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# In a field day at a school, each child who competed in n events and sc

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In a field day at a school, each child who competed in n events and sc  [#permalink]

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Updated on: 23 Jul 2017, 23:57
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In a field day at a school, each child who competed in $$n$$ events and scored a total of $$p$$ points was given an overall score of $$\frac{p}{n} + n$$. Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

A. $$\frac{10}{23}$$

B. $$\frac{7}{10}$$

C. $$\frac{4}{5}$$

D. $$\frac{10}{9}$$

E. $$\frac{12}{7}$$

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Originally posted by carcass on 23 Jul 2017, 09:16.
Last edited by Bunuel on 23 Jul 2017, 23:57, edited 1 time in total.
Edited the question.
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Re: In a field day at a school, each child who competed in n events and sc  [#permalink]

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25 May 2020, 13:31
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carcass wrote:
In a field day at a school, each child who competed in $$n$$ events and scored a total of $$p$$ points was given an overall score of $$\frac{p}{n} + n$$. Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

A. $$\frac{10}{23}$$

B. $$\frac{7}{10}$$

C. $$\frac{4}{5}$$

D. $$\frac{10}{9}$$

E. $$\frac{12}{7}$$

Given: Score = p/n + n

Andrew competed in 1 event and scored 9 points
Here, n = 1 and p = 9
So, Andrew's score = 9/1 + 1 = 9 + 1 = 10

Jason competed in 3 events and scored 5, 6, and 7 points, respectively
5 + 6 + 7 = 18
So, n = 3 and p = 18
Jason's score = 18/3 + 3 = 6 + 3 = 9

What was the ratio of Andrew's overall score to Jason's overall score?
Ratio = 10/9

Cheers,
Brent
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Re: In a field day at a school, each child who competed in n events and sc  [#permalink]

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23 Jul 2017, 17:01
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carcass wrote:
In a field day at a school, each child who competed in n events and scored a total of p points was given an overall score of P/n + n. n Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

A. $$\frac{10}{23}$$

B.$$\frac{7}{10}$$

C. $$\frac{4}{5}$$

D.$$\frac{10}{9}$$

E. $$\frac{12}{7}$$

It should be D

For readers, denominator for P is just 1 n. The fraction then adds into so you can rewrite it as $$n + \frac{p}{n}$$ for a clearer understanding.

Andrew:

$$1 + \frac{9}{1}$$ $$= 1 + 9 = 10$$

Jason:
$$3 + \frac{(5+6+7)}{3}$$ $$= 3 + \frac{18}{3} = 9$$

Andrew : Jason $$= 10 : 9$$
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Re: In a field day at a school, each child who competed in n events and sc  [#permalink]

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26 Jul 2017, 15:38
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carcass wrote:
In a field day at a school, each child who competed in $$n$$ events and scored a total of $$p$$ points was given an overall score of $$\frac{p}{n} + n$$. Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?

A. $$\frac{10}{23}$$

B. $$\frac{7}{10}$$

C. $$\frac{4}{5}$$

D. $$\frac{10}{9}$$

E. $$\frac{12}{7}$$

Since Andrew competed in 1 event and received 9 points, his overall score was:

9/1 + 1 = 10

Since Jason completed in 3 events and scored 5, 6, and 7 points, he scored a total of 18 points and his overall score was:

18/3 + 3 = 9

Thus, the ratio of Andrew’s score to Jason’s score is 10/9.

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Re: In a field day at a school, each child who competed in n events and sc  [#permalink]

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24 Jul 2017, 06:37

Andrew: n=1, p=9 So: 9/1+1=10
Jason: n=3, p=5+6+7=18 So: 18/3+3=9
Ratio: 10/9
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Re: In a field day at a school, each child who competed in n events and sc  [#permalink]

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24 Jul 2017, 08:00
Andrew's overall score = $$\frac{9}{1} + 1 = 10$$.

Jason's overall score $$= \frac{5+6+7}{3} + 3 = 6+3 = 9$$.

Ratio = $$10:9$$. Ans - D.
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Re: In a field day at a school, each child who competed in n events and sc  [#permalink]

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05 Sep 2017, 05:00
1
Andrew / Jason = X = Ratio of andrews overall over Jason's overall

Andrew = P/n + n = 9/1 + 1 = 1 9/1 = 10/1 = 10 = Andrews overall score
Jason = 18/3 + 3 = 3 18/3 = 27/3 = 9 = Jason's overall score
X = 10/9

Therefore, the correct answer is (D) 10/9

Good warm up question. I wonder what level it is.
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In a field day at a school, each child who competed in n events and sc  [#permalink]

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24 Jan 2018, 05:22
Is there really a need of word " respectively" in the question?
What difference will it make with or without this word?

The reason i ask is this word made me calculate the three rates Separately at first and then re-do my calculations again.
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Re: In a field day at a school, each child who competed in n events and sc  [#permalink]

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18 Mar 2018, 23:18
sandysilva wrote:
Is there really a need of word " respectively" in the question?
What difference will it make with or without this word?

The reason i ask is this word made me calculate the three rates Separately at first and then re-do my calculations again.

Word "respectively" adds emphasize that you need to calculate each set of point i.e, 5, 6 , and 7 for 1 game only. Means 5/1, 6/1, and 7/. And not 5/1 + 1, 6/1 + 1 etc.

Though I did it wrong.

QZ
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Re: In a field day at a school, each child who competed in n events and sc   [#permalink] 18 Mar 2018, 23:18