GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 08 Dec 2019, 16:40

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# In a graduating class, the difference between the highest and lowest

Author Message
TAGS:

### Hide Tags

Current Student
Joined: 22 Jul 2014
Posts: 120
Concentration: General Management, Finance
GMAT 1: 670 Q48 V34
WE: Engineering (Energy and Utilities)
In a graduating class, the difference between the highest and lowest  [#permalink]

### Show Tags

08 Sep 2014, 02:08
1
32
00:00

Difficulty:

75% (hard)

Question Stats:

53% (02:44) correct 47% (02:37) wrong based on 101 sessions

### HideShow timer Statistics

In a graduating class, the difference between the highest and lowest salaries is \$100,000. The median salary is \$50,000 higher than the lowest salary and the average salary is \$20,000 higher than the median. What is the minimum number of students in the class?

A)10
B)12
C)15
D)20
E)25

Source: 4gmat

Our instructor mentioned that this is a 750+ question.
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9855
Location: Pune, India
In a graduating class, the difference between the highest and lowest  [#permalink]

### Show Tags

06 Oct 2014, 22:51
3
3
Quote:
In a graduating class, the difference between the highest and lowest salaries is \$100,000. The median salary is \$50,000 higher than the lowest salary and the average salary is \$20,000 higher than the median. What is the minimum number of students in the class?

A)10
B)12
C)15
D)20
E)25

Responding to a pm:

You need to understand the concepts of mean, median and range very well to do this question. Since you asked me to resolve it, I am assuming that you are comfortable with these stats concepts I have discussed on my blog. Here is the logical solution:

"the difference between the highest and lowest salaries is \$100,000."
So there are at least 2 people - say one with salary 0 and the other with 100k. No salary will be outside this range.

Median = 50k more than lowest. So median is right in the center of lowest and highest since lowest and highest differ by 100k. In our example, median = 50k. Since there are more than 2 people, there would probably be a person at 50k.

Mean = 20k more than median so in our example, mean salary = 70k

On the number line,

0........50k (median)........100k

Mean = 70k

So there must be people more toward 100k to bring the mean up to 70k. Since we want to add minimum people, we will add people at 100k to quickly make up the right side deficit. 0 and 50k are (70k + 20k) = 90k away from 70k. 100k is 30k away from 70k. To bring the mean to 70k, we will add two people at 100k each to get:

0....50k.....100k, 100k, 100k

But when we add more people to the right of 70k, the median will shift to the right. We need to keep the median at 50k. So every time we add people to the right of 70k, we need to add people at 50k too to balance the median. 50k is 20k less than 70k while 100k is 30k more than 70k. To keep the mean same, we need to add 2 people at 100k for every 3 people we add at 50k. So if we add 3 people at 50k and 2 people at 100k, we get:

0, ... 50k, 50k, 50k, 50k, ... 100k, 100k, 100k, 100k, 100k
the median is not at 50k yet.

Add another 3 people at 50k and another 2 at 100k to get

0, 50k, 50k, 50k, 50k, 50k, 50k, 50k, 100k, 100k, 100k, 100k, 100k, 100k, 100k

Now the median is 50k and mean is 70k.

Total number of people is 15.

_________________
Karishma
Veritas Prep GMAT Instructor

##### General Discussion
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9855
Location: Pune, India
In a graduating class, the difference between the highest and lowest  [#permalink]

### Show Tags

06 Oct 2014, 23:07
As for your question as to how close this question is to actual GMAT questions, quite close I would say. You need a solid understanding of very basic concepts and need to just apply those. The question is easily do-able within 2 mins. I can't find any reason to call this is a 'non-GMAT like' question.
_________________
Karishma
Veritas Prep GMAT Instructor

Intern
Joined: 12 Sep 2012
Posts: 25
GMAT 1: 550 Q49 V17
Re: In a graduating class, the difference between the highest and lowest  [#permalink]

### Show Tags

14 Oct 2014, 13:14
1
VeritasPrepKarishma wrote:
Quote:
In a graduating class, the difference between the highest and lowest salaries is \$100,000. The median salary is \$50,000 higher than the lowest salary and the average salary is \$20,000 higher than the median. What is the minimum number of students in the class?

A)10
B)12
C)15
D)20
E)25

Responding to a pm:

You need to understand the concepts of mean, median and range very well to do this question. Since you asked me to resolve it, I am assuming that you are comfortable with these stats concepts I have discussed on my blog. Here is the logical solution:

"the difference between the highest and lowest salaries is \$100,000."
So there are at least 2 people - say one with salary 0 and the other with 100k. No salary will be outside this range.

Median = 50k more than lowest. So median is right in the center of lowest and highest since lowest and highest differ by 100k. In our example, median = 50k. Since there are more than 2 people, there would probably be a person at 50k.

