Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

In a network of car dealerships, a group of d sales director [#permalink]

Show Tags

22 Apr 2013, 21:57

3

This post received KUDOS

5

This post was BOOKMARKED

00:00

A

B

C

D

E

Difficulty:

95% (hard)

Question Stats:

46% (01:46) correct
54% (01:41) wrong based on 213 sessions

HideShow timer Statistics

In a network of car dealerships, a group of d sales directors each has a team of a sales associates. In a given month, if the directors each sold 10 cars and each sales associate sold 20 cars, and all cars were sold by either a sales director or a sales associate, how many people total sold cars?

Re: n a network of car dealerships, a group of d sales [#permalink]

Show Tags

22 Apr 2013, 22:25

In a network of car dealerships, a group of d sales directors each has a team of a sales associates. In a given month, if the directors each sold 10 cars and each sales associate sold 20 cars, and all cars were sold by either a sales director or a sales associate, how many people total sold cars?

(1) The total number of cars sold was 270 \(a=13,\) \(d=1,\) \(20*13+10*1=270\) or \(a=12,\) \(d=3,\) \(20*12+10*3=270\) Not sufficient

(2) a > d > 2 Clearly not sufficient

1+2 \(a=10, d=7, 10*20+7*10=270\) or \(a=11,d=5,11*20+5*10=270\). Not sufficient E _________________

It is beyond a doubt that all our knowledge that begins with experience.

A network of car dealerships, employs d sales directors, who [#permalink]

Show Tags

16 Sep 2013, 22:47

A network of car dealerships, employs d sales directors, who each supervise a sales associates. If each director sells 10 cars and each sales associate sells 20 cars, and no other cars were sold by the dealership, how many people total sold cars?

(1) The total number of cars sold was 270

(2) a>d>2

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked Both statements (1) and (2) TOGETHER are sufficient to answer the question asked; but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient to answer the question asked Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed

_________________

Like my post Send me a Kudos It is a Good manner. My Debrief: http://gmatclub.com/forum/how-to-score-750-and-750-i-moved-from-710-to-189016.html

Re: n a network of car dealerships, a group of d sales [#permalink]

Show Tags

16 Sep 2013, 23:32

Zarrolou wrote:

In a network of car dealerships, a group of d sales directors each has a team of a sales associates. In a given month, if the directors each sold 10 cars and each sales associate sold 20 cars, and all cars were sold by either a sales director or a sales associate, how many people total sold cars?

(1) The total number of cars sold was 270 \(a=13,\) \(d=1,\) \(20*13+10*1=270\) or \(a=12,\) \(d=3,\) \(20*12+10*3=270\) Not sufficient

(2) a > d > 2 Clearly not sufficient

1+2 \(a=10, d=7, 10*20+7*10=270\) or \(a=11,d=5,11*20+5*10=270\). Not sufficient E

dx10 + ax20 = 270 here a=d

d=9 2d total number pf person who sold the car = 2 X9 = 18 A is the correct answer
_________________

Like my post Send me a Kudos It is a Good manner. My Debrief: http://gmatclub.com/forum/how-to-score-750-and-750-i-moved-from-710-to-189016.html

Re: n a network of car dealerships, a group of d sales [#permalink]

Show Tags

16 Sep 2013, 23:45

2

This post received KUDOS

Zarrolou wrote:

In a network of car dealerships, a group of d sales directors each has a team of a sales associates. In a given month, if the directors each sold 10 cars and each sales associate sold 20 cars, and all cars were sold by either a sales director or a sales associate, how many people total sold cars?

(1) The total number of cars sold was 270 \(a=13,\) \(d=1,\) \(20*13+10*1=270\) or \(a=12,\) \(d=3,\) \(20*12+10*3=270\) Not sufficient

(2) a > d > 2 Clearly not sufficient

1+2 \(a=10, d=7, 10*20+7*10=270\) or \(a=11,d=5,11*20+5*10=270\). Not sufficient E

Hi Zarrolou,

Isn't the answer suppose to be C

Below is my explanation

St 1 and 2 are clearly not sufficient so we rule out option A, D, and B.

