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# In a garden with 56 flowers, the ratio of perennials to annuals to bul

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Math Expert
Joined: 02 Sep 2009
Posts: 43335

Kudos [?]: 139569 [0], given: 12794

In a garden with 56 flowers, the ratio of perennials to annuals to bul [#permalink]

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25 Dec 2017, 23:24
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Question Stats:

58% (00:49) correct 42% (00:57) wrong based on 18 sessions

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In a garden with 56 flowers, the ratio of perennials to annuals to bulbs is 9 : x : 3. If there are 12 of bulbs in the garden then what is the value of x?

A. 0
B. 2
C. 4
D. 8
E. 36
[Reveal] Spoiler: OA

_________________

Kudos [?]: 139569 [0], given: 12794

Intern
Joined: 14 Jun 2017
Posts: 15

Kudos [?]: 2 [0], given: 2

GMAT 1: 700 Q48 V38
GMAT 2: 710 Q48 V38
In a garden with 56 flowers, the ratio of perennials to annuals to bul [#permalink]

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26 Dec 2017, 01:15
Bunuel wrote:
In a garden with 56 flowers, the ratio of perennials to annuals to bulbs is 9 : x : 3. If there are 12 of bulbs in the garden then what is the value of x?

A. 0
B. 2
C. 4
D. 8
E. 36

$$9A+ xA+ 3A= 56$$.....(i)
Also $$3A= 12$$, means $$A= 4$$, so (i) becomes $$36+ 4x+ 12= 56$$ implies $$x= (56-12-36)/4= 2$$. Hence B.

Kudos [?]: 2 [0], given: 2

Manager
Joined: 24 Nov 2016
Posts: 151

Kudos [?]: 31 [0], given: 40

Re: In a garden with 56 flowers, the ratio of perennials to annuals to bul [#permalink]

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27 Dec 2017, 03:05
Bunuel wrote:
In a garden with 56 flowers, the ratio of perennials to annuals to bulbs is 9 : x : 3. If there are 12 of bulbs in the garden then what is the value of x?

A. 0
B. 2
C. 4
D. 8
E. 36

$$Total=Ratio*Multiple$$, $$Multiple=m$$, and $$bulbs=12$$; so $$9m+xm+3m=56$$ and $$3m=12$$, $$m=4$$.

Substitute: $$9m+xm+3m=56$$, $$9(4)+x(4)+3(4)=56$$, then $$x=56-12-36=8$$

We want to know the ratio of x: $$Ratio=\frac{Total.x}{Multiple}=\frac{8}{4}=2$$

Kudos [?]: 31 [0], given: 40

Re: In a garden with 56 flowers, the ratio of perennials to annuals to bul   [#permalink] 27 Dec 2017, 03:05
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