It is currently 15 Dec 2017, 04:25

Decision(s) Day!:

CHAT Rooms | Wharton R1 | Stanford R1 | Tuck R1 | Ross R1 | Haas R1 | UCLA R1


Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

In a sequence, after the first two terms, each term is the

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Senior Manager
Senior Manager
avatar
Joined: 08 Aug 2005
Posts: 251

Kudos [?]: 67 [0], given: 0

In a sequence, after the first two terms, each term is the [#permalink]

Show Tags

New post 21 Apr 2006, 03:17
1
This post was
BOOKMARKED
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

In a sequence, after the first two terms, each term is the sum of all the previous terms. If an=P, a(n+2)=?

Kudos [?]: 67 [0], given: 0

Director
Director
avatar
Joined: 24 Oct 2005
Posts: 658

Kudos [?]: 16 [0], given: 0

Location: London
 [#permalink]

Show Tags

New post 21 Apr 2006, 04:33
a(1) = a
a(2) = b
a(3) = a+b
a(4) = 2a + 2b
a(5) = 4a + 4b

Let us take a(n) = a(3) = a + b = P
Therefore, a(n+ 2) = a(5) = 4(a+b) = 4P

Ans = 4P

Kudos [?]: 16 [0], given: 0

VP
VP
avatar
Joined: 06 Jun 2004
Posts: 1050

Kudos [?]: 188 [0], given: 0

Location: CA
 [#permalink]

Show Tags

New post 27 Apr 2006, 20:12
Agree with remgeo's approach
_________________

Don't be afraid to take a flying leap of faith.. If you risk nothing, than you gain nothing...

Kudos [?]: 188 [0], given: 0

Manager
Manager
avatar
Joined: 14 Mar 2006
Posts: 208

Kudos [?]: 10 [0], given: 0

 [#permalink]

Show Tags

New post 28 Apr 2006, 06:05
remgeo wrote:
a(1) = a
a(2) = b
a(3) = a+b
a(4) = 2a + 2b
a(5) = 4a + 4b

Let us take a(n) = a(3) = a + b = P
Therefore, a(n+ 2) = a(5) = 4(a+b) = 4P

Ans = 4P


Took me a while but I think i understand your explanation.

since we let n=3, a(3)= a+b
therefore, P= a+b
Now lets look at a(n+2), since n=3 we have a(3+2)=a(5), where a(5)= 4a+4b. or 4(a+b), since P=a+b, we have 4P :)

I had to break it down for my understanding, plz let me know if I am wrong. greak work!

Kudos [?]: 10 [0], given: 0

Director
Director
User avatar
Joined: 04 Jan 2006
Posts: 922

Kudos [?]: 38 [0], given: 0

 [#permalink]

Show Tags

New post 29 Apr 2006, 08:40
Does it work for n=1?

Kudos [?]: 38 [0], given: 0

Manager
Manager
avatar
Joined: 09 Apr 2006
Posts: 173

Kudos [?]: 3 [0], given: 0

Location: Somewhere in Wisconsin!
 [#permalink]

Show Tags

New post 29 Apr 2006, 09:15
Probably the question is interested in all n after the first two numbers.
_________________

Thanks,
Zooroopa

Kudos [?]: 3 [0], given: 0

  [#permalink] 29 Apr 2006, 09:15
Display posts from previous: Sort by

In a sequence, after the first two terms, each term is the

  post reply Question banks Downloads My Bookmarks Reviews Important topics  

Moderator: chetan2u



GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.