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# In a fishing box with red, blue, and green worms, the ratio of red wor

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Re: In a fishing box with red, blue, and green worms, the ratio of red wor [#permalink]
Hi plz help me to understand how did you calculate R:B:G
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Re: In a fishing box with red, blue, and green worms, the ratio of red wor [#permalink]
deepak.brijendra wrote:
Hi plz help me to understand how did you calculate R:B:G

How to derive R:B:G = 20:24:15 given two ratios R:B = 5:6 and R:G = 4:3:

We want the same number for 'R' in both ratios. So, we find the least common multiple of 5 (from R:B) and 4 (from R:G), which is 20. We scale up both ratios to have 'R' as 20.

So, R:B = 5:6 becomes R:B = 20:24 (by multiplying by 4), and R:G = 4:3 becomes R:G = 20:15 (by multiplying by 5).

Thus, we get R:B:G = 20:24:15.

Hope it helps.
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Re: In a fishing box with red, blue, and green worms, the ratio of red wor [#permalink]
r:b = 5:6
r:g = 4:3

g:r:b = 15k:20k:24k

hence, k(max)= 1

No. of blue worms = 24 (option B)
Re: In a fishing box with red, blue, and green worms, the ratio of red wor [#permalink]