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# In a photography exhibition, some photographs were taken by

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Senior Manager
Joined: 21 Oct 2013
Posts: 411
In a photography exhibition, some photographs were taken by  [#permalink]

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29 Jul 2014, 06:51
5
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Difficulty:

35% (medium)

Question Stats:

70% (01:39) correct 30% (02:04) wrong based on 205 sessions

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In a photography exhibition, some photographs were taken by Octavia the photographer, and some photographs were framed by Jack the framer. Jack had framed 24 photographs taken by Octavia, and 12 photographs taken by other photographers. If 36 of the photographs in the exhibition were taken by Octavia, how many photographs were either framed by Jack or taken by Octavia?

A. 36
B. 48
C. 72
D. 96
E. 108
Math Expert
Joined: 02 Sep 2009
Posts: 58335
Re: In a photography exhibition, some photographs were taken by  [#permalink]

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29 Jul 2014, 08:22
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goodyear2013 wrote:
In a photography exhibition, some photographs were taken by Octavia the photographer, and some photographs were framed by Jack the framer. Jack had framed 24 photographs taken by Octavia, and 12 photographs taken by other photographers. If 36 of the photographs in the exhibition were taken by Octavia, how many photographs were either framed by Jack or taken by Octavia?

A. 36
B. 48
C. 72
D. 96
E. 108

Check the matrix below:
Attachment:

Untitled.png [ 4.56 KiB | Viewed 3275 times ]
Numbers in black are given and in red calculated based on them.

The number of photographs either framed by Jack or taken by Octavia = {Jack} + {Octavia} - {overlap} = 36 + 36 - 24 = 48 ({overlap} is green box).

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##### General Discussion
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Joined: 20 Mar 2012
Posts: 2
Schools: Yale
Re: In a photography exhibition, some photographs were taken by  [#permalink]

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04 Oct 2015, 19:10
I have a question. Why can't we just add 12 + 12 i.e photos clicked only by Octavia and not framed by Jack + Photos framed only by Jack and not clicked by Olivia?
Veritas Prep GMAT Instructor
Joined: 16 Oct 2010
Posts: 9695
Location: Pune, India
Re: In a photography exhibition, some photographs were taken by  [#permalink]

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05 Oct 2015, 00:42
1
mankakhanna wrote:
I have a question. Why can't we just add 12 + 12 i.e photos clicked only by Octavia and not framed by Jack + Photos framed only by Jack and not clicked by Olivia?

Either A or B includes "Both" too.
So you also need to include the 24 that were taken by Octavia AND framed by Jack.
You get 12 + 12 + 24 = 48

Either Or in logic/Math is a bit different from the way we understand it in day-to-day language.
In Math, "Either A or B" means that it is at least one of A and B. It could be both too.
Either the car is red in colour or it is a Ferrari means it could be a Red Ferrari too but it is definitely at least one of them.
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Re: In a photography exhibition, some photographs were taken by  [#permalink]

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01 Jul 2019, 17:19
goodyear2013 wrote:
In a photography exhibition, some photographs were taken by Octavia the photographer, and some photographs were framed by Jack the framer. Jack had framed 24 photographs taken by Octavia, and 12 photographs taken by other photographers. If 36 of the photographs in the exhibition were taken by Octavia, how many photographs were either framed by Jack or taken by Octavia?

A. 36
B. 48
C. 72
D. 96
E. 108

We can use the formula:

N(Octavia or Jack) = N(Octavia) + N(Jack) - N(Both)

Therefore, we have:

N(Octavia or Jack) = 36 + 36 - 24 = 72 - 24 = 48

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Re: In a photography exhibition, some photographs were taken by   [#permalink] 01 Jul 2019, 17:19
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