and those who liked exactly 3.

Liked exactly 2 ---> From x = 5
Liked exactly 3----> Given 5

Total 5+5 =10

Kudos [?]: 740 [0], given: 355

Math Expert
Joined: 02 Sep 2009
Posts: 42247

Kudos [?]: 132664 [0], given: 12331

Re: In a consumer survey, 85% of those surveyed liked at least [#permalink]

### Show Tags

14 Sep 2013, 12:21
Expert's post
2
This post was
BOOKMARKED
In a consumer survey, 85% of those surveyed liked at least one of three products: 1, 2, and 3. 50% of those asked liked product 1, 30% liked product 2, and 20% liked product 3. If 5% of the people in the survey liked all three of the products, what percentage of the survey participants liked more than one of the three products?

A) 5
B) 10
C) 15
D) 20
E) 25

As 85% of those surveyed liked at least one of three products then 15% liked none of three products.

Total = {liked product 1} + {liked product 2} + {liked product 3} - {liked exactly two products} - 2*{liked exactly three product} + {liked none of three products}

$$100=50+30+20-x-2*5+15$$ --> $$x=5$$, so 5 people liked exactly two products. More than one product liked those who liked exactly two products, (5%) plus those who liked exactly three products (5%), so 5+5=10% liked more than one product.

For more check ADVANCED OVERLAPPING SETS PROBLEMS

OPEN DISCUSSION OF THIS QUESTION IS HERE: in-a-consumer-survey-85-of-those-surveyed-liked-at-least-98018.html
_________________

Kudos [?]: 132664 [0], given: 12331

Re: In a consumer survey, 85% of those surveyed liked at least   [#permalink] 14 Sep 2013, 12:21
Display posts from previous: Sort by