Combining we get

10d+ 20 a= 270 and that a>d>2

Possible cases are

let us say d=1, a =13 so Total no . of people =14 d=3, a=12, Total= 15 d=9,a=9, Total 18 d=5, a=11, Total 16 and so one We see that as D increases A will decrease and hence the given condition that each sales director handle "a" sales associates will not hold.

From the above condition there is only 1 case possible which d=3, a=12 and T=15. Note that each Sales director handles 4 Sales associates.

Where am I wrong on this one???
_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

A network of car dealerships, employs d sales directors, who each supervise a sales associates. If each director sells 10 cars and each sales associate sells 20 cars, and no other cars were sold by the dealership, how many people total sold cars?

(1) The total number of cars sold was 270

(2) a>d>2

Statement (1) ALONE is sufficient, but statement (2) alone is not sufficient to answer the question asked Statement (2) ALONE is sufficient, but statement (1) alone is not sufficient to answer the question asked Both statements (1) and (2) TOGETHER are sufficient to answer the question asked; but NEITHER statement ALONE is sufficient EACH statement ALONE is sufficient to answer the question asked Statements (1) and (2) TOGETHER are NOT sufficient to answer the question asked, and additional data specific to the problem are needed

Re: In a network of car dealerships, a group of d sales [#permalink]

Show Tags

17 Sep 2013, 19:41

1

This post received KUDOS

(1) --> d*10+ad*20 =270; d(10+2a)=270 Many values could solve this equation, Not Sufficient

(2) --> a>d>2 Clearly insufficient

(1)+(2), The first value of d and a is 3 and 4 (a and d must be integer), then d(10+2a)=270 --> 3(10+2*4)=270 --> so d must be 4 and a must be 3. If we increase d to 4 and a to 5, then the value is to big to get 270. Sufficient, answer C

In a network of car dealerships, a group of d sales directors each has a team of a sales associates. In a given month, if the directors each sold 10 cars and each sales associate sold 20 cars, and all cars were sold by either a sales director or a sales associate, how many people total sold cars?

The total # of directors = d; The total # of associates = ad;

Total # of cars sold = 10d + 20ad.

(1) The total number of cars sold was 270 --> 10d + 20ad = 270 --> d(1 + 2a) = 27. Four cases are possible: d = 1 and a = 13, d = 3 and a = 4, d = 9 and a = 1, d = 27 and a = 0.

Not sufficient.

(2) a > d > 2. Clearly insufficient.

(1)+(2) Since from (2) a > d > 2, then only one case remains from (1): d = 3 and a = 4. Sufficient.

Re: In a network of car dealerships, a group of d sales director [#permalink]

Show Tags

11 Mar 2015, 06:14

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: In a network of car dealerships, a group of d sales director [#permalink]

Show Tags

30 Apr 2016, 08:17

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Re: In a network of car dealerships, a group of d sales director [#permalink]

Show Tags

05 May 2016, 05:32

Bunuel wrote:

In a network of car dealerships, a group of d sales directors each has a team of a sales associates. In a given month, if the directors each sold 10 cars and each sales associate sold 20 cars, and all cars were sold by either a sales director or a sales associate, how many people total sold cars?

The total # of directors = d; The total # of associates = ad;

Total # of cars sold = 10d + 20ad.

(1) The total number of cars sold was 270 --> 10d + 20ad = 270 --> d(1 + 2a) = 27. Four cases are possible: d = 1 and a = 13, d = 3 and a = 4, d = 9 and a = 1, d = 27 and a = 0.

Not sufficient.

(2) a > d > 2. Clearly insufficient.

(1)+(2) Since from (2) a > d > 2, then only one case remains from (1): d = 3 and a = 4. Sufficient.

Answer: C.

Hope it's clear.