Mean = 20k more than median so in our example, mean salary = 70k

On the number line,

0........50k (median)........100k

Mean = 70k

So there must be people more toward 100k to bring the mean up to 70k. Since we want to add minimum people, we will add people at 100k to quickly make up the right side deficit. 0 and 50k are (70k + 20k) = 90k away from 70k. 100k is 30k away from 70k. To bring the mean to 70k, we will add two people at 100k each to get:

0....50k.....100k, 100k, 100k

But when we add more people to the right of 70k, the median will shift to the right. We need to keep the median at 50k. So every time we add people to the right of 70k, we need to add people at 50k too to balance the median. 50k is 20k less than 70k while 100k is 30k more than 70k. To keep the mean same, we need to add 2 people at 100k for every 3 people we add at 50k. So if we add 3 people at 50k and 2 people at 100k, we get:

0, ... 50k, 50k, 50k, 50k, ... 100k, 100k, 100k, 100k, 100k
the median is not at 50k yet.

Add another 3 people at 50k and another 2 at 100k to get

0, 50k, 50k, 50k, 50k, 50k, 50k, 50k, 100k, 100k, 100k, 100k, 100k, 100k, 100k

Now the median is 50k and mean is 70k.

Total number of people is 15.

Hello Karishma,

That is a great solution. Unfortunately, I am unable to understand the concept behind this. Kindly give the link of your blog as reference. That would be beneficial for me.
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9855
Location: Pune, India
Re: In a graduating class, the difference between the highest and lowest  [#permalink]

### Show Tags

14 Oct 2014, 20:35
deya wrote:

Hello Karishma,

That is a great solution. Unfortunately, I am unable to understand the concept behind this. Kindly give the link of your blog as reference. That would be beneficial for me.

Here are some posts discussing mean and median:

http://www.veritasprep.com/blog/2012/04 ... etic-mean/
http://www.veritasprep.com/blog/2012/04 ... questions/
http://www.veritasprep.com/blog/2012/05 ... eviations/
http://www.veritasprep.com/blog/2012/05 ... tic-means/
http://www.veritasprep.com/blog/2012/05 ... on-median/
_________________
Karishma
Veritas Prep GMAT Instructor

Manager
Joined: 21 Jun 2014
Posts: 98
Location: United States
Concentration: General Management, Strategy
GMAT 1: 630 Q45 V31
GPA: 3.4
WE: Engineering (Computer Software)
Re: In a graduating class, the difference between the highest and lowest  [#permalink]

### Show Tags

17 Jun 2015, 01:57
1
We can also use POE .Median is the middle number between lowest and highest so total number of students will be odd .This eliminates choices A,B,D
Between C and E .Average is 70000 which is more towards higher pay and is also more then median .So number of students will be more on the rhs then lhs .Add the students accordingly on both sides to get the final answer.

Regards,
Manish Khare
_________________
Regards,
Manish Khare
"Every thing is fine at the end. If it is not fine ,then it is not the end "
CrackVerbal Quant Expert
Joined: 12 Apr 2019
Posts: 313
Re: In a graduating class, the difference between the highest and lowest  [#permalink]

### Show Tags

04 Jun 2019, 08:37
1
This question is definitely a good question on statistics. Essentially, it tests your in depth knowledge of averages in general and weighted average in particular.

A smart approach in this question, as highlighted by some experts already on this thread, is to take values that will make problem solving simpler.

The mean salary is higher than the median salary, which points out to the fact that, the number of values greater than the mean and closer to the highest salary, is higher.

Let’s take the lowest salary be \$0. If we take 10 students, the tenth value should be \$100000. The median, which is the average of the fifth and sixth value should be \$50000. So, the list can look like this:
0, 50, 50, 50, 50, 50, 100,100,100,100.

The idea is to take every value to the left of the median as \$50000 to ensure the median is \$50000 and to take every value to the right of the median as \$100000. However, these values do not total up to \$700000 [ \$70000 (mean) * 10 (number of employees)]. Notice that the number of 50s are higher than the 100s and hence the mean is not 70.

A similar thing happens when we take 12 values:
0, 50, 50, 50 , 50, 50, 50, 100,100,100, 100, 100. The mean for this set comes out to be 66.66.

When we take 15 values, the median is the 8th value. So, we can have a 0, seven 50s and seven 100s. This gives us a mean of 70 and also ensures that the median is 50 along with the range being 100.

The correct answer option is C.

Hope this helps!
_________________
Target Test Prep Representative
Status: Founder & CEO
Affiliations: Target Test Prep
Joined: 14 Oct 2015
Posts: 8622
Location: United States (CA)
Re: In a graduating class, the difference between the highest and lowest  [#permalink]

### Show Tags

09 Jun 2019, 18:55
1
1
alphonsa wrote:
In a graduating class, the difference between the highest and lowest salaries is \$100,000. The median salary is \$50,000 higher than the lowest salary and the average salary is \$20,000 higher than the median. What is the minimum number of students in the class?

