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# In a picnic 60% people ate two hotdogs, 30% people ate one hamburger,

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Intern
Joined: 17 Jan 2012
Posts: 41
GMAT 1: 610 Q43 V31
In a picnic 60% people ate two hotdogs, 30% people ate one hamburger,  [#permalink]

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30 Jan 2012, 12:58
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0% (00:00) correct 100% (00:02) wrong based on 9 sessions

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In a picnic 60% people ate two hotdogs, 30% people ate one hamburger, and 10% people ate one hotdog. The total number of hotdog and hamburgers consumed is 80. How many hamburgers and hotdogs are consumed?

Total people 50, total hotdogs 65, total hamburgers 15
Senior Manager
Joined: 31 Oct 2011
Posts: 476
Schools: Johnson '16 (M)
GMAT 1: 690 Q45 V40
WE: Asset Management (Mutual Funds and Brokerage)
Re: In a picnic 60% people ate two hotdogs, 30% people ate one hamburger,  [#permalink]

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30 Jan 2012, 13:04
docabuzar wrote:
In a picnic 60% people ate two hotdogs, 30% people ate one hamburger, and 10% people ate one hotdog. The total number of hotdog and hamburgers consumed is 80. How many hamburgers and hotdogs are consumed?

Answer>Total people 50, total hotdogs 65, total hamburgers 15

Can somebody explain?

let the total # of earthlings be 'x'.
total # of hamburgers= .3x
total # of hotdogs = (.6x)*2 + .1x ( .6x*2 b'coz they ate 2 each.)
now, total food = .3x +1.2x+.1x
this is given to be 80
equating we get x= 50
hence # of hamburgers = .3x = 15
# of hotdogs= 1.3x = 65
80 Total - 65 hotdogs = 15 hamburgers

65 hotdogs, 15 hamburgers

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Intern
Joined: 17 Jan 2012
Posts: 41
GMAT 1: 610 Q43 V31
Re: In a picnic 60% people ate two hotdogs, 30% people ate one hamburger,  [#permalink]

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30 Jan 2012, 13:06
I cracked it like this:

60% people ate 2 hotdogs = 60% x 2 = 1.2
60% people ate 1 burger = 30% x 2 = 0.3
10% people ate 1 hotdogs = 10% x 1 = 0.1

TOtal = 1.2+0.3+0.1 = 1.6

Hotdaogs = (1.2+0.1)/1.6 x 80 = 65
Burgers = 0.3/1.6 x 80 = 15

Pls confirm is this right
Senior Manager
Joined: 31 Oct 2011
Posts: 476
Schools: Johnson '16 (M)
GMAT 1: 690 Q45 V40
WE: Asset Management (Mutual Funds and Brokerage)
Re: In a picnic 60% people ate two hotdogs, 30% people ate one hamburger,  [#permalink]

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30 Jan 2012, 13:14
docabuzar wrote:
I cracked it like this:

60% people ate 2 hotdogs = 60% x 2 = 1.2
[strike]60% people ate 1 burger = 30% x 2 = 0.3[/strike] 30% people ate 1 burger = 30% x 1 = 0.3
10% people ate 1 hotdogs = 10% x 1 = 0.1

TOtal = 1.2+0.3+0.1 = 1.6

Hotdaogs = (1.2+0.1)/1.6 x 80 = 65
Burgers = 0.3/1.6 x 80 = 15

Pls confirm is this right

I corrected a bit of it above, but i supposed that works as well.
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Posts: 59709
Re: In a picnic 60% people ate two hotdogs, 30% people ate one hamburger,  [#permalink]

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30 Jan 2012, 14:15
docabuzar wrote:
In a picnic 60% people ate two hotdogs, 30% people ate one hamburger, and 10% people ate one hotdog. The total number of hotdog and hamburgers consumed is 80. How many hamburgers and hotdogs are consumed?

Answer>Total people 50, total hotdogs 65, total hamburgers 15

Can somebody explain?

Let the total # of people be T, then: 0.6T*2+0.3T+0.1T=80 --> T=50 --> hot dogs=0.3*50=15 --> hamburgers=80-15=65.
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Re: In a picnic 60% people ate two hotdogs, 30% people ate one hamburger,   [#permalink] 30 Jan 2012, 14:15
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