Hi Bunuel,

For AC A, how can we figure out the possible possible valid combinations for 'a' and 'd' quickly? it would take significant time starting from 1 and tracking back from 27. Thank you.

In a network of car dealerships, a group of d sales directors each has a team of a sales associates. In a given month, if the directors each sold 10 cars and each sales associate sold 20 cars, and all cars were sold by either a sales director or a sales associate, how many people total sold cars?

The total # of directors = d; The total # of associates = ad;

Total # of cars sold = 10d + 20ad.

(1) The total number of cars sold was 270 --> 10d + 20ad = 270 --> d(1 + 2a) = 27. Four cases are possible: d = 1 and a = 13, d = 3 and a = 4, d = 9 and a = 1, d = 27 and a = 0.

Not sufficient.

(2) a > d > 2. Clearly insufficient.

(1)+(2) Since from (2) a > d > 2, then only one case remains from (1): d = 3 and a = 4. Sufficient.

Answer: C.

Hope it's clear.

Hi Bunuel,

For AC A, how can we figure out the possible possible valid combinations for 'a' and 'd' quickly? it would take significant time starting from 1 and tracking back from 27. Thank you.

27 can be broken into the product of two positive integers only in 4 ways: 1*27 3*9 9*3 27*1.

From here it should not take much time to get the values of a and d.
_________________

Re: In a network of car dealerships, a group of d sales director [#permalink]

Show Tags

06 Sep 2016, 03:27

skamal7 wrote:

In a network of car dealerships, a group of d sales directors each has a team of a sales associates. In a given month, if the directors each sold 10 cars and each sales associate sold 20 cars, and all cars were sold by either a sales director or a sales associate, how many people total sold cars?

(1) The total number of cars sold was 270

(2) a > d > 2

# of people who sold cars = d + d*a Each director has a associates.

We should acknowledge (2) first because it is a simple statement giving us a constraint rather than a concrete data about question and it is easy to prove that insufficient.

(2) a > d > 2 Insufficient.

(1) The total number of cars sold was 270

i.e. 10d + 20d*a = 270 => d + 2d*a = 27

1 Equation, 2 Variables. Don't be too hasty to jump on to (C) for this situation. There have been a lot of DS questions where such situations have yielded a unique answer because of the presence of "invisible" constraint - a & d are Positive Integers .

d*(1 + 2a) = 27

Notice that (1+2a) and d will always be Odd because their multiple is Odd.

Therefore,

If d = 1; 1+2a = 27 => Odd => a = 13 d = 3; 1+2a = 9 => Odd => a = 4

2 Solutions Possible. Statement (1) - Not Sufficient.

(1) + (2)..

a > d > 2 & d(1+2a) = 27

We do not have to check for every Odd value of d. We can find the factors of 27 and then move forward.

27 = \(3^3\)

Therefore, Factors of 27 - 1, 3, 9, 27.

Therefore, If d != 1 (Constraint in Statement (2)) If d = 3; a = 4 - Valid Solution. For d = 9; a != 1 (Constraint in Statement (2)) d = 27; a != 0 (Constraint in Statement (2))

Hence, C is the Answer.
_________________

I'd appreciate learning about the grammatical errors in my posts

Please hit Kudos If my Solution helps

My Debrief for 750 - https://gmatclub.com/forum/from-720-to-750-one-of-the-most-difficult-pleatues-to-overcome-246420.html

We’ve given one of our favorite features a boost! You can now manage your profile photo, or avatar , right on WordPress.com. This avatar, powered by a service...

Sometimes it’s the extra touches that make all the difference; on your website, that’s the photos and video that give your content life. You asked for streamlined access...

A lot has been written recently about the big five technology giants (Microsoft, Google, Amazon, Apple, and Facebook) that dominate the technology sector. There are fears about the...

Post today is short and sweet for my MBA batchmates! We survived Foundations term, and tomorrow's the start of our Term 1! I'm sharing my pre-MBA notes...