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In a field day at a school, each child who competed in n events and sc
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Updated on: 23 Jul 2017, 23:57
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In a field day at a school, each child who competed in \(n\) events and scored a total of \(p\) points was given an overall score of \(\frac{p}{n} + n\). Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score? A. \(\frac{10}{23}\) B. \(\frac{7}{10}\) C. \(\frac{4}{5}\) D. \(\frac{10}{9}\) E. \(\frac{12}{7}\)
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Originally posted by carcass on 23 Jul 2017, 09:16.
Last edited by Bunuel on 23 Jul 2017, 23:57, edited 1 time in total.
Edited the question.




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Re: In a field day at a school, each child who competed in n events and sc
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25 May 2020, 13:31
carcass wrote: In a field day at a school, each child who competed in \(n\) events and scored a total of \(p\) points was given an overall score of \(\frac{p}{n} + n\). Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?
A. \(\frac{10}{23}\)
B. \(\frac{7}{10}\)
C. \(\frac{4}{5}\)
D. \(\frac{10}{9}\)
E. \(\frac{12}{7}\) Given: Score = p/n + n Andrew competed in 1 event and scored 9 pointsHere, n = 1 and p = 9 So, Andrew's score = 9/1 + 1 = 9 + 1 = 10Jason competed in 3 events and scored 5, 6, and 7 points, respectively5 + 6 + 7 = 18 So, n = 3 and p = 18 Jason's score = 18/3 + 3 = 6 + 3 = 9 What was the ratio of Andrew's overall score to Jason's overall score? Ratio = 10/ 9 Answer: D Cheers, Brent
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Re: In a field day at a school, each child who competed in n events and sc
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23 Jul 2017, 17:01
carcass wrote: In a field day at a school, each child who competed in n events and scored a total of p points was given an overall score of P/n + n. n Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?
A. \(\frac{10}{23}\)
B.\(\frac{7}{10}\)
C. \(\frac{4}{5}\)
D.\(\frac{10}{9}\)
E. \(\frac{12}{7}\) It should be DFor readers, denominator for P is just 1 n. The fraction then adds into so you can rewrite it as \(n + \frac{p}{n}\) for a clearer understanding. Andrew: \(1 + \frac{9}{1}\) \(= 1 + 9 = 10\) Jason: \(3 + \frac{(5+6+7)}{3}\) \(= 3 + \frac{18}{3} = 9\) Andrew : Jason \(= 10 : 9\)



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Re: In a field day at a school, each child who competed in n events and sc
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26 Jul 2017, 15:38
carcass wrote: In a field day at a school, each child who competed in \(n\) events and scored a total of \(p\) points was given an overall score of \(\frac{p}{n} + n\). Andrew competed in 1 event and scored 9 points. Jason competed in 3 events and scored 5, 6, and 7 points, respectively. What was the ratio of Andrew's overall score to Jason's overall score?
A. \(\frac{10}{23}\)
B. \(\frac{7}{10}\)
C. \(\frac{4}{5}\)
D. \(\frac{10}{9}\)
E. \(\frac{12}{7}\) Since Andrew competed in 1 event and received 9 points, his overall score was: 9/1 + 1 = 10 Since Jason completed in 3 events and scored 5, 6, and 7 points, he scored a total of 18 points and his overall score was: 18/3 + 3 = 9 Thus, the ratio of Andrew’s score to Jason’s score is 10/9. Answer: D
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Re: In a field day at a school, each child who competed in n events and sc
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24 Jul 2017, 06:37
Answer D
Andrew: n=1, p=9 So: 9/1+1=10 Jason: n=3, p=5+6+7=18 So: 18/3+3=9 Ratio: 10/9



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Re: In a field day at a school, each child who competed in n events and sc
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24 Jul 2017, 08:00
Andrew's overall score = \(\frac{9}{1} + 1 = 10\). Jason's overall score \(= \frac{5+6+7}{3} + 3 = 6+3 = 9\). Ratio = \(10:9\). Ans  D.
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Re: In a field day at a school, each child who competed in n events and sc
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05 Sep 2017, 05:00
Andrew / Jason = X = Ratio of andrews overall over Jason's overall
Andrew = P/n + n = 9/1 + 1 = 1 9/1 = 10/1 = 10 = Andrews overall score Jason = 18/3 + 3 = 3 18/3 = 27/3 = 9 = Jason's overall score X = 10/9
Therefore, the correct answer is (D) 10/9
Good warm up question. I wonder what level it is.



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In a field day at a school, each child who competed in n events and sc
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24 Jan 2018, 05:22
Is there really a need of word " respectively" in the question? What difference will it make with or without this word?
The reason i ask is this word made me calculate the three rates Separately at first and then redo my calculations again.



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Re: In a field day at a school, each child who competed in n events and sc
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18 Mar 2018, 23:18
sandysilva wrote: Is there really a need of word " respectively" in the question? What difference will it make with or without this word?
The reason i ask is this word made me calculate the three rates Separately at first and then redo my calculations again.
Word "respectively" adds emphasize that you need to calculate each set of point i.e, 5, 6 , and 7 for 1 game only. Means 5/1, 6/1, and 7/. And not 5/1 + 1, 6/1 + 1 etc. Though I did it wrong. QZ
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Re: In a field day at a school, each child who competed in n events and sc
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18 Mar 2018, 23:18