A)10
B)12
C)15
D)20
E)25

Source: 4gmat

Our instructor mentioned that this is a 750+ question.

Let the lowest salary be x. Then, the median salary is x + 50,000; the average salary is x + 70,000 and the greatest salary is x + 100,000.

We notice that the average salary is between the median and the greatest salary. When this is the case, the number of students in the class can be minimized by choosing the salaries as one salary which is equal to x, some number of salaries which are equal to x + 50,000 and some number of salaries which are equal to x + 100,000. The reason for such a choice of salaries is because every salary we add that is less than x + 50,000 will bring the average salary down, and to counter that, since we can’t add any salaries greater than x + 100,000, we have to increase the number of salaries that equal x + 100,000, therefore increasing the number of students.

So, let n be the number of salaries that equal x + 50,000 and m be the number of salaries that equal x + 100,000. Notice that m cannot be greater than n because otherwise, the median will equal x + 100,000. Since the average salary is x + 70,000 and the number of students is n + m + 1, the sum of all the salaries is (n + m + 1)(x + 70,000). On the other hand, the sum of all the salaries is also equal to x + n(x + 50,000) + m(x + 100,000). Let’s equate these two quantities:

x + n(x + 50,000) + m(x + 100,000) = (n + m + 1)(x + 70,000)

x + nx + 50,000n + mx + 100,000m = nx + mx + x + 70,000n + 70,000m + 70,000

30,000m = 20,000n + 70,000

3m = 2n + 7

Since m ≤ n, 3m ≤ 3n. Let’s substitute 3m = 2n + 7:

2n + 7 ≤ 3n

7 ≤ n

We see that the smallest value of n is 7. If n = 7, then 3m = 14 + 7 = 21; therefore m = 7 as well. Thus, the smallest number of students is n + m + 1 = 7 + 7 + 1 = 15.

_________________

# Scott Woodbury-Stewart

Founder and CEO

Scott@TargetTestPrep.com
122 Reviews

5-star rated online GMAT quant
self study course

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

Intern
Joined: 03 Jun 2019
Posts: 22
Re: In a graduating class, the difference between the highest and lowest  [#permalink]

### Show Tags

19 Jun 2019, 07:00
Quote:
In a graduating class, the difference between the highest and lowest salaries is \$100,000. The median salary is \$50,000 higher than the lowest salary and the average salary is \$20,000 higher than the median. What is the minimum number of students in the class?

A)10
B)12
C)15
D)20
E)25

Responding to a pm:

You need to understand the concepts of mean, median and range very well to do this question. Since you asked me to resolve it, I am assuming that you are comfortable with these stats concepts I have discussed on my blog. Here is the logical solution:

"the difference between the highest and lowest salaries is \$100,000."
So there are at least 2 people - say one with salary 0 and the other with 100k. No salary will be outside this range.

Median = 50k more than lowest. So median is right in the center of lowest and highest since lowest and highest differ by 100k. In our example, median = 50k. Since there are more than 2 people, there would probably be a person at 50k.

Mean = 20k more than median so in our example, mean salary = 70k

On the number line,

0........50k (median)........100k

Mean = 70k

So there must be people more toward 100k to bring the mean up to 70k. Since we want to add minimum people, we will add people at 100k to quickly make up the right side deficit. 0 and 50k are (70k + 20k) = 90k away from 70k. 100k is 30k away from 70k. To bring the mean to 70k, we will add two people at 100k each to get:

0....50k.....100k, 100k, 100k

But when we add more people to the right of 70k, the median will shift to the right. We need to keep the median at 50k. So every time we add people to the right of 70k, we need to add people at 50k too to balance the median. 50k is 20k less than 70k while 100k is 30k more than 70k. To keep the mean same, we need to add 2 people at 100k for every 3 people we add at 50k. So if we add 3 people at 50k and 2 people at 100k, we get:

0, ... 50k, 50k, 50k, 50k, ... 100k, 100k, 100k, 100k, 100k
the median is not at 50k yet.

Add another 3 people at 50k and another 2 at 100k to get

0, 50k, 50k, 50k, 50k, 50k, 50k, 50k, 100k, 100k, 100k, 100k, 100k, 100k, 100k

Now the median is 50k and mean is 70k.

Total number of people is 15.

I did not understand how 0k and 50k are 90k away from 70k, could you please help in clearing this doubt?
Re: In a graduating class, the difference between the highest and lowest   [#permalink] 19 Jun 2019, 07:00
Display posts from previous: Sort by